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Some Basic Concepts of Chemistry Test - 23

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Some Basic Concepts of Chemistry Test - 23
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  • Question 1
    1 / -0
    If an equivalent weight of an element is $$32$$, then the percentage of oxygen in its oxide is : 
    Solution
    If an equivalent weight of an element is $$32$$, then it will combine with $$8$$ g of oxygen to form metal oxide (from the definition of equivalent weight).
    So, % of oxygen $$=8\times \dfrac{100}{40} = 20$$
  • Question 2
    1 / -0
    Which of the following has the largest mass of carbon per gram?
    Solution
    Compound             Mass of carbon per gram
    (a)$$H_2CO_3                  =   \dfrac{12}{62}g$$ carbon
    (b)$$CH_3CO_2H         = \dfrac{24}{60}g$$ carbon
    (c)$$CH_3OH                 =     \dfrac{12}{32}g$$ carbon
    (d)$$CH_3CH_2OH       = \dfrac{24}{40}g$$ carbon (maximum)
    Hence, largest mass of carbon per gram is for  
    $$CH_3CH_2OH$$.
  • Question 3
    1 / -0
    All the substances listed below are fertilizers that contribute nitrogen to the soil. Which of these is the richest source of nitrogen on a mass percentage basis?
    Solution
    Compound                                  %N
    Urea $$(NH_2)_2CO$$                        $$28\times 100/60 = 46.67\%$$
    Ammonia $$NH_3$$           
                      $$14\times 100/17 = 82.35\%$$
    Ammonium nitrate $$NH_4NO_3      $$     
     $$28\times 100/80 =35\%$$
    Guanidine $$HNC(NH_2)_2$$            
    $$42\times 100/59 = 71.18\%$$
    Hence, ammonia is the richest source of nitrogen on a mass percentage basis.
  • Question 4
    1 / -0
    What is the mass percent of carbon in carbon dioxide?
    Solution
    Molecular formula of carbon dioxide is $$CO_2$$.
    Molar mass of carbon dioxide is $$12+2(16)=44$$ g/mol.
    Mass percentage of carbon in carbon dioxide is $$\dfrac {12} {44} \times 100 =27.27\%$$.
  • Question 5
    1 / -0
    Cost of a fertilizer is based on the percentage of nitrogen in it. Which of the fertilizers should be priced maximum?
    Solution
    Molecular weight of $$NH_4NO_3$$ is 80, $$NH_2CONH_2$$ is 60, and $$KNO_3$$ is 101.

    Percentage of $$N$$ in:

    $$NH_4NO_3=\displaystyle\dfrac{28\times 100}{80} = 35\% $$

    $$NH_2CONH_2=\displaystyle\frac{28\times 100}{60} = 46.7\% $$   

    $$KNO_3=\displaystyle\frac{14}{101}\times 100 = 13.9\%$$    

    Urea, having the highest percentage of nitrogen, should have the highest cost.

    Hence, option B is correct.
  • Question 6
    1 / -0
    Cortisone is a molecular substance containing $$21$$ atoms of carbon per molecule. The mass percentage of carbon in cortisone is $$69.98\%$$. It's molar mass is:
    Solution
    Let molar mass be$$=M$$

    Mass of $$21$$ carbon atoms$$=252$$

    $$\%$$ of carbon $$=\displaystyle\frac{252\times 100}{M}=69.98$$

    but %  of carbon = 69.98 %

    $$\therefore M=360.1$$

    Hence, the correct option is $$D$$
  • Question 7
    1 / -0
    A certain metal sulphide, $$MS_2$$, is used extensively as a high temperature lubricant. If $$MS_2$$ is $$40.06\%$$ by mass of sulphur, metal $$M$$ has atomic mass :
    Solution
    Molecular weight of $$MS_2=2S + M$$
    $$\dfrac {64}{M+64} =  0.4006$$
    $$\therefore    M=96$$
  • Question 8
    1 / -0
    Which has maximum percentage of $$Cl$$?
    Solution
    Compound                 % Cl
    $$C_6H_6Cl_6$$             $$6\times \dfrac{35.5}{78} + 35.5\times 6 = \dfrac{213}{291} = 73.2\%$$

    $$CHCl_3$$                 $$3\times \dfrac{35.5}{119.5} = \dfrac{106.5}{119.5} = 89.1\%$$

    $$C_6H_5Cl$$              $$\dfrac{35.5}{112.5} = 31.6\% $$

    $$CH_3Cl$$                $$\dfrac{35.5}{50.5} = 70.3\%$$
    Hence, the maximum percentage of chlorine is present in $$CHCl_3$$.
  • Question 9
    1 / -0
    $$Na_2SO_3\cdot xH_2O$$ has $$50\%$$ $$H_2O$$ by mass. Hence, $$x$$ is :
    Solution
    Molecular mass of $$Na_2SO_3\cdot xH_2O=126+18x$$
    Hence, $$\displaystyle\frac{18x}{126+18x}=0.5$$ (given)
    $$\therefore x=7$$
  • Question 10
    1 / -0
    Which pair has the same percentage of carbon?
    Solution
    The table below shows the simple ratio between the number of atoms.
    $$Compound$$                         $$C$$            $$H$$$$O$$
    $$CH_3COOH$$1    2                       1
    $$C_6H_12O_6$$1  21
    $$C_2H_5OH$$2    61
    $$C_{12}H_{22}O_{11}$$12  2211
    So, $$CH_3COOH$$  and $$C_6H_{12}O_6$$ have same % of $$C$$.
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