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Relations Test 5

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Relations Test 5
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  • Question 1
    1 / -0
    Let R be the set of real numbers and the mapping $$f:R\rightarrow R$$ and $$g:R\rightarrow R$$ be defined by $$f(x)=5-x^2$$ and $$g(x)=3\lambda-4$$, then the value of $$(fog)(-1)$$ is
    Solution
    Given, $$f(x)=5-x^2,\,g(x)=3x-4$$
    Now, $$(fog)(-1)=f\begin{Bmatrix}g(-1)\end{Bmatrix}$$
    $$=f(-7)\;[\because\;g(-1)=3(-1)-4=-7]$$
    $$=5-(-7)^2$$
    $$=-44$$
  • Question 2
    1 / -0
    Let the number of elements of the sets $$A$$ and $$B$$ be $$p$$ and $$q$$ respectively. Then, the number of relations from the set $$A$$ to the set $$B$$ is
    Solution
    Given, number of elements of $$A$$ and $$B$$ are $$p$$ and $$q$$ respectively.
    $$\therefore$$ The number of relations from the set $$A$$ to the set $$B$$ is $${2}^{pq}$$.
  • Question 3
    1 / -0
    Let $$A = \left \{x, y, z\right \}$$ and $$B = \left \{p, q, r, s\right \}$$. What is the number of distinct relations from $$B$$ to $$A$$?
    Solution
    Since, No. of elements in set A$$=3$$
               No. of elements in set B$$=4$$
    $$\therefore$$ No. of elements in B$$\times$$A$$=3\times 4=12$$
    $$\therefore$$ No. of distinct relations from B to A $$= 2^{12}=4096$$
    Option A is correct.
  • Question 4
    1 / -0
    Let R be the relation in the set N given by = {(a, b): a = b - 2, b > 6}. Choose the correct answer
    Solution
    Firstly b should be greater than 6 & also difference between b& a should be 2 , option C is satisfing both the conditions hence the correct answer is C
  • Question 5
    1 / -0
    Let A be a finite set containing n distinct elements. The number of relations that can be defined on A is.
  • Question 6
    1 / -0
    On the set $$N$$ of all natural numbers define the relation $$R$$ by $$a R b$$ if and only if the G.C.D. of $$a$$ and $$b$$ is $$2$$. Then $$R$$ is:
    Solution
    $$aRa$$ only if GCD of a and a is 2 which is clearly not the case.
    Hence not reflexive.

    $$aRb \Rightarrow bRa$$ if GCD of a and b is 2 then GCD of b and a is also 2.
    The relation is symmetric.

    Transitiveness is not necessary,i.e, if and b have GCD 2 and b and c also have GCD 2 a and c need not have GCD 2.


    The relation is symmetric only.
  • Question 7
    1 / -0
    Consider two sets $$A=\{a, b, c\}, B=\{e, f\}$$. If maximum numbers of total relations from A to B; symmetric relation from A to A and from B to B are $$l, m, n$$ respectively, then the value of $$2l+m-n$$ is
    Solution
    We have $$n(A)=3$$ and $$n(B)=2$$.
    Now cartesian product of $$A$$ and $$B$$ can contain maximum $$3\times 2=6$$ elements.
    Since relation is the possible subsets of cartesian product.
    So maximum number of relations from $$A$$ to $$B$$ be $$(l)=2^{6}=64$$.
    Now maximum possible symmetric relation from $$A$$ to $$A$$ be $$(m)=2^{\cfrac{3(3+1)}{2}}=2^6=64$$ and that of from $$B$$ to $$B$$ be $$(m)=2^{\cfrac{2(2+1)}{2}}=2^3=8$$. [Using formula for number of symmetric relation]
    Now $$2l+m-n=128+64-8=184$$.
  • Question 8
    1 / -0
    The number of reflexive relation in set A = {a, b, c} is equal to
    Solution
    $$\therefore$$ Total number of relation in set A $$2 ^{3 \times  3} = 2^9$$
    and maximum number of cartesian product = 9 out of which 3 ordered pair is necessary for reflexive.
    So, for remaining 6 ordered pair 
    Number of ordered pair required.$$=^6 C _0\, +\, ^6C_1 \,+ \,  ^6C_2 +......^6C_6$$ =$$ 2^6 $$
  • Question 9
    1 / -0
    If the relation is defined on $$R-\left\{ 0 \right\} $$ by $$\left( x,y \right) \in S\Leftrightarrow xy>0$$, then $$S$$ is ________
    Solution
     $$s\Leftrightarrow xy$$
    for (x,x) on relation
     $$s\Leftrightarrow xy$$
    and $$x^2>0$$
    so, $$S$$ is symmetric
    if $$xy>0$$
    thus $$xy>0$$
    so, $$S$$ is reflexive.
    Now, if $$xy>0$$
    and $$yz>0$$
    so, $$xz>0$$
    Thus, $$S$$ is transitive.
    So, relation is equivilance.

  • Question 10
    1 / -0
    Let $$A=\left\{ u,v,w,z \right\} ;B=\left\{ 3,5 \right\} $$, then the number of relations from $$A$$ to $$B$$ is
    Solution
    Given
    $$A=\left\{ u,v,w,z \right\} ;B=\left\{ 3,5 \right\} $$
    Here, number of element in set $$A$$ is $$n(A)=4$$
    And number of element in set $$B$$ is $$ n(B)=2$$
    $$\therefore$$ Number of relations from $$A$$ to $$B$$
    $$={ 2 }^{ n(A).n(B) }={ 2 }^{ 4\times 2 }={ 2 }^{ 8 }=256$$
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