Logarithm and A...

The logarithm form of $$\displaystyle (81)^\frac{3}{4} = 27$$ is $$\log_{81} 27 = \displaystyle \frac{3}{m}$$. Then value of $$m$$ is equal to

The logarithm form of $$10^{-3} = 0.001$$ is $$\log_{10} 0.001 = -m$$, then value of $$m$$ is 

If $$\log_{10}(x - 10) = 1$$, then value of $$x$$ is

If $$\displaystyle 64^{a}=\frac{1}{256^{b}}$$, then $$3a + 4b$$ equals:

If $$x = 2$$ and $$y = 3$$, then find the value of $$\left[ \displaystyle\frac { 1 }{ x^{ x } } +\displaystyle\frac { 1 }{ y^{ y } }  \right] $$.

If $$\log_4m\,=\,1.5$$, then the value of $$m$$ is equal to

If $$ \log (a)^{3} + \log a$$ = $$m \log a$$, then value of $$m$$ is equal to

The value of $$4(7^1.\, 7^{-1}.\, 7^{-1}.7^0)$$ is

If $$ \dfrac{\log 81}{\log 27} = x$$, then the value of $$x$$ is equal to 

If $$\displaystyle \sqrt{3^{n}}=81$$. Then n is equal to