Numerical Applications Test 46

Result

Numerical Applications Test 46

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Find $$x$$, if $$\dfrac {1}{4!}-\dfrac {1}{x}=\dfrac {1}{5!}$$.

A
$$5$$

B
$$4$$

C
$$30$$

D
$$None$$

Solution
Question 2
1 / -0

$$A$$ and $$B$$ can complete a task in $$12$$ days. However, $$A$$ had to leave a few days before the task was complete and hence it took $$16$$ days in all to complete task. If $$A$$ alone could complete the work in $$21$$ days, how many days before the work getting over did $$A$$ leave?

A
$$7$$

B
$$9$$

C
$$5$$

D
$$0$$

Solution

B can alone do the work
$$=\dfrac{1}{\dfrac{1}{12}-\dfrac{1}{21}}$$ days

$$\implies \dfrac 1B = \dfrac{7-4}{84}=\dfrac{3}{84} = \dfrac1{28}$$

$$=28$$ Days

Let $$A$$ worked $$X$$ days, So

Work done by $$A+$$ Work done by $$B =1$$

$$\dfrac{X}{21} +\dfrac{16}{28} =1$$

$$\implies \dfrac{X}{21} = \dfrac{12}{28}$$

$$\implies X=9$$

Hence, $$A$$ worked for $$9$$ days means $$A$$ left work before $$( 16-9)= 7$$ days of completion.
Question 3
1 / -0

A takes $$5$$ days less than $$B$$ to complete the work. Both complete the work in $$6$$ days. In how many days $$A$$ complete the work?

A
$$10$$

B
$$15$$

C
$$20$$

D
$$30$$

Solution

From given, we have,

$$\dfrac{1}{x}+\dfrac{1}{x+5}=\dfrac{1}{6}$$

$$6\left(x+5\right)+6x=x\left(x+5\right)$$

$$x^2+5x-30=12x+30-30$$

$$x^2-7x-30=0$$

$$(x-10)(x+3)=0$$

$$\therefore x=-3,10$$

Days can't be negative.

Therefore, the number of days A uses to complete the work is $$10$$ days.
Question 4
1 / -0

Ram and Shyam together can do a work in $$16$$ days. Shyam takes twice time as Ram takes to do the same work. In how many days Shyam alone can complete that work?

A
$$16$$ days

B
$$32$$ days

C
$$24$$ days

D
$$40$$ days

E
$$48$$ days

Solution

Given,

Shyam+Ram=Shyam-Ram

$$\Rightarrow \dfrac{1}{2x}+\dfrac{1}{x}=\dfrac{1}{16}$$

$$8+16=x$$

$$\therefore x=24$$

Total days Shyam takes to complete work $$=2x=2\times 24=48$$ days
Question 5
1 / -0

Ram and Shyam together can do a work in $$16$$ days. Shyam takes twice time as Ram takes to do the same work. In how many days Ram alone can complete that work.

A
$$16$$ days

B
$$32$$ dyas

C
$$24$$ days

D
$$40$$ days

E
$$48$$ days

Solution

From given, we have,

Shyam+Ram=Shyam-Ram

$$\dfrac{1}{x}+\dfrac{1}{2x}=\dfrac{1}{16}$$

$$\Rightarrow 16+8=x$$

$$\therefore x=24$$

Ram takes $$24$$ days to complete the work
Question 6
1 / -0

$$4$$ men or $$6$$ women can do a work in $$42$$ days. The number of days $$12$$ men and $$3$$ women would take to finish the work is

A
$$20$$ days

B
$$15$$ days

C
$$12$$ days

D
$$10$$ days

Solution

Let the amount of work done by $$1$$ man in a day be $$m$$, and that done by $$1$$ woman be $$w$$.

Now, $$4m = 6w$$

Or, $$w = \dfrac{2m}{3} ……… (1)$$

Also, amount of work done by $$4$$ men in a day $$= 4m$$

Or $$4m = \dfrac{1}{42}$$

Or, $$m =\dfrac {1}{168} ……… (2)$$

Using $$(1)$$ and $$(2)$$, amount of work done by $$12$$ men and $$3$$ women in a day is $$12 m + 3w$$

$$=12 m + 2m$$ (substituting $$w$$ from $$1$$)

$$= 14 m$$

$$= 14/168$$

$$= 1/12$$

So, the total work will be completed in $$12$$ days.
Question 7
1 / -0

$$40$$ conservancy workers were employed for $$10$$ days to clean buildings affected by floods. The number of additional workers required to complete the work in $$4$$ days is

A
$$60$$

B
$$50$$

C
$$40$$

D
$$35$$

Solution

$$40$$ workers can clean the building in $$10$$ days

Number of workers required to clean the building in $$1$$ day $$=40\times 10=400$$

Hence, number of workers required to clean the building in $$4$$ days $$=\dfrac{40\times 10}{4}=100$$

So, number of additional workers required$$=100-40=60$$.
Question 8
1 / -0

$$39$$ persons can repair a road in $$12$$ days, working $$5$$ hours a day. In how many days will $$30$$ persons, working $$6$$ hours a day, complete the work?

A
$$9$$

B
$$12$$

C
$$13$$

D
$$10$$

Solution

Given,

Let the required number of days be $$x$$.

$$\left.\begin{matrix} Persons & 30:39 \\ Working hours/day & 6:5 \end{matrix}\right\} ⋮⋮ 12:x$$

$$\Rightarrow 30 \times 6 \times x = 39 \times 5 \times 12 $$

$$\therefore x= 13$$

Hence the number of days.
Question 9
1 / -0

The number of ways in which $$9$$ persons can be divided into three equal groups, is

A
$$1680$$

B
$$840$$

C
$$560$$

D
$$280$$

Solution
Question 10
1 / -0

The mean of squares of consecutive odd numbers from 1 to 13 is

A
70

B
65

C
75

D
66

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Numerical Applications Test 46

Result

Numerical Applications Test 46

Score

-

Rank

-

SHARING IS CARING

Question 1

$$5$$

$$4$$

$$30$$

$$None$$

Solution

Question 2

$$7$$

$$9$$

$$5$$

$$0$$

Solution

Question 3

$$10$$

$$15$$

$$20$$

$$30$$

Solution

Question 4

$$16$$ days

$$32$$ days

$$24$$ days

$$40$$ days

$$48$$ days

Solution

Question 5

$$16$$ days

$$32$$ dyas

$$24$$ days

$$40$$ days

$$48$$ days

Solution

Question 6

$$20$$ days

$$15$$ days

$$12$$ days

$$10$$ days

Solution

Question 7

$$60$$

$$50$$

$$40$$

$$35$$

Solution

Question 8

$$9$$

$$12$$

$$13$$

$$10$$

Solution

Question 9

$$1680$$

$$840$$

$$560$$

$$280$$

Solution

Question 10

70

65

75

66

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.