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Electricity Test - 76

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Electricity Test - 76
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  • Question 1
    1 / -0
    In the adjoining figure the equivalent resistance between $$A$$ and $$B$$ is

    Solution
    We are given circuit, we have to calculate equivalent between A and B. 
    Clearly in 2nd fig.
    2, 2 and 2 are in series
    So, $$R_1 = 2 + 2 + 2$$
    $$= 6\Omega$$
    Now, $$6\Omega$$ and $$6\Omega$$ are in parallel
    $$\therefore R_2 = \dfrac{6\times 6}{12} = 3\Omega$$
    Now, Equivalent Resistance ($$R_{AB}$$) = 1 + 3 + 1
    $$= 5\Omega$$
    Hence option A is correct. 

  • Question 2
    1 / -0
    Three equal resistors are connected as shown in figure. the maximum power consumed by each resistor is 18 W. Then the maximum power consumed by the combination is :

    Solution
    equivalent resistance from $$A\rightarrow B$$

    $$\boxed{(R\parallel R)+R}$$

    $$\Rightarrow \dfrac{1}{\dfrac{1}{R}+\dfrac{1}{R}}+R=\dfrac{1}{\dfrac{2}{R}}+R=\dfrac{R}{2}+R$$

    $$=\dfrac{3R}{2}$$

    $$\therefore$$ equivalent resistance $$=\dfrac{3R}{2}$$
    Power across the single resistor $$=18\ W$$ ( given)

    $$P=i^2R=18\ W.......(1)$$

    Power across the equivalent circuit is

    $$P_1=i^2\times \dfrac{3R}{2}=\dfrac{3i^2R}{2}\rightarrow .....(2)$$

    dividing $$(1)$$ by $$(2)$$

    $$\dfrac{P}{P_1}=\dfrac{18}{P_1}=\dfrac{i^2R}{\dfrac{3i^2R}{2}}=\dfrac{2}{3}$$

    $$\Rightarrow P_1=\dfrac{3}{2}\times 18=27\ W$$   
    $$\therefore$$ maximum power consumed by circuit $$=27\ W$$

  • Question 3
    1 / -0
    Effective resistance between $$A$$ and $$B$$ is

    Solution

  • Question 4
    1 / -0
    As we continue to flow the current through the human body then
    Solution
    As we continue to flow the current through the human body, the potential difference increases so from Ohm's law ( V= IR) the resistance of the body gradually decreases.
  • Question 5
    1 / -0
    A hollow cylinder $$(\rho =2.2\times 10^{-8}\Omega -m)$$ of length 3m has inner and outer diameter as 2mm and 4mm respectively. The resistance of the cylinder is  
    Solution
    outer radii$$=2=R$$
    inner radii$$1=r$$
    $$l=3m$$
    $$p=2.2\times 10^{-8}\Omega-m$$
    $$resistance=resistivity\left(\dfrac{lenght}{area}\right)$$
    Area of hollow cylinder$$=\pi(R^2-r^2)$$
    $$=\pi (2^{ 2 }-1^{ 2 })=3.14\times 3\times 10^{ -6 }=9.42\times { 10 }^{ -6 }$$

    $$R=2.2\times 10^{ -8 }\left[ \dfrac { 3 }{ 9.42\times { 10 }^{ -6 } }  \right] $$
    $$R=0.7\times 10^{-2}\Omega$$ 
    $$R=7\times 10^{-3}\Omega$$ 
  • Question 6
    1 / -0
    In the following circuit, what is equivalent resistance between A and B points?

    Solution

  • Question 7
    1 / -0
    In the circuit shown, when R has removed an additional resistance of  $$72\ \Omega $$ must be introduced in series with the battery in order to keep the current through $$30\ \Omega $$ resistance unaltered. Hence R is 

  • Question 8
    1 / -0
    The value of the resistance $$r$$ in the electric circuit given below is (in $$\Omega$$)

    Solution

  • Question 9
    1 / -0
    5 identical thin conducting plates are kept parallel to each other such that separation between each plate is d. Area of each plate is A. Plates are arranged as shown in figure. All wires are conducting.
    Switch S is closed, find the work done by battery. $$\left( A\succ \succ \succ { d }^{ 2 } \right) $$

    Solution

  • Question 10
    1 / -0
    In the given circuit (as shown in the figure), choose the wrong statement.

    Solution

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