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Interest (Simple & Compound) Test - 4

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Interest (Simple & Compound) Test - 4
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  • Question 1
    3 / -1

    The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is: 

    Solution

    Let the sum be Rs. P

  • Question 2
    3 / -1

    The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is: 

  • Question 3
    3 / -1

    The Simple interest on a certain sum for 2 years at 20% per annum is Rs. 80. The corresponding compound interest is 

    Solution

    P = (100×80)/(20×2) = 200
    20%(200)= 40
    20%(40) = 8
    Required compound interest = 2(40)+ 8
    = 88

  • Question 4
    3 / -1

    A sum put out at 4% compound interest payable half-yearly amounts to Rs. 13265.10 in 1 1/2 years. The sum is:

  • Question 5
    3 / -1

    Arun invested an amount of Rs. 20000 in a fixed deposit scheme for 2 years at compound interest rate 4 p.c.p.a. How much amount will Arun get on maturity of the fixed deposit? 

  • Question 6
    3 / -1

    The compound interest on Rs. 20,480 at 6 1/4 % per annum for 2 years 73 days, is:

  • Question 7
    3 / -1

    A sum amounts to Rs. 882 in 2 years at 5% compound interest. The sum is 

    Solution

    Compound interest = Amount -Principal
    Amount = P(1 + R/100)N 
    882 = P(1+5/100)2
    =  882 × 20/21 × 20/21 
    P = 800
     

  • Question 8
    3 / -1

    Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 3000 for 2 years at 10% per annum. The sum placed on simple interest is: 

    Solution

    C.I = P[(1 + r/100)n - 1]
    C.I = 3000[(1 + 0.10)2 - 1]
    = 3000(1.21 - 1)
    ⇒ 3000 * 0.21 
    ⇒ 630
    S.I = 630/2
    ⇒ 315
    As we know that, P = (SI * 100)/(R * T)
    ⇒ (315 * 100)/(4 * 5)
    ⇒ 1575

  • Question 9
    3 / -1

    The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is

    Solution

    P [1 + (r/100)]n  >  2P
    ⇒ P [1 + (20/100)]n  >  2P
    [1 + (2/10) ]n  > 2
    [12 / 10]n  > 2
    [6/5]n  > 2
    {6/5 * 6/5 * 6/5 * 6/5}  >  2
    ∴ n = 4
     

  • Question 10
    3 / -1

    The difference between simple interest and compound on Rs. 2400 for one year at 10% per annum reckoned half-yearly is: 

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