Coordinate Geometry Test

Result

Coordinate Geometry Test - 5

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
3 / -1

If the point (x, y) is equidistant from the points (5, 1) and ( – 1, 5), then the relation between ‘x’ and ‘y’ is given by

A
3x = 2y

B
– 2x = 3y

C
2x = 3y

D
3x = – 2y

Solution

Let the point C(x,y)is equidistant from the points A (5, 1) and B(−1,5).(−1,5).

i.e. AC = BC
Question 2
3 / -1

The points A(4, – 1), B(6, 0), C(7, 2) and D(5, 1) are the vertices of a

A
Rectangle

B
Parallelogram

C
Rhombus

D
Square

Solution

Therefore diagonals AC and BD are not equal
Since, all sides are equal and both diagonals are not equal.
Therefore, the given quadrilateral is a rhombus.
Question 3
3 / -1

The co – ordinates of the mid – point of the line joining the points (3p, 4) and ( – 2, 4) are (5, p). The value of ‘p’ is

A
1

B
2

C
3

D
4

Solution

Let the coordinates of midpoint O(5,p) is equidistance from the points A(3p,4) and B(−2,4).( because O is the mid-point of AB)
Question 4
3 / -1

If the points (2, 3), (4, k) and (6, – 3) are collinear, then the value of ‘k’ is

A
1

B
0

C
3

D
4

Solution

Let the points A (2, 3), B(4,k) and C(6,−3) be collinear.
If the points are collinear then area of triangle ABC formed by these three points is 0.
Question 5
3 / -1

The distance of a point from the y – axis is called

A
none of these

B
abscissa

C
ordinate

D
origin

Solution

The distance of a point from the y – axis is the x (horizontal) coordinate of the point and is called abscissa.
Question 6
3 / -1

If the point P(2, 4) lies on a circle, whose centre is C(5, 8), then the radius of the circle is

A
5 units

B
25 units

C
4 units

D
8 units

Solution

The point P(2 , 4) is on the circle and C(5, 8) is its centre

Hence PC will be Radius of circle.
Question 7
3 / -1

The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is

A
15 units

B
12 units

C
9 units

D
10 units

Solution

Given: the vertices of a triangle ABC, A(0, 4), B (0, 0) and C (3, 0).
∴ Perimeter of triangle ABC = AB + BC + AC
Question 8
3 / -1

The co – ordinates of the point which divides the join of ( – 6, 10) and (3, – 8) in the ratio 2 : 7 is

A
(1, – 3)

B
( – 4, 6)

C
(4, – 6)

D
( – 1, 3)

Solution
Question 9
3 / -1

If the points (x, y), (1, 2) and (7, 0) are collinear, then the relation between ‘x’ and ‘y’ is given by

A
3x + y + 7 = 0

B
3x – y – 7 = 0

C
x – 3y + 7 = 0

D
x + 3y – 7 = 0

Solution

and these are collinear
Question 10
3 / -1

The distance of a point from the x – axis is called

A
none of these

B
origin

C
abscissa

D
ordinate

Solution

The distance of a point from the x – axis is the y (vertical) coordinate of the point and is called ordinate.
Question 11
3 / -1

A circle has its centre at the origin and a point P(5, 0) lies on it. Then the point Q(8, 6) lies ________ the circle.

A
out side

B
on

C
none of these

D
in side

Solution
Question 12
3 / -1

(0, 3), (4, 0) and ( – 4, 0) are the vertices of

A
a right triangle

B
a scalene triangle

C
an isosceles triangle

D
an equilateral triangle

Solution

Since, two sides are equal, therefore, ABC is an isosceles triangle.
Question 13
3 / -1

The ratio in which the point (1, 3) divides the line segment joining the points ( – 1, 7) and (4, – 3) is

A
2 : 3

B
2 : 7

C
3 : 2

D
7: 2

Solution
Question 14
3 / -1

If the vertices of a triangle are (1, 1), ( – 2, 7) and (3, – 3), then its area is

A
2 sq. units

B
24 sq. units

C
0 sq. units

D
12 sq. units

Solution

Given: (x1,y1)=(1,1),(x2,y2)=(−2,7) and (x3,y3)=(3,−3)=(3,−3), then the Area of trianlge

Also therefore the three given points(vertices) are collinear
Question 15
3 / -1

The point of intersection of the x – axis and y – axis is called

A
quardant

B
ordinate

C
abscissa

D
origin

Solution

The point of intersection of the x – axis and y – axis is called origin.The coordinates of origin are (0, 0).