Permutations and Combinations Test 12

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Permutations and Combinations Test 12

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Weekly Quiz Competition

Question 1
1 / -0

Complete the addition square by finding the missing numbers.
Find $$(A-B)-(C-D)$$
$$+$$ $$10,923$$ $$8,473$$
$$18,732$$ $$A$$ $$B$$
$$9,018$$ $$C$$ $$D$$

A
$$0$$

B
$$450$$

C
$$1000$$

D
$$300$$

Solution

From the given table, we have
$$A=18,732+10,923=29,655$$
$$B=18,732+8,473=27,205$$
$$C=10,923+9,018=19,941$$
and $$D=8473+9,018=17,491$$
Now $$A-B=29,655-27,205=2,450$$
$$C-D=19,941-17,491=2,450$$
$$\therefore$$ $$(A-B)-(C-D)=2,450-2,450=0$$
Question 2
1 / -0

The models are shaded to show which of the following?

A
$$\cfrac { 1 }{ 3 } =\cfrac { 2 }{ 4 } $$

B
$$\cfrac { 1 }{ 4 } >\cfrac { 1 }{ 3 } $$

C
$$\cfrac { 2 }{ 3 } <\cfrac { 2 }{ 4 } $$

D
$$\cfrac { 2 }{ 4 } <\cfrac { 2 }{ 3 } $$

Solution

Fraction of shaded part in upper rectangle $$=2\times\dfrac{1}{3}=\dfrac{2}{3}$$
Fraction of shaded part in lower rectangle $$=2\times\dfrac{1}{4}=\dfrac{2}{4}$$
In upper rectangle shaded part is greater
So, $$\dfrac { 2 }{ 4 } <\dfrac { 2 }{ 3 } $$
Option D is correct.
Question 3
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Fathom is a unit once used by sailors to measure the depth of water. If a sunken ship was located underwater at $$240$$ feet, which expression would describe the location of the ship in fathoms?
$$ { 1\ fathom=6\ feet } $$

A
$$240\times 6$$

B
$$240\div 6$$

C
$$240-6$$

D
$$240+6$$

Solution

We have $$1fathom=6feet$$
$$1feet=\cfrac{1}{6}fathom$$
Ship was located underwater at $$240$$ feet
$$\therefore$$ location of ship underwater in fathoms $$=240\div6$$
Question 4
1 / -0

In the Number series given below, one number is missing. Series is followed by five alternatives. One of them is the right answer. Identify and indicate it as per the "Instructions".
$$2,35,104,209,....$$

A
$$350$$

B
$$248$$

C
$$256$$

D
$$311$$

E
$$413$$

Solution

To solve this question, we use the method of difference.
let $${T_5}=x$$
Now, series is $${S}:\ 2,\ 35,\ 104,\ 209,\ x$$
Let us take the difference between any 2 adjacent terms be a series $$dS$$
$${dS}: \ 33,\ 69,\ 105,\ (x-209)$$
We again take the difference between 2 adjacent terms. Let the series be $$ddS: \ 36,\ 36,\ (x-209-105) $$
For the series to be consistent,
$${x-209-105}={36}$$
$$\implies x=350$$
Thus, $${(A)}$$ must be the answer.
Question 5
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Directions For Questions

In these questions, numbers are placed in the figures on the basis of some rules. One place is vacant which if indicated as'?' Find out the correct alternatives to replace the question mark '?'

...view full instructions

The figure is given.

A
$$7$$

B
$$4$$

C
$$10$$

D
$$8$$

E
$$6$$

Solution

The no. in the triangle is:
$$\dfrac { (\text{largest}+\text{smallest})-\text{middle} }{ 2 } =\text{ number}$$
Triangle 1: $$\quad \dfrac { (13+5)-12 }{ 2 } = 3$$
Triangle 2: $$\quad \dfrac { (13+4)-9 }{ 2 } = 4$$
Thus the answer is: $$ \dfrac { (16+5)-7}{ 2 } =7$$
Thus, the answer is $$7$$.
Question 6
1 / -0

Directions For Questions

Question have a series with four figures called the problem figures. Bearing series in mind, choose the correct fifth blank figure(marked with $$?$$) from answer figures.

...view full instructions

A

B

C

D

Solution

Given answer is correct as first line appears and then cut of image appears.
Hence, option B is correct.
Question 7
1 / -0

Select the correct alternative from the given ones that will complete the series.
$$YXWv, TSrQ, OnML, jIHG, EDCb, ?$$

A
$$YXwV$$

B
$$ZYxW$$

C
$$XwVU$$

D
$$YxWV$$

Solution

$$\underset {-5\downarrow}{Y}\xrightarrow {-1} \underset {-5\downarrow}{X}\xrightarrow {-1} \underset {-5\downarrow}{W}\xrightarrow {-1} \underset {-5\downarrow}{v}$$

$$T\xrightarrow {-1} S\xrightarrow {-1} r\xrightarrow {-1} Q$$
Similarly, $$\underset {-5\downarrow}{E}\xrightarrow {-1} \underset {-5\downarrow}{D}\xrightarrow {-1} \underset {-5\downarrow}{C}\xrightarrow {-1} \underset {-5\downarrow}{b}$$

$$Z \xrightarrow {-1} Y \xrightarrow {-1} x \xrightarrow {-1} W$$

The small alphabets move $$1$$ step towards left in each term.

Hence, $$ZYxW$$ is the missing term.

Hence option $$B$$ is the answer.
Question 8
1 / -0

A word is represented by only one set of numbers as given in any one of the alternatives. The sets of numbers given in the alternatives are represented by two classes of alphabets as in the two matrices given below. The columns and rows of Matrix I are numbered from $$0$$ to $$4$$ and that of Matrix $$I$$ are numbered from $$5$$ to $$9$$. A letter from these matrices can be represented first by its row and next by its column, e.g. $$'A'$$ can be represented by $$00, 12, 23$$ etc., and $$'P'$$ can be represented by $$58, 69, 75$$ etc. Similarly, you have to identify the set for the word 'POET'.
Matrix I
$$0$$ $$1$$ $$2$$ $$3$$ $$4$$
$$0$$ $$A$$ $$R$$ $$S$$ $$N$$ $$C$$
$$1$$ $$N$$ $$C$$ $$A$$ $$R$$ $$S$$
$$2$$ $$S$$ $$N$$ $$C$$ $$A$$ $$R$$
$$3$$ $$R$$ $$S$$ $$N$$ $$C$$ $$A$$
$$4$$ $$C$$ $$A$$ $$R$$ $$S$$ $$N$$
Matrix II
$$5$$ $$6$$ $$7$$ $$8$$ $$9$$
$$5$$ $$O$$ $$E$$ $$L$$ $$P$$ $$T$$
$$6$$ $$T$$ $$O$$ $$E$$ $$L$$ $$P$$
$$7$$ $$P$$ $$T$$ $$O$$ $$E$$ $$L$$
$$8$$ $$L$$ $$P$$ $$T$$ $$O$$ $$E$$
$$9$$ $$E$$ $$L$$ $$P$$ $$T$$ $$O$$

A
$$69, 88, 67, 65$$

B
$$75, 56, 65, 67$$

C
$$77, 88, 98, 78$$

D
$$75, 66, 76, 78$$

Solution

From matrix,
$$P\Rightarrow 58, 69, 75, 86, 97$$
$$O\Rightarrow 55, 66, 77, 88, 99$$
$$E\Rightarrow 56, 67, 78, 87, 98$$
$$T\Rightarrow 69, 88, 67, 65$$
$$\therefore POET\Rightarrow 69, 88, 67, 65$$.
Question 9
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In this question, the sets of numbers given in the alternatives are represented by two classes of alphabets as in two matrices given below. The columns and rows of Matrix I are numbered from $$0$$ to $$4$$ and that of Matrix II are numbered from $$5$$ to $$9$$. A letter from these matrices can be represented first by its row and next by its column, e.g., $$'B'$$ can be represented by $$00, 13,$$ etc., and $$'A'$$ can be represented by $$55, 69$$, etc. Similarly you have to identify the set for the word 'GIRL'.
Matrix I
$$0$$ $$1$$ $$2$$ $$3$$ $$4$$
$$0$$ $$B$$ $$N$$ $$G$$ $$L$$ $$D$$
$$1$$ $$G$$ $$L$$ $$D$$ $$B$$ $$N$$
$$2$$ $$D$$ $$B$$ $$N$$ $$G$$ $$L$$
$$3$$ $$N$$ $$G$$ $$L$$ $$D$$ $$B$$
$$4$$ $$L$$ $$D$$ $$B$$ $$N$$ $$G$$
Matrix II
$$5$$ $$6$$ $$7$$ $$8$$ $$9$$
$$5$$ $$A$$ $$I$$ $$K$$ $$O$$ $$R$$
$$6$$ $$I$$ $$K$$ $$O$$ $$R$$ $$A$$
$$7$$ $$K$$ $$O$$ $$R$$ $$A$$ $$I$$
$$8$$ $$O$$ $$R$$ $$A$$ $$I$$ $$K$$
$$9$$ $$R$$ $$A$$ $$I$$ $$K$$ $$O$$

A
$$02, 56, 97, 24$$

B
$$31, 79, 68, 42$$

C
$$23, 97, 77, 11$$

D
$$11, 88, 95, 23$$

Solution

From matrix,
$$G\Rightarrow 02, 10, 23, 31, 44$$
$$I\Rightarrow 56, 65, 79, 88, 97$$
$$R\Rightarrow 59, 68, 77, 86, 95$$
$$L\Rightarrow 03, 11, 24, 32, 40$$
$$\therefore GIRL\Rightarrow 23, 97, 77, 11$$.
Question 10
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A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
$$hqva, clqv, ?, yhmr$$.

A
$$gpvy$$

B
$$gkuz$$

C
$$gpuz$$

D
$$govz$$

Solution

$$h\xrightarrow {-2} q \xrightarrow {+5} v \xrightarrow {+5} a$$

$$c\xrightarrow {-2} l\xrightarrow {+5} q\xrightarrow {+5} v$$

$$g\xrightarrow {2} p\xrightarrow {+5} u\xrightarrow {+5} z$$

$$y \xrightarrow {-2} h\xrightarrow {+5} m \xrightarrow {+5} r$$.

Hence option $$C$$ is the answer.

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$$+$$	$$10,923$$	$$8,473$$
$$18,732$$	$$A$$	$$B$$
$$9,018$$	$$C$$	$$D$$

		Matrix I
	$$0$$	$$1$$	$$2$$	$$3$$	$$4$$
$$0$$	$$A$$	$$R$$	$$S$$	$$N$$	$$C$$
$$1$$	$$N$$	$$C$$	$$A$$	$$R$$	$$S$$
$$2$$	$$S$$	$$N$$	$$C$$	$$A$$	$$R$$
$$3$$	$$R$$	$$S$$	$$N$$	$$C$$	$$A$$
$$4$$	$$C$$	$$A$$	$$R$$	$$S$$	$$N$$

		Matrix II
	$$5$$	$$6$$	$$7$$	$$8$$	$$9$$
$$5$$	$$O$$	$$E$$	$$L$$	$$P$$	$$T$$
$$6$$	$$T$$	$$O$$	$$E$$	$$L$$	$$P$$
$$7$$	$$P$$	$$T$$	$$O$$	$$E$$	$$L$$
$$8$$	$$L$$	$$P$$	$$T$$	$$O$$	$$E$$
$$9$$	$$E$$	$$L$$	$$P$$	$$T$$	$$O$$

Permutations and Combinations Test 12

Result

Permutations and Combinations Test 12

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SHARING IS CARING

Question 1

$$0$$

$$450$$

$$1000$$

$$300$$

Solution

Question 2

$$\cfrac { 1 }{ 3 } =\cfrac { 2 }{ 4 } $$

$$\cfrac { 1 }{ 4 } >\cfrac { 1 }{ 3 } $$

$$\cfrac { 2 }{ 3 } <\cfrac { 2 }{ 4 } $$

$$\cfrac { 2 }{ 4 } <\cfrac { 2 }{ 3 } $$

Solution

Question 3

$$240\times 6$$

$$240\div 6$$

$$240-6$$

$$240+6$$

Solution

Question 4

$$350$$

$$248$$

$$256$$

$$311$$

$$413$$

Solution

Question 5

$$7$$

$$4$$

$$10$$

$$8$$

$$6$$

Solution

Question 6

Solution

Question 7

$$YXwV$$

$$ZYxW$$

$$XwVU$$

$$YxWV$$

Solution

Question 8

$$69, 88, 67, 65$$

$$75, 56, 65, 67$$

$$77, 88, 98, 78$$

$$75, 66, 76, 78$$

Solution

Question 9

$$02, 56, 97, 24$$

$$31, 79, 68, 42$$

$$23, 97, 77, 11$$

$$11, 88, 95, 23$$

Solution

Question 10

$$gpvy$$

$$gkuz$$

$$gpuz$$

$$govz$$

Solution

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