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Probability Test - 10

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Probability Test - 10
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  • Question 1
    1 / -0

    An unbiased die is thrown once. The probability of getting an odd number is

    Solution

     

    Number of odd numbers on a dice = {1, 3, 5}, = 3
    Number of possible outcomes = 3
    Number of Total outcomes = 6
    ∴ Required Probability = 3/6 = 1/2

  • Question 2
    1 / -0

    From a well-shuffled pack of 52 cards, one card is drawn at random. The probability of getting a face card is

    Solution

     

    Face Cards are = 4 kings + 4 queens + 4 jacks = 12
    Number of possible outcomes = 12
    Number of Total outcomes = 52
    ∴ Required Probability = 12/52 = 3/13

  • Question 3
    1 / -0

    An unbiased die is thrown once. The probability of getting a number between 2 and 6 is

    Solution

    Number of numbers between 2 and 6 on a dice = {3, 4, 5}, = 3
    Number of possible outcomes = 3
    Number of Total outcomes = 6
    ∴ Required Probability = 3/6=1/2

  • Question 4
    1 / -0

    From a well shuffled pack of 52 cards, one card is drawn at random. The probability of getting a jack of hearts is

    Solution

     

    Number of jacks of Heart in a pack of 52 cards = 1
    Number of possible outcomes = 1
    Number of Total outcomes = 52
    ∴ Required Probability = 1/52

  • Question 5
    1 / -0

    An unbiased die is thrown once. The probability of getting a multiple of 3 is

    Solution

    Number of multiple of 3 on a dice = {3, 6}, = 2
    Number of possible outcomes = 2
    Number of Total outcomes = 6
    ∴ Required Probability = 2/6 = 1/3

  • Question 6
    1 / -0

    Ram and Shyam are friends. The probability that both will have the birthday on the same day is

    Solution

    Assuming a non-leap year

    Ram can have the birthday on any day of the 365 days of the year

    Shyam has a different birthday if his birthday is on any of the remaining 364 days of the year 

    Therefore P (Ram and Shyam have different birthdays) = 364 / 365

    and so, P (Ram and Shyam have birthdays on the same day) = 1 - P(Ram and Shyam have different birthdays)

     = 1 - 364/365

     = 1/365

  • Question 7
    1 / -0

    A letter of English alphabets is chosen at random. The probability that the letter chosen is a consonant is

    Solution

    We have,
    Number of vowels = 5 ( a  e  i  o  u)
    Number of consonants = 21  ( 26 - 5 = 21 ) 
    Number of possible outcomes = 21
    Number of total outcomes = 26
    ∴ Required Probability = 21/26

  • Question 8
    1 / -0

    Cards marked with numbers 1, 2, 3, ……….., 25 are placed in a box and mixed thoroughly and one card is drawn at random from the box. The probability that the number on the card is a multiple of 3 or 5 is

    Solution

    Number of multiples of 3 = 8 ( 3  6  9  12  15  18  21  24)
    Number of multiples of 5 = 5 ( 5  10  15  20  25)
    Number of possible outcomes (multiples of 3 or 5)  = 12 ( 3,5,6,9,10,12,15,18,20,21,24,25 )
    Number of Total outcomes = 25
    ∴ Required Probability = 12/25

  • Question 9
    1 / -0

    A letter of English alphabets is chosen at random. The probability that the letter chosen is a vowel is

    Solution

    We know that "A , E , I , O , U" are vowels 

    Number of vowels = 5

    Number of possible outcomes = 5
    Number of total outcomes = 26
    ∴ Required Probability = 5/26

  • Question 10
    1 / -0

    Cards marked with numbers 1, 2, 3, ……….., 25 are placed in a box and mixed thoroughly and one card is drawn at random from the box. The probability that the number on the card is a multiple of 3 and 5 is

    Solution

    Multiples of 3  =  3 6 9 12 15 18 21 24

    Multiples of 5 = 5  10 15 20 25
    Number of possible outcomes (multiple of 3 and 5) = {15} = 1
    Number of Total outcomes = 25
    ∴ Required Probability =1/25

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