Logarithm and A...

The value of $$\frac { \log _{ 2 }{ 24 }  }{ \log _{ 96 }{ 2 }  } -\frac { \log _{ 2 }{ 192 }  }{ \log _{ 12 }{ 2 }  } $$ is:

$$a\times a\times b\times b\times b$$ can be written as 

$$\left(\dfrac {1}{10}\right)^0$$ is equal to

By solving $$(6^0 -7^0) \times (6^0+7^0)$$, we get ________.

$$\log_{\sqrt{2}} x = 4$$ then value of $$x$$ will be

$$\log_{x} 243 = 2.5$$, then value of $$x$$ will be:

The value of $$\log (1 + 2 * 3)$$:

Number $$\log_{2} 7$$ is:

Multiply $$10^4$$ by $$10^2$$