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Inequalities Test - 2

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Inequalities Test - 2
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Weekly Quiz Competition
  • Question 1
    3 / -1

    3x2 - 7x + 4 ≤ 0

    Solution

    At x = 0, inequality is not satisfied. Thus, option (c) is rejected. Also x = 0 is not a solution of the equation. Since, this is a continuous function, the solution cannot start from 0. Thus options (a) and (b) are not right. Further, we see that the given function is quadratic with real roots. Hence, option (d) is also rejected.

  • Question 2
    3 / -1

     

    3x2 - 7x + 6 < 0

     

    Solution

     

     

    At x = 0, inequality is not satisfied.
    Hence, options (b), (c) and (d) are rejected. At x = 2, inequality is not satisfied. Hence, option (a) is rejected.
    Thus, option (d) is correct.

     

     

  • Question 3
    3 / -1

    X2 - 14x - 15 > 0

    Solution

    At x = 0 inequality is not satisfied. Thus option (d) is rejected. x = -1 and x = 15 are the roots of the quadratic equation. Thus, option (c) is correct.

  • Question 4
    3 / -1

    For all integral values of x,

    |x - 4| x< 5

    Solution

    At x = 0 inequality is satisfied, option (b) is rejected.

    At x = 2, inequality is satisfied, option (c) is rejected.

    At x = 5, LHS = RHS.

    Thus, option (d) is correct.

  • Question 5
    3 / -1

    |x2 - 2x| < x

    Solution

    At x = 1 and x = 3 LHS = RHS.
    At x = 2 inequality is satisfied.
    At x = 0.1 inequality is not satisfied.
    At x = 2.9 inequality is satisfied.
    At x = 3.1 inequality is not satisfied.
    Thus, option (a) is correct.

  • Question 6
    3 / -1

    x2 - 7x + 12 < | x - 4 |

    Solution

    At x = 0, inequality is not satisfied, option (a) is rejected.

    At x = 5, inequality is not satisfied, option (b) is rejected.
    At x = 2 inequality is not satisfied.
    Options (d) are rejected.
    Option (c) is correct.

  • Question 7
    3 / -1

    |x - 6| > x2 - 5x + 9

    Solution

    At x = 2, inequality is satisfied.
    At x = 0, inequality is not satisfied.
    At x = 1, inequality is not satisfied but LHS = RHS. At x = 3, inequality is not satisfied but LHS = RHS. Thus, option (b) is correct.
    Solve other questions of LOD I and LOD II in the same fashion.

  • Question 8
    3 / -1

    3x2 – 7x – 6 < 0

    Solution

    At x = 0, inequality is satisfied. Hence, options (b) and (c) are rejected. x = 3 gives LHS = RHS.
    and x = – 0.66 also does the same. Hence. roots of the equation are 3 and – 0.66.
    Thus, option (a) is correct.

  • Question 9
    3 / -1

    x2 – 14x – 15 > 0

    Solution

    At x = 0 inequality is not satisfied. Thus option (d) is rejected.
    x = –1 and x = 15 are the roots of the quadratic equation. Thus, option (c) is correct.

  • Question 10
    3 / -1

    |x2 + x| – 5 < 0

  • Question 11
    3 / -1

    |x2 – 2x – 3| < 3x – 3

    Solution

    x2 - 2x - 3 ≥ 0
    (x-3) (x+1) ≥ 0
    x belongs to (-∞,-3]∪[3,∞)
    Therefore, x belongs to (-1,3)
    => x2 - 2x - 3 > 0
    x2 - 2x - 3< 3x - 3
    x2 - 5x < 0
    x(x-5) < 0
    x belongs to (0,5)........(1)
    x2 - 2x - 3 < 0
    x2 - 2x - 3 < 3x - 3
    x2 + x - 6 > 0
    (x+3)(x-2) > 0
    x belongs to (-∞,-3]∪[2,∞)
    x belongs to (2,3)........(2)
    Taking intersection of (1) and (2)
    we get,
    x belongs to (2,5)
     

  • Question 12
    3 / -1

    x2 – 7x + 12 < |x – 4|

    Solution

    At x = 0, inequality is not satisfied, option (a) is rejected.
    At x = 5, inequality is not satisfied, option (b) is rejected.
    At x = 2 inequality is not satisfied.
    Options (d) are rejected.
    Option (c) is correct

  • Question 13
    3 / -1

    |x – 6| > x2 – 5x + 9

    Solution

    At x = 2, inequality is satisfied.
    At x = 0, inequality is not satisfied.
    At x = 1, inequality is not satisfied but LHS = RHS.
    At x = 3, inequality is not satisfied but LHS = RHS.
    Thus, option (b) is correct.
    Solve other questions of LOD I and LOD II in the same fashion.

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