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Some Basic Concepts of Chemistry Test - 10

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Some Basic Concepts of Chemistry Test - 10
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Weekly Quiz Competition
  • Question 1
    1 / -0

    15 km is  =   ---------------- m. ? 

    Solution

    Since ,

    1km

    = 1000 m 

    ∴ 15 km

     =  (  15  x  1000 ) m  

    =15000 m

  • Question 2
    1 / -0

    30.4 cm  = ---------- mm.:

    Solution

     Since,

    1cm

    =10 mm

    ∴ 30.4 cm  

    =  (30.4 x  10) mm.

    = 304 mm.

  • Question 3
    1 / -0

    There are ___ L  in 12.0 ml?

    Solution

    Since , 1L

    =1000 ml

    ∴   12 ml

    = 12/1000  L

    =  0.012 L

  • Question 4
    1 / -0

    The gram  molar mass of ZnSO4 is,

    Solution

    molar mass of ZnSO4

    = Σ ( Atomic masses of Zn  ,  S ,  4 x   O atoms ) 

     = [ ( 65.30 )   +  ( 32.065 )  +  ( 15.994 * 4 ) ].

    =   161.4426 g / mol

    ~ = 161.44 g / mol

  • Question 5
    1 / -0

    The gm molar mass of H2SO4 is

    Solution

    Gram molar mas of s HS O4

      =  [(  2  x  atomic mass of  H )    +   (  atomic mass of  S  )     +  (  4   x  atomic mass of  O ) ] g

    =  [ 2(1)+32+4(16) ] g

    = 98 g.

  • Question 6
    1 / -0

    A person is suffering with fever with a high temperature of 104 °F. What will be his body temperature in °C?

    Solution

    104°F − 32) × 5/9 = 40°C

  • Question 7
    1 / -0

    In centigrade scale, -40 °F becomes

    Solution

    Calculations :-  

    Since , °F

    = [ (°C x 9/5 ) + 32 ] 

    Substituting the given value of temperature in o F ,we get

    -40o F  

    = ( o C  x  1.8 )

    ∴   C

    =  - (72 / 1.8 )

     -40o C 

  • Question 8
    1 / -0

    -122 °C in Fahrenheit scale is

    Solution

    Calculations  :

    °F

    =[ (°C x 9/5 ) + 32 ]

    Substituting  the given temperature in o C   we get,

      oF

    =  [ ( -122  x  1.8  )   +    32 ]

    =   ( -219.6  +  32  )

    =   - 187.6

  • Question 9
    1 / -0

    27 °C is  eqal to --------------K ?

    Solution

    Since ,  0 C  

     =  273.15 K

    ∴ 27o C          

      =    ( 273.15  +   27 ) K

    = 300.15 K 

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