Let the total score of Day 1, Day 2, Day 3, Day 4 and Day 5 of all the participants be a, b, c, d and e respectively. As per the Table 1,
a + b = 15 × 2 = 30, b + c = 15.5 × 2 = 31,
c + d = 16 × 2 = 32 and d + e = 17 × 2 = 34
Point 2, total score on Day 3 = total score on Day 4
⇒ c = d = 16 (each)
⇒ e = 34 – 16 = 18, b = 31 – 16 = 15 and a = 30 – 15 = 15
Point 1, Chatur score on any day = 3, 6 or 9
The only possibility of his Day 2 score being unique highest = 9 His only minimum score on Day 1 = 3
⇒ Chatur’s score on Day 3, Day 4 and Day 5 = 6 (each) Also, Akhil’s Day 4 score = Chatur’s Day 1 score = 3
⇒ Bimal’s Day 4 score = 16 – (3 + 6) = 7
Now being same rank, Akhil’s Day 3 score = Bimal’s Day 3 score = 5 (each) Point 3, Bimal’s Day 1 score = Bimal’s Day 3 score = 5
⇒ Akhil’s Day 1 score = 15 – (5 + 3) = 7
Now for Day 2, let the score of Akhil = p and Bimal = q Solving, p + q + 9 = 15 ⇒ p + q = 6
Since, the rank of Akhil is 2 and Bimal is 3 Possible values of p = 4 or 5 and q = 2 or 1
Now for Day 5, let the score of Akhil = x and Bimal = y
Solving, x + y + 6 = 18 ⇒ x + y = 12
Since, the rank of Akhil is 3 and Bimal is 1 Possible value of x = 5 or 4 and y = 7 or 8
(y cannot be 9 as that being unique highest)
The rest of the information can be gathered as follows-

Akhil’s score on Day 1 = 7