Straight Lines Test 8

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Straight Lines Test 8

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Weekly Quiz Competition

Question 1
1 / -0

How many numbers are there between 500 and 600 in which 9 occurs only once?

A
19

B
18

C
10

D
9

Solution

509 , 519 , 529 , 539 , 549 , 559 , 569 , 579 , 589 , 590 , 591 , 592 ,

593 , 594 , 595 , 596 , 597 , 598 ...as 9 has to be occurred only once

so 599 would not be there so only 18 numbers are there.
Question 2
1 / -0

aba_baca_ba_bacaabac_aca

A
cacb

B
ccab

C
cabc

D
abcc

Solution

Pattern is abac/baca/abac/baca/abac/baca
Thus the pattern abac,baca is repeated
Question 3
1 / -0

How many numbers of four digits can be formed from the digits 0, 1, 2, 3, and 4?

A
48

B
64

C
96

D
100

Solution

The first box can be filled in four ways, because we cannot put 0 in the first box. The second box can also be filled in four ways, because we cannot put 0. The third box can be filled in three ways and the fourth in two ways. Therefore,
Total numbers = $$\displaystyle 4\times 4\times 3\times 2=96$$
Question 4
1 / -0

_ab_caa_bbcaa_b_caaa

A
abaab

B
cabab

C
bccaa

D
baaba

Solution

Pattern is aabbc/ aaabbc/ aaabbc/ aaa
Question 5
1 / -0

If the area of the triangle formed by $$ (-2,5), (x,-3) $$ and $$(3,2)$$ is $$14 $$ square units, then $$x=$$ ____.

A
1

B
2

C
-2

D
-1

Solution

Area of triangle having vertices $$(x_1,y_1), (x_2,y_2)$$ and $$(x_3,y_3)$$ is given by
$$ = \dfrac{1}{2} \times [ x_1 (y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) ] $$
$$\therefore \displaystyle Area=\frac{1}{2}\left [ -2\left ( -3-2 \right )+x\left ( 2-5 \right )+3\left ( 5+3 \right ) \right ]$$
$$\displaystyle =\frac{1}{2}\left [ 10-3x+24 \right ]=\frac{34-3x}{2}$$
$$\displaystyle \therefore \frac{34-3x}{2}=14$$ or x = 2
Question 6
1 / -0

ab _ bc _ c _ ba _ c

A
baac

B
aabb

C
caab

D
aaab

Solution

Pattern is abc/bca/cab/abc
Thus letters are written in a cyclic order
Question 7
1 / -0

In a class there are 18 boys who are over 160 cm tall If these constitute three-fourths of the boys and the total number of boys is tow-third of the total number of students in the class what is the number of girls in the class?

A
6

B
12

C
18

D
24

Solution

Given in class there are 18 boys who over 160 cm tall and these are three- fourths of total boys
Then total boys in class=$$18\div \frac{3}{4}= 18\times \frac{4}{3}=24$$
And total no of student in class=$$24\times \frac{3}{2}=36$$
Then number of girls=36-24=12
Question 8
1 / -0

Out of 100 students 50 fail in English and 30 in Maths. If 12 students fail in both English and Maths, then the number of students passing both the subjects is

A
26

B
28

C
30

D
32

Solution

Total number of students=100
Number of students fail in English=(50-12)=38
Number of students fail in Maths=(30-12)=18
Number of students fail in both=12
Therefore total failing students=(38+18+12)=68
Pass in both the subjects=(100-68)
=32 students
32 students have passed in both subjects
Question 9
1 / -0

If the area of the triangle formed by the points $$(-2,3), (4,-5)$$ and $$(-3,y)$$ is 10 square units then $$y =$$

A
$$\dfrac{19}{3}$$

B
$$\dfrac{21}{3}$$

C
$$\dfrac{23}{3}$$

D
$$\dfrac{25}{3}$$

Solution

Area of triangle having vertices $$(x_1,y_1), (x_2,y_2)$$ and $$(x_3,y_3)$$ is given by
$$ = \dfrac{1}{2} \times [ x_1 (y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) ] $$
$$\displaystyle \text{Area} =\frac{1}{2}\left [ -2\left ( -5-y \right )+4\left ( y-3 \right )-3\left ( 3+5 \right ) \right ]$$
$$\displaystyle =\frac{1}{2}\left ( 10+2y+4y-12-24 \right )$$
$$\displaystyle =\frac{1}{2}\left ( 6y-26 \right )=3y-13$$
$$\displaystyle 3y-13=10\ \mathrm{sq. unit}$$
$$\displaystyle y=\frac{23}{3}$$
Question 10
1 / -0

At the end of a business conference, the ten people present all shake hands with each other once. How many handshakes will there be altogether?

A
20

B
45

C
55

D
90

Solution

Total number of handshakes=10×92=45

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Re-Attempt Weekly Quiz Competition

Straight Lines Test 8

Result

Straight Lines Test 8

Score

-

Rank

-

SHARING IS CARING

Question 1

19

18

10

9

Solution

Question 2

cacb

ccab

cabc

abcc

Solution

Question 3

48

64

96

100

Solution

Question 4

abaab

cabab

bccaa

baaba

Solution

Question 5

1

2

-2

-1

Solution

Question 6

baac

aabb

caab

aaab

Solution

Question 7

6

12

18

24

Solution

Question 8

26

28

30

32

Solution

Question 9

$$\dfrac{19}{3}$$

$$\dfrac{21}{3}$$

$$\dfrac{23}{3}$$

$$\dfrac{25}{3}$$

Solution

Question 10

20

45

55

90

Solution

User

Question Analysis

My Perfomance

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