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Sequences and Series Test 11

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Sequences and Series Test 11
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  • Question 1
    1 / -0
    $$10,20,40,80$$ is an example of
    Solution
    $$10, 20, 40, 80$$ is an example of geometric sequence.
    In geometric sequence, the ratio of succeeding term to the preceeding term is always equal.
    Here the common ratio is $$2$$.
  • Question 2
    1 / -0
    The geometric sequence is also called as
    Solution
    The sequence is also called as progression.
    So, the geometric sequence can be called as the geometric progression.
  • Question 3
    1 / -0
    A progression of the form $$a, ar, ar^2$$, ..... is a
    Solution
    A progression of the form $$a, ar, ar^2$$, ..... is a geometric progression.
    Geometric Progression refers to a sequence in which successor term of each term is obtained by multiplying a constant term.
  • Question 4
    1 / -0
    The number of terms in a sequence $$6, 12, 24, ....1536$$ represents a
    Solution
    Given sequence is $$6,12,24,....1536$$
    Since, $$\dfrac {12}{6} =2$$ and $$\dfrac {24}{12} =2$$
    i.e. the given sequence is a geometric sequence / progression. 
  • Question 5
    1 / -0
    $$4, \dfrac{8}{3}, \dfrac{16}{9}, \dfrac{32}{27}..$$ is a
    Solution
    lets check the ratio between the consecutive terms.
    $$\dfrac {\frac {8}{3}}{4}=\dfrac {8}{12}=\dfrac {2}{3}$$
    Again take the ratio between next consecutive terms.
    $$\dfrac {\frac {16}{9}}{\frac {8}{3}}=\dfrac {16\times 3}{9\times 8}=\dfrac {2}{3}$$
    Here the common ratio is same $$\dfrac{2}{3}$$ throughout.
    Hence, $$4, \dfrac{8}{3}, \dfrac{16}{9}, \dfrac{32}{27}..$$ is a geometric sequence.
  • Question 6
    1 / -0
    Identify the geometric progression.
    Solution
    A geometric sequence is a sequence of numbers such that the quotient of any two successive members of the sequence is a constant called the common ratio of the sequence.
    So, $$1, 3, 9, 27, 81...$$ is a geometric progression.
    Here the common ratio is $$3$$.
  • Question 7
    1 / -0
    A sequence of numbers such that the quotient of any two successive members of the sequence is a constant called the common ratio of the sequence is known as
    Solution
    A sequence of number, $${ a }_{ 1 }+{ a }_{ 2 }+......{ a }_{ n }$$ quotient of any two successive number is a constant,
    $$\cfrac { { a }_{ 2 } }{ { a }_{ 1 } } =\cfrac { { a }_{ 3 } }{ { a }_{ 2 } } =........=\cfrac { { a }_{ n } }{ { a }_{ n-1 } } =$$common ratio $$(r)$$
    So we can write
    $${ a }_{ 1 }+{ a }_{ 1 }r+{ a }_{ 2 }r+{ a }_{ 3 }r.......{ a }_{ n-1 }r\\ ={ a }_{ 1 }+{ a }_{ 1 }r+{ a }_{ 1 }{ r }^{ 2 }..........{ a }_{ n-2 }{ r }^{ 2 }$$
    and in the end in terms of $${ a }_{ 1 }$$
    $$={ a }_{ 1 }+{ a }_{ 1 }r+{ a }_{ 1 }{ r }^{ 2 }+{ a }_{ 1 }{ r }^{ 3 }.........{ a }_{ 1 }{ r }^{ n-1 }$$
    We can clearly say this series is in $$GP$$.
    Answer $$(D)$$
  • Question 8
    1 / -0
    The common ratio is used in _____ progression.
    Solution
    The common ratio is used in geometric progression.
    For example: $$2,4,8,16,....$$
    Here the common ratio is $$2$$.
  • Question 9
    1 / -0
    $$1, 3, 9, 27, 81$$ is a
    Solution
    $$1, 3, 9, 27, 81$$ is a geometric sequence.
    A geometric progression is a sequence of numbers such that the quotient of any two successive members of the sequence is a constant called the common ratio of the sequence.
  • Question 10
    1 / -0
    Which one of the following is a geometric progression?
    Solution
    $$4, -4, 4, -4, 4$$ is a geometric progression.
    Here the common ratio is $$-1$$.
    Option B is correct.
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