Electricity Test

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Electricity Test - 48

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Weekly Quiz Competition

Question 1
1 / -0

Two wires of resistances 10 $$\Omega$$ and 5 $$\Omega$$ are connected in series. The effective resistances is _______ $$\Omega$$

A
15

B
20

C
30

D
40

Solution

we know that in the series combination of two resistors, the equivalent resistance is given by-

$$R_{eq}=R_1+R_2$$

Here-

$$R_{eq}=10+5$$

$$\Rightarrow R_{eq}=15\Omega$$
Question 2
1 / -0

If n number of identical resistors of resistance R are connected in parallel combination, then the effective resistance of the combination is ______

A
nR

B
n/R

C
R/n

D
$$nR-\frac {n}{R}$$

Solution

For parallel combination we know that for equivalent resistance-

$$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+...$$

Here-

$$\dfrac{1}{R_{eq}}=\dfrac{1}{R}+\dfrac{1}{R}+\dfrac{1}{R}+... n \hspace{2mm}times$$

$$\implies \dfrac{1}{R_{eq}}=\dfrac{n}{R}$$

$$\implies R_{eq}=\dfrac{R}{n}$$

Answer-(C)
Question 3
1 / -0

Calculate the electrical energy consumed in units when a 60 W bulb is used for 10 hours

A
1

B
0.6

C
0.3

D
2

Solution

Power is energy consumed per unit time.

Here, energy consumed$$=P=60W$$ and time$$=t=10hr=36000s$$

$$P=\dfrac{E}{t}$$

$$\implies E=Pt=60\times 36000J=3.6\times 10^5\times 6J$$

$$1 unit=3.6\times 10^6J$$

$$\implies E=\dfrac{3.6\times 6\times 10^5}{3.6\times 10^6}$$

$$\implies E=0.6units$$

Answer-(B)
Question 4
1 / -0

The equivalent resistance of the combination of resistors shown in the figure between the points $$A$$ and $$B$$ is:

A
$$2R$$

B
$$\displaystyle \frac {R}{4}$$

C
$$\displaystyle \frac {R}{2}$$

D
$$4R$$

Solution

$$\displaystyle R_{AB} = \frac {R}{4}$$
Question 5
1 / -0

Effective resistance between $$A$$ and $$C$$ is:

A
$$2 \Omega$$

B
$$6 \Omega$$

C
$$9 \Omega$$

D
None

Solution

$$R_{eqv} = \dfrac{6}{3} = 2 \Omega $$
Question 6
1 / -0

Find the effective resistance, when $$1\Omega$$, $$10\Omega$$ and $$4\Omega$$ resistances are connected in series.

A
$$25\Omega$$

B
$$15\Omega$$

C
$$30\Omega$$

D
$$\frac {20}{27}\Omega$$

Solution

In a series combination of resistors, the equivalent resistance is given by-

$$R_{eq}=R_1+R_2+R_3+...$$

Here-

$$R_{eq}=1+10+4$$

$$\implies R_{eq}=15\Omega$$

Answer-(B)
Question 7
1 / -0

Calculate the electric current in the circuit shown.

A
$$1.5A$$

B
$$0.5A$$

C
$$2.5A$$

D
$$2A$$

Solution

Any current that passes through the $$10 \Omega$$ resistor also passes through $$5 \Omega$$, i.e., $$10\Omega$$ and $$5 \Omega$$ are connected in series. Their equivalent resistance is $$R_{eq} = 10 \Omega + 5 \Omega = 15 \Omega$$.

The equivalent circuit is shown in the above figure.
The current $$\displaystyle i = \frac {V}{R_{eq}}=\frac {7.5 V}{15 \Omega}=0.5A$$
Question 8
1 / -0

Some matters do not allow the electricity to pass through it. What is called a matter which does not allow the electricity to pass though it?

A
Conductor

B
Insulator

C
Semiconductor

D
All of these

E
None of these

Solution

Substances which do not allow electricity to pass through them are called insulators.Examples: Mica,Plastic.
Question 9
1 / -0

$$1$$ ampere is same as ______.

A
$$1 Cs^{-1}$$

B
$$1 Cs$$

C
$$1 JC^{-1}$$

D
$$1 VC^{-1}$$

Solution

$$1$$ ampere $$(A)$$ is defined as the current when $$1$$ coulomb $$(C)$$ of charge passes a given cross section in $$1$$ second $$(s)$$.

$$1 \ A=\dfrac{1 \ C}{1 \ s}=1Cs^{-1}$$

Answer: (A)
Question 10
1 / -0

SI unit of current is :

A
Ampere

B
Volt

C
Watt

D
Hertz

E
None of these

Solution

The SI unit of electric current is the ampere (A), or amp, which is the flow of electric charge across a surface at the rate of one coulomb per second.

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Re-Attempt Weekly Quiz Competition

Electricity Test - 48

Result

Electricity Test - 48

Score

-

Rank

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SHARING IS CARING

Question 1

15

20

30

40

Solution

Question 2

nR

n/R

R/n

$$nR-\frac {n}{R}$$

Solution

Question 3

1

0.6

0.3

2

Solution

Question 4

$$2R$$

$$\displaystyle \frac {R}{4}$$

$$\displaystyle \frac {R}{2}$$

$$4R$$

Solution

Question 5

$$2 \Omega$$

$$6 \Omega$$

$$9 \Omega$$

None

Solution

Question 6

$$25\Omega$$

$$15\Omega$$

$$30\Omega$$

$$\frac {20}{27}\Omega$$

Solution

Question 7

$$1.5A$$

$$0.5A$$

$$2.5A$$

$$2A$$

Solution

Question 8

Conductor

Insulator

Semiconductor

All of these

None of these

Solution

Question 9

$$1 Cs^{-1}$$

$$1 Cs$$

$$1 JC^{-1}$$

$$1 VC^{-1}$$

Solution

Question 10

Ampere

Volt

Watt

Hertz

None of these

Solution

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