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Arithmetic Progressions Test - 19

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Arithmetic Progressions Test - 19
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  • Question 1
    1 / -0
    Is $$-150$$ a term of the $$A.P$$ : $$11, 8, 5, 2$$ ?
    Solution
    Clearly the given sequence is an AP with first term $$a=11$$ and the common difference $$d=8-11=-3$$.

    Let $$-150$$ be the $$n^{th}$$ term of given AP. Then,
    $$a_n=-150\Rightarrow t_n= a+(n-1)d=-150$$
    $$\Rightarrow 11+(n-1)\times-3=-150$$
    $$\Rightarrow (n-1)\times-3=-161$$
    $$\Rightarrow n-1=\dfrac{-161}{-3}$$
    $$\Rightarrow n=\dfrac{161}{3}+1=\dfrac{164}3$$
    Clearly $$n$$ is not an natural number, Hence, $$-150$$ is not a term of given AP.
  • Question 2
    1 / -0
    Find the nth term and 9th term of the sequence 3, 7, 11, 15.........
    Solution
    We know,
    $$n^{th}$$ term $$a_{n}= a+(n-1)d $$

    $$a =$$ First term
    $$d =$$ Common difference
    $$n =$$ number of terms
    $$a_n = n^{th}$$ term

    Here,
    $$a=3\ and\ d=7-3\ or\ 11-7=4$$

    $$a_n=a+(n-1)d=3+(n-1)4$$
    $$a_n=4n-1$$

    For $$9$$th term put $$n=9$$
    $$T_9=a_9=4\times9-1=35$$
  • Question 3
    1 / -0
    Write the first term $$a$$ and the common difference $$d$$ of the AP : $$-5, -1, 3, 7......$$
    Solution
    Given series is $$-5, -1, 3,7,......$$
    Clearly first term is $$a=-5$$
    And common difference $$d=-1-(-5)=4$$
  • Question 4
    1 / -0
    Find out whether the sequence $$1^2, 3^2, 5^2, 7^2$$,... is an AP. If it is, find out the common difference.
    Solution
    Given series is $$1^2, 3^2, 5^2, 7^2,......$$
    We have, $$3^2-1^2=9-1=8$$
    $$5^2-3^2=25-9=16$$
    $$7^2-5^2=49-25=24$$
    This shows that the difference of a term and the preceding term is not always same.
    Hence, the given sequence is not an AP.

  • Question 5
    1 / -0
    Check if the series is an AP. Find the common difference $$d$$ and write three more terms of the the following series.
    $$2, 4, 8, 16,....$$
    Solution
    Given series is $$2,4,8,16,.....$$

    In an AP series, the difference between the consecutive terms remain same:
    $$a_2-a_1=4-2=2$$

    $$a_3-a_2=8-4=4$$

    $$a_3-a_2\neq a_2-a_1$$

    This shows that the difference of a term and the preceding terms is not always same. Hence, the given sequence is not an AP.
  • Question 6
    1 / -0
    Find first term 'a' and common difference 'd' for the following AP.

    $$\sqrt{2}$$, $$\sqrt{8}$$, $$\sqrt{18}$$, $$\sqrt{32}$$,.....
    Solution
    The sequence $$\sqrt2,\sqrt8,\sqrt{18},\sqrt{32},...$$ can be written as $$\sqrt2,2\sqrt2,3\sqrt2,4\sqrt{2},...$$
    Clearly, it is an AP with first term $$a=\sqrt2$$ and common difference $$d=\sqrt2$$.

  • Question 7
    1 / -0
    Check if the series is an A.P. Find the common difference $$d$$ and write three more terms of the the following series.
    $$2,\displaystyle\frac{5}{2}$$, $$3,\displaystyle\frac{7}{2}, ...$$
    Solution
    It is an A.P. because $$a = 2$$, $$d = \dfrac12$$
    $$\because [(t_2 - t_1) = (t_3 - t_2) = (t_4 - t_3) = \dfrac12]$$
    $$t_5 = \dfrac{7}{2} + \dfrac{1}{2} = 4$$
    $$t_6 = 4 + \dfrac{1}{2} = \dfrac{9}{2}$$
    $$t_7 = \dfrac{9}{2} + \dfrac{1}{2}= 5$$
  • Question 8
    1 / -0
    For the following AP, write the first term and the common difference
    $$3, 1, -1, -3$$
    Solution
    Given series is $$3,1,-1,-3,......$$
    First term $$a=3$$ 
    And common difference $$d=a_2-a_1$$
    $$=1-3$$
    $$=-2$$.
  • Question 9
    1 / -0
    Write first four terms of the AP, when the first term $$a$$ and the common difference $$d$$ are given as follows:
    $$a = 10, d =10$$
    Solution
    Here $$a=10$$ and $$d=10$$.

    Now, $$n^{th}$$ term $$=a_n=a+(n-1)d$$

    $$\therefore t_1=a=10$$

    $$t_2=a+d=10+10=20$$

    $$t_3=a+2d=10+2\times10=30$$

    $$t_4=a+3d=10+3\times10=40$$

    Thus, the first four terms of given AP are $$10,20,30,40$$.
  • Question 10
    1 / -0
    For the following AP, write the first term and the common difference
    $$-5, -1, 3, 7$$
    Solution
    Given series is $$-5,-1,3,7,....$$
    First term $$a=-5$$ 
    And common difference $$d=a_2-a_1$$
    $$=-1-(-5)$$
    $$=-1+5$$
    $$=4$$
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