Numerical Applications Test 42

Result

Numerical Applications Test 42

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

A completes half as much work as B and C completes half as much work as A and B together, in the same time. If C alone can completes the work in 40 days, all of them can together finish the work in

A
13 $$\dfrac{1}{3}$$ days

B
14 $$\dfrac{1}{3}$$ days

C
20 days

D
30 days

Solution

Given that,
$$\displaystyle A \, = \, \dfrac{1}{2} \, \times \, B \, \Rightarrow \, \frac{A}{B}= \, \dfrac{1}{2}$$
A : B = 1 : 2 or B : A = 2 : l
Also, given that
$$C= \, \dfrac{1}{2} \, \times \, (A \, + \, B)$$
$$C= \, \dfrac{1}{2} \, \times \, (A \, + \, 2A)$$
C = $$\dfrac{3}{2}$$ A
C : A = 3 : 2 or A : C = 2 : 3
From equation (1) & (2), we get
B : A: C = 4 : 2 : 3 or A : B : C = 2 : 4 :3
Time taken to do the work $$\displaystyle \, \frac{1}{work \, done}$$

Hence $$\displaystyle t_A \, : \, t_B \, : \, t_C \, = \, \frac{1}{2} \, : \, \frac{1}{4} \, : \, \frac{1}{3}$$ or 6 : 3 :4
Now, $$t_C$$ = 40
$$t_A$$ = 60
$$t_B$$ = 30
Let the work be 120. [LCM of 40, 60, 30]
A does $$\displaystyle A does \, = \, \frac{120}{60} \, = \, 2$$ units/day

B does $$\displaystyle B does \, = \, \frac{120}{30} \, = \, 4$$ units/day

C does $$\displaystyle C does \, = \, \frac{120}{40} \, = \, 3$$ units/day
Together they do the work in = $$\displaystyle \frac{120}{2 \, + \, 4 \, + \, 3} \, = \, \frac{120}{9} \, = \, \frac{40}{3} \, = \, 13 \, \frac{1}{3}$$ days
Question 2
1 / -0

A, B and C can do a piece of work in 11 days, 20 days and 55 days respectively, working alone. How soon can the work he done if A is assisted by B and C on alternate days?

A
7 days

B
8 days

C
9 days

D
10 days

Solution

Let the total work be 220 units (LCM of 11, 20 & 55).
A does =$$\cfrac{220}{11}$$ = 20 units / day
B does = $$\cfrac{220}{20}$$ = 11 units / day
C does =$$\cfrac{220}{55}$$=4 untis /day
according to the question,
(A + B) + (A + C) + (A + B) + (A + C) + .........
(20 + 11) +(20 + 4) + (20 + 11) + (20 + 4) +.
In 2 days, work get completed = 55 units.
55 units of work completed in 2 days.
220 units of work completed in
= $$\cfrac{2}{55} \times 220 = 2 \times 4$$ = 8days.
Question 3
1 / -0

A manufacturer built a machine which will address 500 envelops in 8 minutes. He wishes to build another machine so that when both are operating together they will address 500 envelops in 2 minutes. The equation used to find how many minutes x it would require the second machine address 500 envelopes alone is:

A
8 - x = 2

B
$$\frac{1}{8}+ \frac{1}{x}= \frac{1}{2}$$

C
$$\frac{500}{8} + \frac{500}{x} = 500$$

D
$$\frac{x}{2}+\frac{x}{8}= 1$$

E
None of these

Solution

Since the first machine addresses 500 envelopes in 8 minutes, it addresses 500/s envelopes in 1 minute and 2. 500/8 in 2 minutes. If the second machine addresses 500 envelopes in x minutes, then it addresses. 500/envelopes in 2 minutes. To determine x so that both machines together address 500 envelopes in 2 minutes we use the condition
$$500\frac{2}{x}.500 = 500 $$ or $$ \frac{500}{8}+ \frac{500}{x}= 250$$
or $$\frac{1}{8} + \frac{1}{x} = \frac{1}{2}$$
Question 4
1 / -0

If m men can do a job in d days, then m + r men can do the job in:

A
d + r days

B
d - r days

C
$$\frac{md}{m + r}$$ days

D
$$\frac{d}{m+r}$$ days

Solution
Question 5
1 / -0

A contractor deploys 36 men on a work and in 16 days they complete $$\dfrac{2}{3}$$rd of the work. To finish the remaining work he deploys 12 men extra. Now the remaining work will be completed in

A
7

B
6

C
9

D
3

Solution

Given that,
36 men working 16 days completed of $$\dfrac{2}{3} $$ work.
i.e. 36 $$\times$$ 16 men days = $$ \dfrac{2}{3} $$work

576 men days = $$ \dfrac{2}{3} $$ work
Total work = 864 men days
Work completed = 864 - 576 = 288 men days.
According to the question,
(36+ 12) men $$\times $$ x days = 288 men days
48 men $$\times$$ x days = 288 men days
x days = $$\dfrac{288}{48}$$ = 6 days
Hence, in another 6 days work will be completed.
Question 6
1 / -0

If $$20$$ men working $$8$$ hours per day can complete a piece of work in $$21$$ days. How many hours per day must $$48$$ men work to complete the same job in $$7$$ days

A
$$12$$

B
$$20$$

C
$$10$$

D
$$15$$

Solution

We know, Work = Men $$×$$ hr/day×days

Work is same in both cases

Let $$48$$ men will complete the same work in $$x$$ hr/day

$$20×8$$ hr/day $$×21=48×x$$ hr/day $$×7$$

$$48x=\dfrac{(20×8×21)}7$$

$$48x=20×8×3$$

$$x=\dfrac{(20×8×3)}{48}$$

$$x=\dfrac{480}{48}$$

$$x=10$$

$$48$$ men must work $$10$$ hr/day to complete the same work in $$7$$ days
Question 7
1 / -0

The number of permutations of the letters of the word $$HONOLULU$$ taken $$4$$ at a time is

A
$$ 354$$

B
$$ 314$$

C
$$ 210$$

D
$$ 124$$

Solution

$$H-1$$
$$N-1$$
$$O-2$$
$$L-2$$
$$U-2$$
Number of permutation $$=\dfrac {n!}{r_1\times r_2\times....\times r_n} =\dfrac { 8! }{ { (2! })^{ 3 }4! } =210$$
Question 8
1 / -0

Khilona earned scores of $$97$$, $$73$$ and $$88$$ respectively in her first three examinations. If she scored $$80$$ in the fourth examination, then her average score will be

A
increased by $$1$$

B
increased by $$1.5$$

C
decreased by $$1$$

D
decreased by $$1.5$$

Solution

When earned scores are $$97,73,88$$ then
Average $$=\dfrac{97+73+88}{3}\Rightarrow 86.$$

When $$80$$ is added in the score list then
Average $$=\dfrac{97+73+88+80}{4}\Rightarrow 84.5$$

Hence, the average is decreased by $$1.5.$$
Question 9
1 / -0

The total number of different combinations of one
or more letters which can be made from the letter of the word MISSISSIPPI is,

A
$$150$$

B
$$148$$

C
$$149$$

D
$$146$$

Solution

We have 1M, 4I ,4S , 2P
Therefore total number of selection of one or more letters=(1+1)(4+1)(4+1)(2+1)-1=149
Question 10
1 / -0

Number of arrangements of the letter $$HOLLYWOOD$$ in which all $$Os$$ are separated.

A
$$360\ ^{ 7 }{ C }_{ 3 }$$

B
$$15\ ^{ 7 }{ P }_{ 4 }$$

C
$$15\ ^{ 7 }{ C }_{ 4 }$$

D
$$30\ ^{ 7 }{ P }_{ 4 }$$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Numerical Applications Test 42

Result

Numerical Applications Test 42

Score

-

Rank

-

SHARING IS CARING

Question 1

13 $$\dfrac{1}{3}$$ days

14 $$\dfrac{1}{3}$$ days

20 days

30 days

Solution

Question 2

7 days

8 days

9 days

10 days

Solution

Question 3

8 - x = 2

$$\frac{1}{8}+ \frac{1}{x}= \frac{1}{2}$$

$$\frac{500}{8} + \frac{500}{x} = 500$$

$$\frac{x}{2}+\frac{x}{8}= 1$$

None of these

Solution

Question 4

d + r days

d - r days

$$\frac{md}{m + r}$$ days

$$\frac{d}{m+r}$$ days

Solution

Question 5

7

6

9

3

Solution

Question 6

$$12$$

$$20$$

$$10$$

$$15$$

Solution

Question 7

$$ 354$$

$$ 314$$

$$ 210$$

$$ 124$$

Solution

Question 8

increased by $$1$$

increased by $$1.5$$

decreased by $$1$$

decreased by $$1.5$$

Solution

Question 9

$$150$$

$$148$$

$$149$$

$$146$$

Solution

Question 10

$$360\ ^{ 7 }{ C }_{ 3 }$$

$$15\ ^{ 7 }{ P }_{ 4 }$$

$$15\ ^{ 7 }{ C }_{ 4 }$$

$$30\ ^{ 7 }{ P }_{ 4 }$$

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.