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Set Theory Test 6

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Set Theory Test 6
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Weekly Quiz Competition
  • Question 1
    1 / -0
    How many rural uneducated people are employed?

    Solution
    Rural uneducated people has been represented by $$'10'$$.
  • Question 2
    1 / -0
    If $$A=\left\{ 2,4\left\{ 5,6 \right\} ,8 \right\} $$, then which one of the following statements is not correct?
    Solution
    $$\left\{ 5,6 \right\} $$ is not the subset but is an element of $$A$$, $$\therefore$$ a is false.
  • Question 3
    1 / -0
    Upper limit of class $$'41 - 50'$$ is __________.
    Solution
    Upper Limit of class $$'41-50'=50$$
    Part (B) is correct answer.
  • Question 4
    1 / -0
    If $$A=\left\{a,b,c\right\},B=\left\{c,d,e\right\},C\left\{a,d,f\right\},$$ then $$A\times \left( B\cup C \right)$$ is
    Solution
    $$(d)$$.
    $$A\times \left( B\cup C \right) =\{ a,b,c\} \times \{ a,c,d,e,f\}$$
    The above set will consist of $$15$$ ordered pairs and not $$3$$.
  • Question 5
    1 / -0
    $$A$$ and $$B$$ are two sets having $$3$$ and $$5$$ elements respectively and having $$2$$ elements in common. Then the number of elements in $$A\times B$$ is
    Solution
    Total ordered pairs $$= n(A) \times n(B) = 3\times 5 = 15$$
  • Question 6
    1 / -0
    Let $$A$$ and $$B$$ have $$3$$ and $$6$$ elements respectively. What can be the minimum number of elements in $$A\cup B$$?
    Solution
    Ans. $$(b)$$.
    $$n\left( A\cup B \right) =n(A)+n(B)-n\left( A\cap B \right)$$
    Now $$A$$ has $$3$$ elements and $$B$$ has $$6$$ elements. If they are disjoint, then $$n\left( A\cap B \right) =0$$.
    $$\therefore n\left( A\cup B \right) =6+3=9$$
    If $$A\subset B$$ then $$A\cup B=B$$
    $$\therefore \left( A\cup B \right) =n(B)=6$$
    $$B$$ cannot be a subset of $$A$$ and hence the other possibility of $$A\cup B=A$$ is ruled out.
  • Question 7
    1 / -0
    For two sets $$A$$ and $$B$$, $$ A\cap \left( A\cup B \right)=$$
    Solution
    $$\left( A\cap A \right) \cup \left( A\cap B \right) =A\cup \left( A\cap B \right) =A$$
    $$\because A\cap B\subset A$$
  • Question 8
    1 / -0
    $$25$$ people for applied for programme $$A$$, $$50$$ people for programme $$B$$, $$10$$ people for both. So number of employee applied only for $$A$$ is
    Solution

    $$n(A - B) = n(A) - n(A \cap B) = 25 -10 -15$$
  • Question 9
    1 / -0
    If $$P(A) = 0.8 , P(B) = 0.5 $$ & $$P(B/A) =0.4 $$ find (i) $$P(A \cap B) $$ (ii) $$P(A/B)$$ (iii) $$P(A\cup B)$$.
    Solution

    $$\\\>P(\frac{B}{A})=\>\frac{P(B\>\cap\>A)}{P(A)}\\\>0.4=\frac{P(B\cap\>A)}{0.8}\\$$

    $$\therefore\>P(B\cap\>A)=0.32\\$$, $$\implies \>P(A\cap\>B)=0.32\\$$

    $$then\>\>P(\frac{A}{B})=\>\frac{P(A\>\cap\>B)}{P(B)}=(\frac{0.32}{0.5})=0.64\>\\$$

    $$and\>P(A\cup\>B)=P(A)+P(B)-P(A\cap\>B)\\=0.8+0.5-0.32\\\>=0.98$$

  • Question 10
    1 / -0
    Let $$A$$ is a finite set such that $$n(A)=6$$ then  $$n[P(A)]$$ is 
    Solution
    We have if a set contains $$n$$ element then its power set contains $$2^n$$ elements.
    In our problem $$n=6$$.
    Then $$n[P(A)]=2^6=64$$.
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