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Surface Areas and Volumes Test - 18

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Surface Areas and Volumes Test - 18
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The volume of a frustum of cone is calculated by using the formula ______.
    Solution
    V = volume
    r = radius of the small circular end plane
    R = radius of the big circular end plane
    h  = height of the frustum
    $$\therefore \cfrac{1}{3}\pi h(R^2+r^2+Rr)$$
  • Question 2
    1 / -0
    The total surface area of a frustum of cone is calculated by using the formula _________.
    Solution
    Area of slanted surface$$=\pi l(r+R)$$
    Area of base circle of frustum $$=\pi R^2$$

    Area of top circle of frustum $$=\pi r^2$$

    Total surface area $$=\pi[R^2+r^2+l(R+r)]$$
  • Question 3
    1 / -0
    Two cubes each of $$8cm$$ edge are joined end to end. Find the surface area of the resulting cuboid.
    Solution
    REF image:
    Surface area = surface area of the cuboid having sides $$l,b,h$$ as $$(8+8)cm, 8cm, 8cm$$ respectively.
                          $$=2(lb+bh+hl)$$
                          $$=2((8+8)\times 8+8\times 8+(8+8)\times 8)$$

                          $$=2(128+64+128)$$ 

                          $$=640cm^{2}$$

  • Question 4
    1 / -0
    The curved surface area of frustum of a cone is given by
    Solution

  • Question 5
    1 / -0
    The maximum length of a pencil that can be kept in rectangular box of dimensions $$12\ cm\times 9\ cm \times 8\ cm$$, is
    Solution
    Rectangular box is has the cuboidal shape. Maximum length of a pencil can be kept along the diagonal of the box.

    We know that length of diagonal of the cuboid $$=\sqrt{l^2+b^2+h^2}$$
    So,

    $$D=\sqrt{12^2+9^2+8^2}$$

    $$=\sqrt{144+81+64}$$

    $$=17$$
  • Question 6
    1 / -0
    A metal sheet 27 cm long, 8 cm broad and 1 cm thick is melted into a cube. The side of the cube is 
    Solution
    A metal sheet 27 cm long, 8 cm braod and 1 cm thick has the volume of = $$ 1\times b\times h $$ = $$ 27\times 8\times 1 $$ = 216 cm $$ ^{3} $$ 
    As the sheet was melted to form a cube of edge length a, the volume of a cube = volume of the metal sheet
    $$ \Rightarrow  $$ $$ a^{3} $$ =  $$ 216 cm^{3} $$
    $$ \Rightarrow  $$  a = 6 cm
  • Question 7
    1 / -0
    A cube of side 5 Cm is painted on all its faces. If it is sliced into 1 cubic centimeter cubes, how many 1 cubic centimeter cubes will have exactly one of their faces painted
    Solution
    (c) 54, Given , a cube of side 5 m is painted on all its faces and is sliced into 1 $$ Cm^{3} $$ cubes. Then, form figure, it is clear that there are 9 cubes available on face
    As there are 6 faces, so the total number of smaller cubes = 6  x 9 = 54.

  • Question 8
    1 / -0
    A shuttle cock used for playing badminton has the shape of the combination of
    Solution
    A shuttle cock used for playing badminton has the shape of the combination of frustrum of a cone and a hemisphere.

  • Question 9
    1 / -0
    A cylindrical pencil sharpened at one edge is the combinations of
    Solution
    The sharpened part of the pencil is cone and unsharpened part is cylinder.

  • Question 10
    1 / -0
    The radii of the top and bottom of a bucket of slant height $$45$$ cm are $$28$$ cm and $$7$$ cm respectively. The curved surface area of the bucket is
    Solution
    Given:
    Slant Height, $$l = 45$$ cm
    Top radius $$= 28$$ cm
    Bottom radius 
    $$=7$$ cm
    Height $$=45$$ cm
    Curved surface area $$=\pi l\left( r_1+r_2 \right) $$
    $$=\dfrac { 22 }{ 7 } \times 45\left( 7+28 \right) $$
    $$=4950 cm ^2$$

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