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Some Basic Concepts of Chemistry Test - 29

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Some Basic Concepts of Chemistry Test - 29
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  • Question 1
    1 / -0
    A compound was found to contain 5.37% nitrogen. What is the minimum molecular weight of compound?
    Solution
    5.37 9 N is present in 100 9 compound
    14gN =$$\frac {100 \times 14}{5.37}=260.7 $$g compound (i.e., minimum molecular weight as it should have atleast one N).
  • Question 2
    1 / -0
    A chemical equation is balanced in accordance with the law of
    Solution
    There must be the same number of each element on both side of the chemical equation. It adheres with the conservation of mass.
    Option $$A$$ is correct.
  • Question 3
    1 / -0
    A sample of $$CaCO_3$$ has $$Ca=40\%,\,C=12\%$$ and $$O=48\%$$. If the law of constant proportion is true then the weight of $$Ca$$ in $$16\;g$$ of $$CaCO_3$$ made from different processes will be
    Solution
    Gram Molecular Mass of $$CaCO_3$$
    $$=40+12+16\times3=40+12+48=100\;gm$$
    $$100\;gm\;CaCO_3$$ contain $$=40\;g\;Ca$$
    $$\therefore\;16\;g\;CaCO_3$$ will contain $$=\displaystyle\frac{40}{100}\times16=6.4\;g\;Ca$$
  • Question 4
    1 / -0
    A sample of $$CaCO_3$$ has Ca =40%, C = 12% and O = 48% by mass. If the law of constant proportion is true then the weight of Ca in 16g of $$CaCO_3$$ made from different processes will be -
    Solution
    Molecular weight of $$CaCO_3$$ = 100g
    Percentage of Ca = 40 %
    Let, law of constant proportion is true.

    So, mass of Ca in 100 g of $$CaCO_3$$ = $$\dfrac{40}{100} \times 100 = 40g$$

    So, weight of Ca in 16g of $$CaCO_3 $$ = $$\dfrac{40}{100} \times 16g = 6.4g$$
  • Question 5
    1 / -0
    Three containers A, B and C of equal volume, contain $$N_2$$, $$NO_2$$ and $$CO_2$$ respectively, at the same temperature and pressure. The ascending order of their masses is:
    Solution
    Since the ideal gas equation is same for all the gases, there will be same number of moles of each gas. Hence, the ascending order of their masses is the ascending order of their molecular weight.
    Molecular weight of $${ N }_{ 2 }=$$ 28
    Molecular weight of $${ NO }_{ 2 }=$$ 46
    Molecular weight of $${ CO }_{ 2 }=$$ 44
    Hence, the correct order would be A, C, B .
  • Question 6
    1 / -0
    A sugar solution contains $$15\%$$ sugar by weight. When the solution is heated, $$40\%$$ sugar is left in the solution. The amount of water which is disappeared is:
    Solution
    Let the mass of solution $$=100\;g$$
    Mass of sugar $$=15\;g$$
    Mass of water $$=100-15=85\;g$$
    On heating some amount water is disappeared and let the new amount of solution is $$(X)\;g$$, which contain $$40\%$$ sugar equal to $$15\;g$$
    $$X\times\displaystyle\frac{40}{100}=15$$
    $$x=37.5\;g$$
    After heating mass of solution is $$=37.5\;g$$
    Mass of water = Mass of solution - Mass of water
    $$=37.5-15=22.5$$
    Amount of water disappeared on heating
    $$=(85-22.5)=62.5\;g$$
  • Question 7
    1 / -0
    One mole of any substance contains $$6.023\times10^{23}$$ particles. It was determined by
    Solution
    Avogadro's law states that in one mole of any substance, a total number of $$6.023 \times 10^{23}$$ molecules are present. 
    So, option $$B$$ is correct.
  • Question 8
    1 / -0
    Which atom contains exactly 15 neutrons?
    Solution
    $$mass\space number= no. of \space protons + no. of\space neutrons$$
    Given that mass number of P = 32 
    Atomic number (no. of electrons $$=$$ no. of protons) $$=$$ 17
    Number of neutrons $$= 32 - 17 = 15$$
    Hence, P satisfies the requirement. 
  • Question 9
    1 / -0
    In a chemical reaction, when 14 g of sodium carbonate reacted with 10g of acetic acid (ethanoic acid), then it was observed that, 16.67 g of sodium acetate solution in water and 7.33 g of carbon dioxide were produced. Which law does this depicts?
    Solution
    In the given reaction,
    $$\underset {(14g)}{\text {Sodium carbonate}}+\underset {(10g)}{\text {Ethanoic acid}}\Rightarrow \underset {(16.67)}{(Sodium  ethanoate+water)}+\underset {(7.33 g)}{Carbon   dioxide  gas}$$
    Total mass of all reactants combined
    $$=14 g+10 g=24 g$$
    Total mass of all the products formed
    $$= 16.67 g + 7.33 g =24 g$$.
    It is observed that Total mass of all reactants combined $$= 24 g =$$ Total mass of all the products formed. Therefore, the given observations are in agreement with the law of conservation of mass.
  • Question 10
    1 / -0
    How much MgO is obtained on heating 5 gm of $$\displaystyle \left ( MgCO_{3} \right )$$ Magnesium carbonate?
    Solution
    $$\displaystyle MgCO_{3}\rightarrow MgO+CO_{2}$$
    Molecular weight of $$\displaystyle MgCO_{3}$$
    = 24 + 12 +16 x 3 = 84
    Molecular weight of MgO
    = 24 + 16 = 40
    On heating 84 gms of $$\displaystyle MgCO_{3}$$ the quantity of MgO obtained
    = 40 gms
    $$\displaystyle \therefore $$ On heating 5 gms of $$\displaystyle MgCO_{3}$$ the quantity of MgO obtained
    $$\displaystyle = \frac{40}{84}  X  5gms$$
    = 2.38 gms
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