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Logarithm Test - 5

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Logarithm Test - 5
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Weekly Quiz Competition
  • Question 1
    3 / -1

    Solution

  • Question 2
    3 / -1

    If log 2 = .301, find the number of digits in (125)25.

    Solution

    logy = 25 log 125

    = 25 [log 1000 - 3 log 2]

    = 25 x (2.097)

    = 52 +
    Hence 53 digits.

  • Question 3
    3 / -1

    Solution

    (75/35) x (49/25) x (jc/105) x (25/13) = 1 ⇒ x = 13

  • Question 4
    3 / -1

    Which one of the following is true

    Solution

  • Question 5
    3 / -1

    Solution

    x = (16/15) x (255/245) x (813/803) None of these is correct.

  • Question 6
    3 / -1

    Find the value of the logarithmic expression in the questions below.

    Solution

    log (anbncn/anbncn) = log 1 = 0

  • Question 7
    3 / -1

    Solution

  • Question 8
    3 / -1

     log2 (9 - 2X) = 10log (3-x) Solve for x.

    Solution

    For x = 0, we have LHS

    Log2 8 = 3.
    RHS: 10log3 = 3.
    We do not get LHS = RHS for either x = 3 or x = 6.

    Thus, option (a) is correct.

  • Question 9
    3 / -1

    Which one of the following is true

    Solution

  • Question 10
    3 / -1

    log (x - 13) + 3 log 2 = log (3x + 1)

    Solution

  • Question 11
    3 / -1

    log . 0867 = ? 

    Solution

    Log 0.0867 = log (8.67/100) = log 8.67 - log 100 Log 8.67 - 2

  • Question 12
    3 / -1

    log3x = 1/2

    Solution

    x = 31/2 = √3 .

  • Question 13
    3 / -1

    If log10a = b, find the value of 103b in terms of a.

    Solution

    log10a = b ⇒ 10b = a ⇒ By definition of logs.

    Thus 103b = (10b)3 = a3.

  • Question 14
    3 / -1

    log (x2 - 6x + 6) = 0 

    Solution

  • Question 15
    3 / -1

     Find x If  logx = log 1.5 + log 12

    Solution

    log x = log 18 ⇒ x = 18

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