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Sequences and Series Test 29

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Sequences and Series Test 29
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  • Question 1
    1 / -0
    Choose the correct answer alternatives given.
    Select the missing number from the given alternatives.

    Solution
    80 = 8 $$\times$$ (8 + 2)
    143 = 11 $$\times$$ (11 + 2)
    323 = ? $$\times$$ (? + 2)
    $$\therefore$$ ? = 17
  • Question 2
    1 / -0
    If $$1^{3} + 2^{3} + .... + 10^{3} = 3025$$, then the value of $$2^{3} + 4^{3} + ..... + 20^{3}$$ is
    Solution
    Given that, $$1^{3} + 2^{3} + .... + 10^{3} = 3025$$
    Now, $$2^{3} + 4^{3} + .... + 20^{3}$$
    $$= 2^{3} (1 + 2^{3} + .... + 10^{3}) = 8\times 3025 = 24200$$.
  • Question 3
    1 / -0
    If $$12\times 16 = 188$$ and $$14\times 18 = 248$$, then find the value of $$16\times 20 = ?$$
    Solution
    $$12\times 16 = 192 - 4 = 188$$
    $$14\times 18 = 252 - 4 = 248$$
    $$16\times 20 = 320 - 4 = 316$$.
  • Question 4
    1 / -0
    How many different $$4$$-person committees can be chosen form the $$100$$ members of the Senate ?
    Solution
    Total number of members $$=100$$.
    Members has to be selected $$=4$$.
    $$\therefore$$ different committees $$=^{100}C_{4}=\large{\frac{100!}{4!\times96!}}$$ $$=3,921,225$$.
  • Question 5
    1 / -0
    Arrange these numbers in ascending order. 
    $$756, 567, 657, 676$$ 
    Solution
    $$\Rightarrow$$  Numbers are said to be in ascending order when they are arranged from the smallest to the largest number.
    $$\Rightarrow$$  The numbers which we have to arrange in ascending order are $$756,\,567,\,657$$ and $$676$$
    $$\Rightarrow$$  $$567<657<676<756$$
    $$\therefore$$  Ascending order $$=567,\,657,\,676,\,756$$
  • Question 6
    1 / -0
    The number of ways in which we can select 5 letters of the word INTERNATIONAL is equal to
    Solution
    We have thirteen letters.
    $$2l, 3N, 2T, 2A$$ and $$(E, O, L,R)8$$ (types)
    We can select 5(five) letters in the following manner:

    1. All different $${^8C}_5 = \dfrac{8.7.5}{1.2.3} = 56$$ ways

    2. 2 alike, 3 different $${^4C}_1 . {^7C}_3 = 435 = 140$$ ways (we have 4 sets of alike letters)

    3. 3 alike, 2 different $${^1C}_1 . {^7C}_2 = 1.21 = 21$$ ways (we have only one set of 3 alike)

    4. 3 alike and 2 alike $${^1C}_1 . {^3C}_1 = 1.3 = 3$$ ways

    5.Two sets of alike and one different 
    $${^4C}_2 . {^6C}_1 = 6.6 = 36$$ ways

    $$\therefore$$ Total number of selection is
    $$56 + 140 + 21 + 3 + 36 = 256$$ ways $$\Longrightarrow$$ (d)
  • Question 7
    1 / -0
    Statement I: The function f(x) in the figure is differentiable at x = a
    Statement II: The function f(x) continuous at x = a

    Solution
    $$f(x)$$ is continuous at as it can be observed from the figure there is no discontinuous at $$x=a$$ but coming to differentiability $$f(x)$$ is not differentiable at $$x=a$$ since the curve is sharp[i.e the left slope and right slope are not equal]
    therefore the answer is statement I is false but statement II is true
  • Question 8
    1 / -0

    The total number of different combinations of one
    or more letters which can be made from the letter of the word MISSISSIPPI is,

    Solution
    We have 1M, 4I ,4S , 2P
    Therefore total number of selection of one or more letters=(1+1)(4+1)(4+1)(2+1)-1=149
  • Question 9
    1 / -0

    The total number of non-negative integer n satisfying the
    equation $$ {n^2} = p + q\,and\,{n^3} = {p^2} + {q^2}$$, where p and q are
    integers, is

    Solution

  • Question 10
    1 / -0
    Number of arrangements of the letter $$HOLLYWOOD$$ in which all $$Os$$ are separated.
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