Differentiation Test 8

Result

Differentiation Test 8

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Weekly Quiz Competition

Question 1
1 / -0

abc_bc_c_

A
acbbab

B
aabbca

C
aabacb

D
aababc

Solution

Pattern is abc/abc/abc/abc
Question 2
1 / -0

aa_b_abb___bb

A
abaa

B
bbaa

C
baaa

D
baba

Solution

Pattern is aa/bb/aa/bb/aa/bb
Question 3
1 / -0

Find the missing letters
B E I N T.........

A
A

B
S

C
U

D
V

Solution

Sequence is the given series is moving forward with +2, +3, +4, +5, +6 and so on steps
i.e.
Question 4
1 / -0

On the eve of Diwali festival, a group of 12 friends greeted every other friend by sending greeting cards. Find the number of cards purchased by the group.

A
156

B
144

C
132

D
72

E
66

Solution

There being 12 friends in the group, each friend must have purchased (12 - 1) i.e. 11 cards for sending greeting to rest of his 11 friends. Thus total number of cards purchased by all the friends together is 12 x 11 i.e. 132. '
Question 5
1 / -0

aab....aaa......bba.....

A
baa

B
abb

C
bab

D
bbb

Solution

1 First blank space should be filled in by 'b' so that we have two a's followed by two b's
2 Second blank space should be filled in either by 'a' so that we have four a's followed by two b's or by 'b' so that we have three a's followed by three b's
3 Last space must be filled in by 'a'
4 Thus we have two possible answer : 'baa' and 'bba' But only 'baa' appears in the alternatives So the answer is (a).
5 In case we had both the possible answer in the alternatives we would have chosen the one that forms a more prominent pattern which is aabb/aaabbb/aa Thus our answer would have been "bba"
Question 6
1 / -0

aba_baca_ba_bacaabac_aca

A
cacb

B
ccab

C
cabc

D
abcc

Solution

Pattern is abac/baca/abac/baca/abac/baca
Thus the pattern abac,baca is repeated
Question 7
1 / -0

If the area of the triangle formed by the points $$(-2,3), (4,-5)$$ and $$(-3,y)$$ is 10 square units then $$y =$$

A
$$\dfrac{19}{3}$$

B
$$\dfrac{21}{3}$$

C
$$\dfrac{23}{3}$$

D
$$\dfrac{25}{3}$$

Solution

Area of triangle having vertices $$(x_1,y_1), (x_2,y_2)$$ and $$(x_3,y_3)$$ is given by
$$ = \dfrac{1}{2} \times [ x_1 (y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) ] $$
$$\displaystyle \text{Area} =\frac{1}{2}\left [ -2\left ( -5-y \right )+4\left ( y-3 \right )-3\left ( 3+5 \right ) \right ]$$
$$\displaystyle =\frac{1}{2}\left ( 10+2y+4y-12-24 \right )$$
$$\displaystyle =\frac{1}{2}\left ( 6y-26 \right )=3y-13$$
$$\displaystyle 3y-13=10\ \mathrm{sq. unit}$$
$$\displaystyle y=\frac{23}{3}$$
Question 8
1 / -0

How many numbers are there between 500 and 600 in which 9 occurs only once?

A
19

B
18

C
10

D
9

Solution

509 , 519 , 529 , 539 , 549 , 559 , 569 , 579 , 589 , 590 , 591 , 592 ,

593 , 594 , 595 , 596 , 597 , 598 ...as 9 has to be occurred only once

so 599 would not be there so only 18 numbers are there.
Question 9
1 / -0

How many numbers of four digits can be formed from the digits 0, 1, 2, 3, and 4?

A
48

B
64

C
96

D
100

Solution

The first box can be filled in four ways, because we cannot put 0 in the first box. The second box can also be filled in four ways, because we cannot put 0. The third box can be filled in three ways and the fourth in two ways. Therefore,
Total numbers = $$\displaystyle 4\times 4\times 3\times 2=96$$
Question 10
1 / -0

A car driver knows four different routes from Delhi to Amritsar. From Amritsar to Pathankot, he knows three different routes and from Pathankot to Jammu he knows two different routes. How many routes does he know from Delhi to Jammu?

A
4

B
8

C
12

D
24

E
36

Solution

The car driver can reach Amritsar in 4 ways.From each of these four ways, he can reach Pathankot in 3 different ways and so he can reach from Delhi to Pathankot in $$\displaystyle \left( 4\times 3 \right) $$ i.e 12 ways. Again from Pathankot to Jammu, there are 2 ways. Hence he can reach Jammu from Delhi in $$\displaystyle \left( 12\times 2 \right) $$ i.e. in 24 ways.

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Re-Attempt Weekly Quiz Competition

Differentiation Test 8

Result

Differentiation Test 8

Score

-

Rank

-

SHARING IS CARING

Question 1

acbbab

aabbca

aabacb

aababc

Solution

Question 2

abaa

bbaa

baaa

baba

Solution

Question 3

A

S

U

V

Solution

Question 4

156

144

132

72

66

Solution

Question 5

baa

abb

bab

bbb

Solution

Question 6

cacb

ccab

cabc

abcc

Solution

Question 7

$$\dfrac{19}{3}$$

$$\dfrac{21}{3}$$

$$\dfrac{23}{3}$$

$$\dfrac{25}{3}$$

Solution

Question 8

19

18

10

9

Solution

Question 9

48

64

96

100

Solution

Question 10

4

8

12

24

36

Solution

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