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Statistics Test - 19

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Statistics Test - 19
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  • Question 1
    1 / -0
    What is the modal class for the following distributions?
    Class interval
    $$22-33$$
    $$33-44$$
    $$44-55$$
    $$55-66$$
    $$66-77$$
    $$77-88$$
    $$88-99$$
    Frequency
    $$23$$
    $$45$$
    $$67$$
    $$89$$
    $$100$$
    $$123$$
    $$20$$

    Solution
    Modal class is the class which has the highest frequency.

    The highest frequency is $$123$$ which is associated with the class $$77-88$$
    Therefore, the modal class is $$77-88$$
  • Question 2
    1 / -0
    The marks scored by $$20$$ students in exam are given below$$:$$ Find the median.
    Marks
    $$50$$
    $$60$$
    $$70$$
    $$80$$
    Students
    $$1$$
    $$2$$
    $$3$$
    $$4$$

    Solution
    Marks
    Students(f)
    Cumulative frequency(cf)
    $$50$$
     $$1$$
    $$1$$
    $$60$$
     $$2$$
    $$1+2=3$$
    $$70$$
     $$3$$
    $$3+3=6$$
    $$80$$
     $$4$$
    $$6+4=10$$


    $$n=\Sigma f=10$$

    $$\displaystyle\frac{n}{2}=\frac{10}{2}=5$$


               $$\displaystyle\frac{n}{2}=\frac{10}{2}=5$$
    Therefore, the corresponding value of marks for $$5$$ is $$70$$.
  • Question 3
    1 / -0
     Number of employees 5 6 7 8
     Daily wedges 500 750200  400 600
    Estimate the mean of the following data 
    Solution
     Number of employees
                    $$xi$$
     Daily wedges
              $$fi$$
     $$fixi$$
     2 500 1000
     5 750 3750
     6 200 1200
     7 400 2800
     8 600 4800
      $$\sum fi=2450$$ $$\sum fixi=13550$$
    First construct the following table.
    Mean using direct method, $$\bar { x } =\dfrac { \sum { { f }_{ i } } { x }_{ i } }{ \sum { { f }_{ i } }  } $$
    $$\therefore \bar { x } =\dfrac { 13,550 }{ 2,450 } $$
    $$\bar { x } =5.53$$
    Mean, $$\bar { x } =5.53$$.
  • Question 4
    1 / -0
    The following table shows the scores of a group of $$20$$ football players. Identify the modal class.
    Scores
    $$7-14$$
    $$14-21$$
    $$21-28$$
    $$28-35$$
    $$35-42$$
    Football players
    $$30$$
    $$40$$
    $$20$$
    $$60$$
    $$10$$

    Solution

    The modal class is the class with the highest frequency. In this case, the highest frequency is $$60,$$ which is the frequency for class $$28-35$$.

  • Question 5
    1 / -0
    For the following table identify the modal class:
    Length
    $$6-12$$
    $$12-18$$
    $$18-24$$
    $$24-30$$
    $$30-36$$
    $$36-42$$
    $$42-48$$
    Frequency
    $$100$$
    $$234$$
    $$450$$
    $$342$$
    $$540$$
    $$289$$
    $$265$$
    Solution
    We know that, a modal class is the class which has the highest frequency.

    The highest frequency in the given table is $$540$$, which is associated with the class $$30-36$$

    Hence, the modal class is $$30-36$$.
  • Question 6
    1 / -0
    The mean of first 10 natural numbers is
    Solution
    The first 10 natural numbers are 1,2,3,4,5,6,7,8,9,10
    Then mean of first natural numbers =$$\frac{1+2+3+4+5+6+7+8+9+10}{2}=\frac{55}{10}=5.5=\frac{11}{2}$$
  • Question 7
    1 / -0
    Consider the data: $$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2$$. The frequency of $$2$$ is _____
    Solution
    Number of times $$ 2 $$ occurs in the given data is $$ 5 $$

    So, frequency of $$ 2 $$ in given data is $$ 5 $$.
  • Question 8
    1 / -0
    The mean of 20 items of a data is 5 and if each item is multiplied by 3 then the mean will be
    Solution
    Given the mean of 20 items are 5
    Then total of 20 items =$$20\times 3=300$$
    Then new mean =$$\frac{300}{20}=15$$
    If multiply each item by 3 then total of 20 items =$$100\times 5=100$$
  • Question 9
    1 / -0
    Find the median class$$:$$
    Marks
    $$10-20$$
    $$20-30$$
    $$30-40$$
    $$40-50$$
    $$50-60$$
    Number of students
    $$12$$
    $$35$$
    $$15$$
    $$25$$
    $$13$$

  • Question 10
    1 / -0
    Calculate the mode for the following data$$:$$
    Distance(km)$$11$$$$21$$$$31$$$$41$$$$51$$
    Number of persons$$4$$$$6$$$$10$$$$20$$$$18$$
    Solution
    Mode for the discrete series is the variable which has the highest frequency.
    From the given distribution table, the highest frequency is $$20$$ which is associated with the variable $$41$$
    Therefore, the mode is $$41$$
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