Mensuration Test

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Mensuration Test - 4

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Weekly Quiz Competition

Question 1
3 / -1

Find the volume of a cuboid whose length is 8 cm, breadth 6 cm and height 3.5 cm.

A
150 cm³

B
168 cm²

C
215 cm³

D
168 cm³

Solution

Explanation:
Length of the cuboid = 8 cm
Breadth of the cuboid = 6 cm
Height of the cuboid = 3.5 cm
Volume of the cuboid = length × breadth × height
= 8 x 6 x 3.5 = 168cm³
Therefore,volume of the cuboid = 168cm³
Question 2
3 / -1

Find the area of the given figure.

A
14 cm²

B
12 cm²

C
10 cm²

D
16 cm²

Solution

Explanation:
Area of a parallellogram = Base x Height = 4 x 2.5 = 10 cm²
Question 3
3 / -1

Find the volume of a cuboid whose length is 8 cm, width is 3 cm and height is 5 cm.

A
120 cm²

B
125 cm³

C
120 cm

D
120 cm³

Solution

:Length of the cuboid = 8 cm
Width of the cuboid = 3 cm
Height of the cuboid = 5 cm
Volume of a cuboid = length × breadth × height
Therefore, Volume of the given cuboid = 8x3x5 = 120 cm³
Question 4
3 / -1

Find the perimeter of a rectangle whose length is 4 cm and breadth is 3 cm.

A
10 cm

B
12 cm

C
8 cm

D
14 cm

Solution

Explanation:Length of the rectangle,l = 4cm Breadth of the rectangle,b = 3 cmPerimeter of a rectangle = 2(l + b) = 2(4 + 3) = 2 x 7 = 14 cm
Question 5
3 / -1

Area of a rhombus = ______

A
Double the product of its diagonals

B
One-third of the product of its diagonals

C
Half the product of its diagonals

D
One-fourth of the product of its diagonals

Solution

Explanation:Area of a rhombus = Half the product of its diagonals = 1/2 x d₁x d₂
Question 6
3 / -1

Area of a trapezium = Half of the sum of the lengths of parallel sides × ______

A
Perpendicular distance between them

B
Slant height

C
Sum of base

D
Perimeter of base

Solution

Explanation:Area of a trapezium =( Half of the sum of the length of parallel sides )×(perpendicular distance between them)
Question 7
3 / -1

Surface area of a cuboid = __________

A
2 l (b + h)

B
2 h (l + b)

C
2(lb + bh + hl)

D
2lbh

Solution

Explanation:Surface area of a cuboid = 2(lb + bh + hl)where, l= lengthb = breadthand h = height
Question 8
3 / -1

_________ of a solid is the sum of the areas of its faces.

A
Volume

B
Surface area

C
Perimeter

D
Area

Solution

Explanation:The surface area of a three-dimensional figure is the sum of the areas of all its faces.
Question 9
3 / -1

In a right angled triangle, find the hypotenuse if base and perpendicular are respectively 36015 cmand 48020 cm.

A
69125 cm

B
60025 cm

C
391025 cm

D
60125 cm

Solution

Let hypotenuse = x cm
Then, by Pythagoras theorem:
x² = (48020)² + (36015)²
x fi 60025 cm
Question 10
3 / -1

The inner circumference of a circular track is 440 cm. The track is 14 cm wide. Find the diameterof the outer circle of the track.

A
84 cm

B
168 cm

C
336 cm

D
77 cm

Solution

Let inner radius = A; then 2pr = 440 \ p = 70
Radius of outer circle = 70 + 14 = 84 cm
Outer diameter = 2 × Radius = 2 × 84 = 168
Question 11
3 / -1

A pit 7.5 metre long, 6 metre wide and 1.5 metre deep is dug in a field. Find the volume of soilremoved in cubic metres.

A
135 m³

B
101.25 m³

C
50.625 m³

D
67.5 m³

Solution

Volume of soil removed = l × b × h
= 7.5 × 6 × 1.5 = 67.5 m³
Question 12
3 / -1

The whole surface of a rectangular block is 8788 square cm. If length, breadth and height are inthe ratio of 4 : 3 : 2, find length.

A
26 cm

B
52 cm

C
104 cm

D
13 cm

Solution

Let the common ratio be = x
Then, length = 4x, breadth = 3x and height = 2x
As per question;
2(4x x 3x + 3x x 2x + 2x x 4x) = 8788
2(12x2 + 6x2 + 8x2) = 8788 fi 52x2 = 8788
fi x = 13
Length = 4x = 52 cm
Question 13
3 / -1

Find the height of a Cuboid , if the volume and area of its base is 1240cm3 and 40 sq.cm respectively.

A
31 cm

B
20 cm

C
60cm

D
41cm
Question 14
3 / -1

A bicycle wheel makes 5000 revolutions in moving 11 km. What is the radius of the wheel?

A
70 cm

B
135 cm

C
17.5 cm

D
35 cm

Solution

Let the radius of the wheel be = p
Then 5000 × 2pr = 1100000 cm fi r = 35 cm
Question 15
3 / -1

The short and the long hands of a clock are 4 cm and 6 cm long respectively. What will be sum ofdistances travelled by their tips in 4 days? (Take p = 3.14)

A
954.56 cm

B
3818.24 cm

C
2909.12 cm

D
2703.56 cm

Solution

In 4 days, the short hand covers its circumference
4 × 2 = 8 times long hand covers its circumference
4 × 24 = 96 times
Then they will cover a total distance of:-
(2 × p × 4)8 + (2 × p × 6)96 fi 3818.24 cm

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Mensuration Test - 4

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Mensuration Test - 4

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SHARING IS CARING

Question 1

150 cm3

168 cm2

215 cm3

168 cm3

Solution

Question 2

14 cm2

12 cm2

10 cm2

16 cm2

Solution

Question 3

120 cm2

125 cm3

120 cm

120 cm3

Solution

Question 4

10 cm

12 cm

8 cm

14 cm

Solution

Question 5

Double the product of its diagonals

One-third of the product of its diagonals

Half the product of its diagonals

One-fourth of the product of its diagonals

Solution

Question 6

Perpendicular distance between them

Slant height

Sum of base

Perimeter of base

Solution

Question 7

2 l (b + h)

2 h (l + b)

2(lb + bh + hl)

2lbh

Solution

Question 8

Volume

Surface area

Perimeter

Area

Solution

Question 9

69125 cm

60025 cm

391025 cm

60125 cm

Solution

Question 10

84 cm

168 cm

336 cm

77 cm

Solution

Question 11

135 m3

101.25 m3

50.625 m3

67.5 m3

Solution

Question 12

26 cm

52 cm

104 cm

13 cm

Solution

150 cm³

168 cm²

215 cm³

168 cm³

14 cm²

12 cm²

10 cm²

16 cm²

120 cm²

125 cm³

120 cm³

135 m³

101.25 m³

50.625 m³

67.5 m³