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Basics of Financial Mathematics Test 44

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Basics of Financial Mathematics Test 44
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  • Question 1
    1 / -0
    A species has an initial population $${ 4 }^{ 10 }.$$ At the end of second day, it decreases by the same percentage. If the process continues in the same pattern, the number of days for the population to reach $${ 3 }^{ 10 }.$$ is
    Solution

  • Question 2
    1 / -0
    The value of a machine depreciate 5% annually.  If is present  value is Rs 200000, its value after 2 years will be 
    Solution

  • Question 3
    1 / -0
    Abhinav purchased a tracksuit for $$2400$$ cash or for $$2000$$ cash down payments and two monthly installments of $$800$$ each. The rate of interest is

    Solution

  • Question 4
    1 / -0
    At what rate % per annul a sum of RS. 1800 will become RS. 2,700 in 10 years ?
    Solution

  • Question 5
    1 / -0
    A sum of money doubles itself in 10 years at SI. Then the rate of interest is ______.
    Solution

  • Question 6
    1 / -0
    A sum of money at SI amounts to RS.2240 in 2 years and to RS.2600 in 5 years. What is the principle amount ?
    Solution

  • Question 7
    1 / -0
    A car is valued at Rs. 500000 If sits value depreciates at 2 % p.a.  What will be its value after three years? 
    Solution

  • Question 8
    1 / -0
    The present population of a city is $$12,00,000$$ . If it increases at the rate of $$8$$% every year, then the population of the city after $$2$$ years is
    Solution

  • Question 9
    1 / -0
    The population of a suburb is $$16000$$. Find the rate of increase in the population if the population after two years is $$17640$$.
    Solution

    $${\textbf{Step  - 1: Framing the formula for finding the rate of decrease}}{\text{.}}$$

                       $${\text{Let the rate of increase in the population be }}r,$$

                       $${\text{We know, population increases geometrical progression so, we}}$$

                       $${\text{will use the compound interest formula}}{\text{.}}$$

                       $${\text{Given}},{\text{ }}P{\text{ }} = {\text{ }}16,000$$

                       $${\text{Time period }},{\text{ }}n{\text{ }} = {\text{ }}2$$

                       $${\text{Population after }}2{\text{ yrs }},{\text{ }}A{\text{ }} = {\text{ }}17640$$

                       $${\text{Using the formula of compound interest, we can write}}$$

                       $$A = P{\left( {1 + \dfrac{r}{{100}}} \right)^n}$$

                       $$17640 = 16000{\left( {1 + \dfrac{r}{{100}}} \right)^2}$$

    $${\textbf{Step  - 2: Solving the above equation to find the rate of decrease}}{\text{.}}$$

                       $$\dfrac{{17640}}{{16000}} = {\left( {1 + \dfrac{r}{{100}}} \right)^2}$$

                       $$\dfrac{{441}}{{400}} = {\left( {1 + \dfrac{r}{{100}}} \right)^2}$$

                       $${\text{Taking square root on both the sides,}}$$

                       $$\dfrac{{21}}{{20}} = 1 + \dfrac{r}{{100}}$$

                       $$\dfrac{1}{{20}} = \dfrac{r}{{100}}$$

                       $$r = 5% $$

    $${\textbf{Hence, the rate of decrease of population is 5% }}{\text{.}}$$

  • Question 10
    1 / -0
    Anitha borrowed Rs.400 from her friend at the rate of 12% p.a for 2 and half year. Find the interest and amount paid by her?
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