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Straight Lines Test 10

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Straight Lines Test 10
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Choose the correct statement(s):
    $$A$$: Every sequence is a progression.
    $$B$$: Every progression is a sequence.
    Solution
    The difference between a progression and a sequence is that a progression has a specific rule to calculate its next term from its previous term, whereas a sequence can be based on a logical rule like 'a group of prime numbers'.
    Thus, every progression is a sequence but every sequence is not a sequence.
  • Question 2
    1 / -0
    A sequence of numbers in which each term is related to its predecessor by same law is called
    Solution

    A sequence of numbers in which each term is related to its predecessor by same law is called progression
    Example: 1, 2, 3, 4.... is an example of sequence or progression.
    Since the given sequence follows a same rule or law through out the sequence and there is a relation between each term and it's previous one.
  • Question 3
    1 / -0
    $$10,$$ __$$, 15, 15, 20, 20, 25, 25,...$$. What number should fill the blank?
    Solution
    Here addition with repetition series, each number in the series repeats itself, and then increases by $$5$$ to get the next number.
    The next number is $$10$$.
  • Question 4
    1 / -0
    ________ can be defined as arrangement of terms in which sequence of terms follow some conditions.
    Solution
    Progression can be defined as arrangement of terms in which sequence of terms follow some conditions.
  • Question 5
    1 / -0
    _______ is a series of successive events.
    Solution
    Progression is a series of successive events.
  • Question 6
    1 / -0
    Find the next number in the series.
    $$3, 6, 9, 12, 15,....$$
    Solution
    The next number is $$18$$.
    Since the numbers are multiple of $$3$$.
    $$3, 6, 9, 12, 15, \underline {18 }$$.
  • Question 7
    1 / -0
    The area of triangle whose vertices are $$A (-3, -1), B(5, 3)$$ and $$C(2, -8)$$ is ____ $$\text{ sq. units}$$.
    Solution
    We know that the area of the triangle whose vertices are $$\displaystyle (x_{1},y_{1}),(x_{2},y_{2}),$$ and $$(x_{3},y_{3})$$ is $$\cfrac{1}{2}\left | x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1}) +x_{3}(y_{1}-y_{2})\right |$$

    The given vertices of the triangle are $$A(-3,-1), B(5,3)$$ and $$C(2,-8)$$.
    So, by using the above formula,
    $$\begin{aligned}{}\text{Area of the triangle} &= \frac{1}{2} {[ - 3(3 - ( - 8)) + 5( - 8 - ( - 1)) + 2( - 1 - 3)]}\\ &= \frac{1}{2}{[ - 33 - 35 - 8]}\\ &= \frac{{[ - 76]}}{2}\\& = \frac{{76}}{2}\quad\quad\quad\quad\dots[\text{Area can never be negative so, we ignore negative sign}]\\& = 38\text{ sq. units}\end{aligned}$$

    So, the area of the triangle is equal to $$38\text{ sq. units}$$.
  • Question 8
    1 / -0
    Based on this information answer the questions given below.
    (i) $$\displaystyle ^{ n }{ C }_{ p }= r!^{ n }{ C }_{ r }$$
    (ii) $$\displaystyle ^{ n }{ C }_{ r }+^{ n }{ C }_{ r-1 }=^{ n+1 }{ C }_{ r }$$
    What is the value of $$\displaystyle ^{ 8 }{ C }_{ 4 }+^{ 8 }{ C }_{ 3 }$$?
    Solution
    $$ ^{n}C_{r}+^{n}C_{r-1} = ^{n+1}C_{r} $$
    $$ \Rightarrow ^{8}C_{4}+^{8}C_{3} = \boxed{^{9}C_{4}} $$ 

  • Question 9
    1 / -0
    If there are five consecutive integer in a series and the first integer is $$1$$, what is the value of the last consecutive integer?
    Solution
    Let the five consecutive integers be $$x, x + 1, x + 2, x + 3$$ and $$x + 4$$.
    Therefore, the value of first integer is $$1$$ i.e., $$x = 1$$
    So, the last integer is $$x + 4$$
    The value of last integer $$= 5$$.
  • Question 10
    1 / -0
    The area of the triangle formed by three vertices $$O(0, 0), A(1, 0), B(0, 1)$$ is _____ sq. units.
    Solution
    Points are given as $$O(0,0), A(1,0), B(0,1)$$. 
    When plotted on the cartesian plane, these points make a right angled triangle $$OAB$$ with
    $$OA=1$$,  $$OB=1$$
    Area of this right angled triangle $$=\dfrac12\times OA\times OB$$
                                                           $$=\cfrac12\times1\times1\ sq.unit$$
                                                           $$=\cfrac12\ sq.unit$$ 

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