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Periodic Classification of Elements Test - 23

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Periodic Classification of Elements Test - 23
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  • Question 1
    1 / -0
    Atomic wt. of P is 31 and Sb is 120. What will be the atomic wt. of As, as per Dobernier triad rule?
    Solution
    Atomic wt. of P is 31 and Sb is 120. The atomic wt. of As, as per Dobernier triad rule will be average of two. It will be $$\displaystyle \frac {31+120}{2} = \frac {151}{2} =75.5 $$
  • Question 2
    1 / -0
    How does number of valence electrons vary on moving from left to right In the first period of a periodic table?
    Solution
    On moving from left to right in any period valence electrons keeps on increasing and period gets over when that valence shell gets filled. Even in the first period it has only 2 elements as in that shell only 2 electrons can be fit. In hydrogen, it has one electron in valence shell where as in the next atom that is helium it has 2 electrons in valence shell completing the period.
  • Question 3
    1 / -0
    Which of the following elements is a metalloid?
    Solution

    Hint: Metalloids are present in the $$p$$ block which separates metals from nonmetals.

    Explanation :

    ·       Metalloids depict properties intermediate between metals and non-metals.

    ·       The six metalloids are known as boron ($$B$$), silicon ($$Si$$) , germanium ($$Ge$$) , arsenic ($$As$$) , and tellurium ($$Te$$).

    ·       They also form alloys with metals.

    ·      Tin ($$Sn$$), Aluminium ($$Al$$), Znic ($$Zn$$) are metals.

    Correct Option: $$C$$.

  • Question 4
    1 / -0
    If A, B and C are the three elements of Dobereiner's triad and atomic weights of A and B are 7 and 15 respectively, then the atomic weight of C is :
    Solution
    According to Dobreiner's triad, the atomic mass of the central element (B) is the arithmetic mean of the atomic masses of the other two elements (A and C ).

    Given that: $$A=7,\ B=15$$

    Let the mass of $$C$$ be $$M_C$$.

    $$M_B = \dfrac{M_A + M_C}{2}$$

    $$ 15= \dfrac { 7+M_c }{2  } $$

    $$\Rightarrow M_ C=23$$.
  • Question 5
    1 / -0
    Which of the following is the correct match?
    (a) Eka silicon - $$\text{Ge}$$
    (b) Eka aluminum - $$\text{Ga}$$
    (c) Eka manganese - $$\text{Tc}$$
    (d) Eka boron - $$\text{Sc}$$
    Solution
    Eka is a prefix used to designate the first element of the same family in the periodic table beyond the one to whose name it is prefixed, as Eka manganese

    (a) Eka silicon - Ge (germanium)

    (b) Eka aluminium - Ga (gallium )

    (c) Eka manganese - Tc (technetium) 

    (d) Eka boron – Sc (scandium)

    Hence, the correct option is $$\text{D}$$
  • Question 6
    1 / -0
    Who was the first to classify the elements into metals and non-metals?
    Solution
    Antoine Lavoisier first classified the elements into different categories based on their chemical and physical properties. These categories of elements include metals, nonmetals and metalloids, and noble gases.
    Hence, option C is correct.
  • Question 7
    1 / -0
    Which of the following has maximum non-metallic character?
    Solution
    F has maximum non-metallic character among the given non-metals.
  • Question 8
    1 / -0
    Which of the following pairs of elements does not follow the Law of Octaves?
    Solution
    The Law of Octaves states that when the elements are arranged in increasing order of their atomic masses, the properties of every eighth element are similar to that of the first. 

    If we observe this arrangement (as shown below), Na and K, F and Cl, and O and S follow the Law of Octaves. Ca and Sr do not follow the rule (Sr is not the eighth element after Ca).

    HLiBeCNO
    FNaMgAlSiPS
    ClKCaCrTiMnFe
    Co/NiCuZnInAsSe
    BrRbSrCe/LaZr --
  • Question 9
    1 / -0
    According to Mendleev's periodic law which properties of the elements are the periodic function of their atomic masses?
    Solution
    According to Mendeleev's periodic law physical and chemical properties both of the elements are the periodic function of their atomic masses
  • Question 10
    1 / -0
    On moving from top to bottom in a group in the periodic table, valency:
    Solution
    On moving from top to bottom in a group in the periodic table, valency remains same.
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