Coordinate Geom...

Find the area of the triangle whose vertices are $$(a, b + c), (a, b - c)$$ and $$(-a, c)$$.

The area of the triangle whose vertices are $$A(1,1), B(7, 3)$$ and $$C(12, 2)$$ is

The mid-point of the line segment joining $$( 2a, 4)$$ and $$(-2, 2b)$$ is $$(1, 2a + 1 )$$. The values of $$a$$ and $$b$$ are 

Find the co ordinates of the point which divides the line segment joining the points (6, 3) and (-4, 5) in the ratio 3 : 2 internally

$$(3, 1), (-3, 2)$$ and $$\displaystyle (0,2-\sqrt{3})$$ are the vertices of __________ triangle of area ___________.

Three points A, B and C have coordinates $$(a, b + c), \ (b, c + a)$$ and $$(c, a + b)$$, respectively. The area of the triangle ABC will be:

If the coordinates of two points A and B are $$(3, 4)$$ and $$(5, -2)$$, respectively, then the coordinates of any point P if $$PA = PB$$ and area of $$\displaystyle \Delta PAB=10$$ is

The  triangle with vertices A(4, 4), B(-2, -6) and C(4, -1) is shown in the diagram. The area of $$\Delta$$ ABC is _______

The coordinates of the points P and Q are respectively (4, - 3) and (-1, 7) Then the abscissa of a point R on the line segment PQ such that $$\displaystyle \frac{PR}{PQ}=\frac{3}{5}$$ is