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Area Related to Circles Test - 30

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Area Related to Circles Test - 30
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  • Question 1
    1 / -0
    Five identical rectangles are placed inside a square with side $$24 cm$$ as shown in the diagram. What is the area of one rectangle ?

    Solution
    Consider vertical line, let $$b$$ & $$h$$ be breadth and height of rectangle then,

    $$24=b+h+h+b$$ (vertically)
    $$b+h=12 \ \ \ \ \ \ ....(1)$$

    $$24=h+(h-b)+b+h$$ (horizontally)
    $$3h=24$$

    $$h=8$$ 

    Substituting $$h=8$$ in equation $$(1)  $$

    $$b=4$$

    Area $$= bh=32 \ cm^2$$.
  • Question 2
    1 / -0
    In the following figure  $$A B = B C$$  and  $$A C = 84 \mathrm { cm } .$$  The radius of the smallest circle is  $$14\mathrm { cm } .$$  $$B$$  is the centre of the largest semicircle. What is the area of the shaded region.

    Solution
    REF.Image
    AC = 84 cm
    AB = BC =
    2AB = 84
    AB = 42
    Area of circle (semi) whose diameter is AB.
    $$A_{1}=\pi R^{2}/2$$
    $$=\pi (21)^{2}/2=\frac{22}{7}\times 22\times 21\times \frac{1}{2}$$
    $$= 11\times 3\times 21=33\times 21$$
    $$= 693 cm^{2}$$
    Area of circle (semi) whose diameter is BC
    $$A_{2}=\frac{\pi R^{2}}{2}$$
    $$= 693 cm^{2}$$
    Area of circle whose diameter is AC
    $$A=\frac{\pi R^{2}}{2}=\frac{22}{7}\times 42\times 42\times \frac{1}{2}$$
    $$A=\frac{5544}{2}cm^{2}= 2772 cm^{2}$$
    Area of smallest circle
    $$a=\pi r^{2}=\frac{22}{7}\times 14\times 14=616 cm^{2}$$
    Area of the shaded region = $$A-(A_{1}+A_{2}+a)$$
    $$=2772-(693+693+616)$$
    $$=2772-2002$$
    $$770 cm^{2}$$

  • Question 3
    1 / -0
    The area $$(in cm^2)$$ of a sector of a circle with an angle of $$45^o$$ and radius $$3$$ cm is_.
    Solution
    Given circle radius $$=3cm$$ (r)
    Sector angle $$=45$$
    Area of sector $$=\dfrac{45}{360}\times \pi r^2$$
    $$=\dfrac{1}{8}\times \dfrac{22}{7}\times (3)^2$$
    $$=\dfrac{22}{8.7}\times 9$$
    $$=\dfrac{99}{28}$$ sq. cm
    $$=3\dfrac{15}{28}$$ sq. cm.

  • Question 4
    1 / -0
    In a circle of radius $$\displaystyle 14 $$ cm an arc subtends an angle of $$\displaystyle 36^0$$ at the centre. The length of the arc is
    Solution
    $$\displaystyle \theta = \left( 36 \times \frac{\pi}{180}\right)^c = \left( \frac{\pi}{5} \right)^c$$ and $$\displaystyle r = 14 $$ cm.
    $$\displaystyle \therefore \ \ l = r \theta = \left( 14 \times \frac{\pi}{5} \right)$$ cm = $$\displaystyle  \left( 14 \times \frac{22}{7} \times \frac{1}{5} \right)$$ cm = $$\displaystyle \frac{44}{5} $$ cm = $$\displaystyle 8.8 $$ cm.
  • Question 5
    1 / -0
    The center of the circle lies
    Solution

  • Question 6
    1 / -0
    The shaded portion of the circle represents

  • Question 7
    1 / -0
    In the given figure, $$r$$ represents

    Solution
    $${\textbf{Step -1: Find r.}}$$

                     $${\text{The distance from the center point to any point on the circle is called the radius of a circle}}$$

                     $${\text{Here, r is the radius in the figure.}}$$

    $${\textbf{Hence, the correct answer is option A.}}$$
  • Question 8
    1 / -0
    In the adjoining figure, $$18 in$$ is the length of 

    Solution

  • Question 9
    1 / -0
    A chord divides a circle into two
    Solution

  • Question 10
    1 / -0

    The centres of a set of circle,

    each of radius $$ 3$$, lies on the circle $$x^2 + y^2 = 25$$. The locus of any

    point in the set is

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