Self Studies

Electricity Test - 8

Result Self Studies

Electricity Test - 8
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    A stream of electrons moving through a conductor constitutes a _______.

    Solution

    A stream of electrons moving through a conductor constitutes an Electric current.

    The Direction of electric current is opposite to the direction of flow electrons.

  • Question 2
    1 / -0

    “The potential difference across the ends of a resistor is directly proportional to the current through it, provided its temperature remains the same”.

    The above is the statement of which of the following law?

    Solution

    The Ohm’s law states that “The potential difference across the ends of a resistor is directly proportional to the current through it, provided its temperature remains the same”.

  • Question 3
    1 / -0

    The resistance of the conductor is independent of _____.

    Solution

    The resistance of the conductor depends upon

    1) The resistivity of the material of the conductor.

    2) The length of the conductor

    3) The area of cross-section of the conductor

  • Question 4
    1 / -0

    Which of the following is used as heating filament in electric toasters?

    Solution

    Nichrome is an alloy of Nickel, Chromium, manganese and iron. The alloy does not oxidise readily at high temperature.

    Thus, Nichrome is used as heating element in electric toaster.

  • Question 5
    1 / -0

    The current drawn by an electric bulb from a 220 V source, if the resistance of the bulb filament is 1200 Ω.

    Solution

    The resistance of the bulb is 1200Ω

    The voltage applied by the source is 220V

    Applying the ohm’s, we get

    Voltage, V=IR

    Where

    I is the current

    R is the resistance

    Putting the values in the above formula, we get

    220 V= 1200Ω × I

    Solving For I, we get

    I=0.18 A

  • Question 6
    1 / -0

    An electric heater of resistance 200Ω takes a current of 2A.

    The heal developed in 30 sec is ________.

    Solution

    Given:

    The resistance of the electric heater, R= 200Ω

    The current in the circuit, I =2A

    Time period, t = 30 sec

    Formula used:

    Heat transferred, H= I2 RT

    Where

    I is the current

    R is the resistance

    T is the time period

    Putting the values in the above equation, we get

     

    H= 22 × 200× 30 sec=24,000 J= 24 KJ

  • Question 7
    1 / -0

    The commercial unit of electrical energy is __________.

    Solution

    The commercial unit of electrical energy is kilowatt hour (kWH)

    1 kWh=3,600,000 J=3.6 × 106 J

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now