Straight Lines Test 12

Result

Straight Lines Test 12

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Directions For Questions

Question have a series with four figures called the problem figures. Bearing series in mind, choose the correct fifth blank figure(marked with $$?$$) from answer figures.

...view full instructions

A

B

C

D

Solution

Given answer is correct as first line appears and then cut of image appears.
Hence, option B is correct.
Question 2
1 / -0

Select the correct alternative from the given ones that will complete the series.
$$YXWv, TSrQ, OnML, jIHG, EDCb, ?$$

A
$$YXwV$$

B
$$ZYxW$$

C
$$XwVU$$

D
$$YxWV$$

Solution

$$\underset {-5\downarrow}{Y}\xrightarrow {-1} \underset {-5\downarrow}{X}\xrightarrow {-1} \underset {-5\downarrow}{W}\xrightarrow {-1} \underset {-5\downarrow}{v}$$

$$T\xrightarrow {-1} S\xrightarrow {-1} r\xrightarrow {-1} Q$$
Similarly, $$\underset {-5\downarrow}{E}\xrightarrow {-1} \underset {-5\downarrow}{D}\xrightarrow {-1} \underset {-5\downarrow}{C}\xrightarrow {-1} \underset {-5\downarrow}{b}$$

$$Z \xrightarrow {-1} Y \xrightarrow {-1} x \xrightarrow {-1} W$$

The small alphabets move $$1$$ step towards left in each term.

Hence, $$ZYxW$$ is the missing term.

Hence option $$B$$ is the answer.
Question 3
1 / -0

A word is represented by only one set of numbers as given in any one of the alternatives. The sets of numbers given in the alternatives are represented by two classes of alphabets as in the two matrices given below. The columns and rows of Matrix I are numbered from $$0$$ to $$4$$ and that of Matrix $$I$$ are numbered from $$5$$ to $$9$$. A letter from these matrices can be represented first by its row and next by its column, e.g. $$'A'$$ can be represented by $$00, 12, 23$$ etc., and $$'P'$$ can be represented by $$58, 69, 75$$ etc. Similarly, you have to identify the set for the word 'POET'.
Matrix I
$$0$$ $$1$$ $$2$$ $$3$$ $$4$$
$$0$$ $$A$$ $$R$$ $$S$$ $$N$$ $$C$$
$$1$$ $$N$$ $$C$$ $$A$$ $$R$$ $$S$$
$$2$$ $$S$$ $$N$$ $$C$$ $$A$$ $$R$$
$$3$$ $$R$$ $$S$$ $$N$$ $$C$$ $$A$$
$$4$$ $$C$$ $$A$$ $$R$$ $$S$$ $$N$$
Matrix II
$$5$$ $$6$$ $$7$$ $$8$$ $$9$$
$$5$$ $$O$$ $$E$$ $$L$$ $$P$$ $$T$$
$$6$$ $$T$$ $$O$$ $$E$$ $$L$$ $$P$$
$$7$$ $$P$$ $$T$$ $$O$$ $$E$$ $$L$$
$$8$$ $$L$$ $$P$$ $$T$$ $$O$$ $$E$$
$$9$$ $$E$$ $$L$$ $$P$$ $$T$$ $$O$$

A
$$69, 88, 67, 65$$

B
$$75, 56, 65, 67$$

C
$$77, 88, 98, 78$$

D
$$75, 66, 76, 78$$

Solution

From matrix,
$$P\Rightarrow 58, 69, 75, 86, 97$$
$$O\Rightarrow 55, 66, 77, 88, 99$$
$$E\Rightarrow 56, 67, 78, 87, 98$$
$$T\Rightarrow 69, 88, 67, 65$$
$$\therefore POET\Rightarrow 69, 88, 67, 65$$.
Question 4
1 / -0

In this question, the sets of numbers given in the alternatives are represented by two classes of alphabets as in two matrices given below. The columns and rows of Matrix I are numbered from $$0$$ to $$4$$ and that of Matrix II are numbered from $$5$$ to $$9$$. A letter from these matrices can be represented first by its row and next by its column, e.g., $$'B'$$ can be represented by $$00, 13,$$ etc., and $$'A'$$ can be represented by $$55, 69$$, etc. Similarly you have to identify the set for the word 'GIRL'.
Matrix I
$$0$$ $$1$$ $$2$$ $$3$$ $$4$$
$$0$$ $$B$$ $$N$$ $$G$$ $$L$$ $$D$$
$$1$$ $$G$$ $$L$$ $$D$$ $$B$$ $$N$$
$$2$$ $$D$$ $$B$$ $$N$$ $$G$$ $$L$$
$$3$$ $$N$$ $$G$$ $$L$$ $$D$$ $$B$$
$$4$$ $$L$$ $$D$$ $$B$$ $$N$$ $$G$$
Matrix II
$$5$$ $$6$$ $$7$$ $$8$$ $$9$$
$$5$$ $$A$$ $$I$$ $$K$$ $$O$$ $$R$$
$$6$$ $$I$$ $$K$$ $$O$$ $$R$$ $$A$$
$$7$$ $$K$$ $$O$$ $$R$$ $$A$$ $$I$$
$$8$$ $$O$$ $$R$$ $$A$$ $$I$$ $$K$$
$$9$$ $$R$$ $$A$$ $$I$$ $$K$$ $$O$$

A
$$02, 56, 97, 24$$

B
$$31, 79, 68, 42$$

C
$$23, 97, 77, 11$$

D
$$11, 88, 95, 23$$

Solution

From matrix,
$$G\Rightarrow 02, 10, 23, 31, 44$$
$$I\Rightarrow 56, 65, 79, 88, 97$$
$$R\Rightarrow 59, 68, 77, 86, 95$$
$$L\Rightarrow 03, 11, 24, 32, 40$$
$$\therefore GIRL\Rightarrow 23, 97, 77, 11$$.
Question 5
1 / -0

A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
$$hqva, clqv, ?, yhmr$$.

A
$$gpvy$$

B
$$gkuz$$

C
$$gpuz$$

D
$$govz$$

Solution

$$h\xrightarrow {-2} q \xrightarrow {+5} v \xrightarrow {+5} a$$

$$c\xrightarrow {-2} l\xrightarrow {+5} q\xrightarrow {+5} v$$

$$g\xrightarrow {2} p\xrightarrow {+5} u\xrightarrow {+5} z$$

$$y \xrightarrow {-2} h\xrightarrow {+5} m \xrightarrow {+5} r$$.

Hence option $$C$$ is the answer.
Question 6
1 / -0

Select a figure from the options which will replace the question mark to complete the given series.

A

B

C

D

Solution

Each element moves on step forward anticlockwise direction.
Option B.
Question 7
1 / -0

In which of these figures does the angle $$\theta$$ represent the inclination of line L.

A

B

C

D
None of the above

Solution

We know that inclination of a line is the angle it makes with the positive $$x-$$axis.
Hence, A will be correct.
Question 8
1 / -0

The number of ways in which ten candidates $$A_1, A_2,......A_{10}$$ can be ranked such that $$A_1$$ is always above $$A_{10}$$ is

A
$$5!$$

B
$$2(5!)$$

C
$$10!$$

D
$$\dfrac{1}{2}(10!)$$

Solution

Total number of ways to arrange $$A_1,A_2 .. A_{10} = 10!$$
In $$\dfrac{10! }{ 2}$$ combinations $$A_1$$ will be above $$A_2$$ and in the other half $$A_2$$ will be above $$A_1$$.

Ans : $$\dfrac{10! }{2}$$
Question 9
1 / -0

From a well shuffled pack of $$52$$ playing cards two cards drawn at random. The probability that either both are red or both are kings is:

A
$$\dfrac{{\left( {^{26}{C_2} + \,{\,^4}{C_2}} \right)}}{{^{52}{C_2}}}$$

B
$$\dfrac{{\left( {^{26}{C_2} + {\,^4}{C_2} - {\,^2}{C_2}} \right)}}{{^{52}{C_2}}}$$

C
$$\dfrac{{^{30}{C_2}}}{{^{52}{C_2}}}$$

D
$$\dfrac{{^{39}{C_2}}}{{^{52}{C_2}}}$$

Solution

Assuming, cards are drawn without replacement:

Total possible events $$=^{52}C_2$$

P(both red) $$=\dfrac{ ^{26}C_2}{^{52}C_2}$$

P(both king) $$=\dfrac{^{4}C_2}{^{52}C_2}$$

P(both red & king) $$=\dfrac {^2C_2}{{^{52}C_2}}$$

We use the basic addition rule,

P(both black or both queens) = P(both red) + P(both queens) - P(both black as well as queens)

Required probability $$=\dfrac{^{26}C_2+^{4}C_2-^2C_2}{^{52}C_2}$$
Question 10
1 / -0

Select the missing number from the given matrix:
5 2 4
4 4 7
2 5 3
18 30 ?

A
$$43$$

B
$$42$$

C
$$33$$

D
$$32$$

Solution

In first column $$(5+4)\times 2=18$$ In second column $$(2+4)\times 5=30$$

so in third column ans

$$=(4+7)\times3$$

$$=11\times 3=33.$$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

		Matrix I
	$$0$$	$$1$$	$$2$$	$$3$$	$$4$$
$$0$$	$$A$$	$$R$$	$$S$$	$$N$$	$$C$$
$$1$$	$$N$$	$$C$$	$$A$$	$$R$$	$$S$$
$$2$$	$$S$$	$$N$$	$$C$$	$$A$$	$$R$$
$$3$$	$$R$$	$$S$$	$$N$$	$$C$$	$$A$$
$$4$$	$$C$$	$$A$$	$$R$$	$$S$$	$$N$$

		Matrix II
	$$5$$	$$6$$	$$7$$	$$8$$	$$9$$
$$5$$	$$O$$	$$E$$	$$L$$	$$P$$	$$T$$
$$6$$	$$T$$	$$O$$	$$E$$	$$L$$	$$P$$
$$7$$	$$P$$	$$T$$	$$O$$	$$E$$	$$L$$
$$8$$	$$L$$	$$P$$	$$T$$	$$O$$	$$E$$
$$9$$	$$E$$	$$L$$	$$P$$	$$T$$	$$O$$

Straight Lines Test 12

Result

Straight Lines Test 12

Score

-

Rank

-

SHARING IS CARING

Question 1

Solution

Question 2

$$YXwV$$

$$ZYxW$$

$$XwVU$$

$$YxWV$$

Solution

Question 3

$$69, 88, 67, 65$$

$$75, 56, 65, 67$$

$$77, 88, 98, 78$$

$$75, 66, 76, 78$$

Solution

Question 4

$$02, 56, 97, 24$$

$$31, 79, 68, 42$$

$$23, 97, 77, 11$$

$$11, 88, 95, 23$$

Solution

Question 5

$$gpvy$$

$$gkuz$$

$$gpuz$$

$$govz$$

Solution

Question 6

Solution

Question 7

None of the above

Solution

Question 8

$$5!$$

$$2(5!)$$

$$10!$$

$$\dfrac{1}{2}(10!)$$

Solution

Question 9

$$\dfrac{{\left( {^{26}{C_2} + \,{\,^4}{C_2}} \right)}}{{^{52}{C_2}}}$$

$$\dfrac{{\left( {^{26}{C_2} + {\,^4}{C_2} - {\,^2}{C_2}} \right)}}{{^{52}{C_2}}}$$

$$\dfrac{{^{30}{C_2}}}{{^{52}{C_2}}}$$

$$\dfrac{{^{39}{C_2}}}{{^{52}{C_2}}}$$

Solution

Question 10

$$43$$

$$42$$

$$33$$

$$32$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.