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Permutations and Combinations Test 2

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Permutations and Combinations Test 2
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  • Question 1
    1 / -0
    Factorial of negative numbers is always greater than 1.
    Solution
    Factorial : product of an integer with integer less than it.
    Factorial can be interpolated using gamma function and gamma function and 
    gamma function is not defined for negative integer.
    Factorial is not defined for negative integer 
  • Question 2
    1 / -0
    Choose the correct option for the following.
    $$n!=n(n-1)(n-2).....3.2.1$$
    Solution
    Factorial : the product of an integer and all integer less than that 
    $$\therefore n!=n\times (n-1)\times (n-2)............3\times 2\times 1$$

    $$\therefore $$ The given statement 
    $$n!=n\times (n-1)\times (n-2)............3\times 2\times 1$$ is True
  • Question 3
    1 / -0
    Three boys and three girls are to be seated around a table in a circle. Among them the boy X does not want any girl neighbour and the girl Y does not want any boy neighbour. How many such arrangements are possible?
    Solution
    As boy $$X$$ does not need any girl neighbour so he will have $$2$$ boys sitting next to him. 
    The $$2$$ boys can be arranged in $$2!$$ ways.
    Similarly $$Y$$ will be surrounded by $$2$$ girls and these $$2$$ girls can be arranged in $$2!$$ ways.
    So number of arrangements $$=2!\times 2!=2\times 2=4$$
    Hence, the answer is $$4$$.
  • Question 4
    1 / -0
    Area of a triangle formed by the points A(5, 2), B(4, 7) and C(7, -4) is _____.
    Solution

    Area of a triangle ABC = $$ \frac { 1 }{ 2 } \left|[ x_{ 1 }\left( y_{ 2 }-y_{ 3 }

    \right) +x_{ 2 }\left( y_{ 3 }-y_{ 1 } \right) +x_{ 3 }\left( y_{ 1 }-y_{ 2 }

    \right)  \right]|$$

    Substituting the given coordinates, we have

    =$$ \frac { 1 }{ 2 } \left[ 5 \left(7+4) \right) -\left( 4+2\right) +7\left( 2-7) \right)  \right]$$

    $$ =\frac { 1 }{ 2 } \left( 5 ( 11) +4\times( -6)
    +7\times( -5)\right)$$

    $$ =\frac { 1 }{ 2 } \left[(55) - ( 24) - ( 35)  \right]$$

    $$ =\frac { 1 }{ 2 } \times |-4| = 2$$ square units.

  • Question 5
    1 / -0
    The figure below shows the network connecting cities A, B, C, D, E and F. The arrows indicate permissible direction of travel. What is the number of distinct paths from A to F?

    Solution
    (B) The maximum routes from A to F are listed below.

    (1) ABDF                   (2) ACDF                     (3) ABF                             (4) ABEF   

    (5) ACDEF                 (6) ABCDEF               (7) ABDEF                        (8) ABCDF

  • Question 6
    1 / -0
    Which letter will be the fifth from the right if the first and second, the third and fourth and so on are interchanged among each other in the word "COMPANIONATE"?
    Solution
    When we interchange the first and the second, third and the fourth, and so on letters in the word COMPANIONATE, the new word becomes OCPMNAOIANET.
    Therefore, 5th letter from right is I
    Answer is Option B
  • Question 7
    1 / -0
    The positions of the first and the fifth digits in the number 83256479 are interchanged. Similarly the positions of the second and the sixth digits are interchanged and so on. Which of the following will be the third to the right of the seventh digit from the right end after rearrangement?
    Solution
    In the given number 83256479, the first and the fifth digits are interchanged.The number becomes 63258479.
    Then second and the sixth digit are interchanged. The number becomes 64258379.
    The third and the seventh digit are interchanged. The number becomes 64758329.
    The fourth and the eighth digit are interchanged. The number becomes 64798325.
    The seventh digit from the right end after rearrangement is 4.The third digit to the right of 4 is 8.
    Answer is Option D

  • Question 8
    1 / -0
    The spread sheet on the right contains 20 cells. A cell In a spread sheet can be identified fIrst by the column letter and then by the row number. For example,. the number 10 is found in cell C4. If the number in cell A3 =B4-3(E2 +D4) then which of the following must be the number in cell E2?

    Solution
    Its given
    A3=B4-3(E2+D4)
    Substituting the values from the grid
    $$18=-6-3(E2+4)$$
    $$24=-3(E2+4)$$
    $$-8-4=E2$$
    $$E2=-12$$
    Answer is Option D
  • Question 9
    1 / -0
    In numbers from $$1 \ to\  100$$ the digit "$$0$$" appears ____________times.
    Solution
    $$10, 20, 30, 40, 50, 60, 70, 80, 90, 100$$
    Thus the digit $$0$$ appears $$11$$ times.
  • Question 10
    1 / -0
    The greatest number that can be formed by the digits $$7,0,9,8,6,3$$
    Solution
    The greatest number that can be formed by the digits $$7,0,9,8,6,3$$ is $$9 8 7 6 3 0$$
    To achieve this arrange the given numbers in descending order.
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