Some Basic Concepts of Chemistry Test

Result

Some Basic Concepts of Chemistry Test - 57

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

"One gram moecule of gas at N.T.P occupies $$22.4$$ litres." This fact was derived from?

A
Dalton's therory

B
Avogadro's hypothesis

C
Berzelius hypothesis

D
Law of gaseous volume

Solution

Finding relationship between gram molecule and volume of gas is an application of Avogadro's Hypothesis.
Result of this application is "One gram molecule of a gas at N.T.P. occupies 22.4 litres"

Hence, Option "B" is the correct answer.
Question 2
1 / -0

A $$0.60g$$ sample consisting of only $$Ca{C}_{2}{O}_{4}$$ and $$Mg{C}_{2}{O}_{4}$$ is heated at $${500}^{o}C$$, converting the two salts of $$Ca{CO}_{3}$$ and $$Mg{CO}_{3}$$. The sample then weighs $$0.465g$$. If the sample had been heated to $${900}^{o}C$$, where the products are $$CaO$$ and $$MgO$$, what would the mixtures of oxides have weighed?

A
$$0.12g$$

B
$$0.21g$$

C
$$0.252g$$

D
$$0.3g$$

Solution
Question 3
1 / -0

If mass percentage of iron in a biomolecule is 0.4% then the minimum molecular weight of biomolecule will be (Atomic weight of Fe = 56)

A
18000

B
16000

C
10000

D
14000

Solution
Question 4
1 / -0

Zinc sulphate contains 22.65% Zn and 43.9% $$ \mathrm { H } _ { 2 } \mathrm { O } $$ . if the law of constant proportions is true, then the mass of Zinc required to give 40g crystal will be

A
90.6 g

B
9.06 g

C
0.906 g

D
906 g

Solution
Question 5
1 / -0

60 g of solution containing 40% by mass of $$NaCl$$ are mixed with 100 g of a solution containing 15% by mass $$NaCl$$. Determine the mass percent of sodium chloride in the final solution.

A
24.4 %

B
78 %

C
48.8 %

D
19.68 %

Solution

$$Mass \ of \ NaCl \ in \ 40\% \ solution=\dfrac{40}{100}\times{60}=24g$$

$$Mass \ of \ NaCl \ in \ 15\% \ solution=\dfrac{15}{100}\times{100}=15g$$
$$Total \ mass \ of \ NaCl \ in \ resulting \ solution=24+15=39g$$
$$Total \ mass \ of \ final \ solution=60+100=160g$$
$$Mass \ percent \ of \ NaCl \ in \ final \ solution=\dfrac{39}{160}\times{100}=24.4\%$$
Question 6
1 / -0

The weight of $$C{H_4}$$ in 9-L cylinder at $${27^0}C$$ temperature and $$16$$ atm pressure is ($$R=0.08$$ L atm $${K^{ - 1}}\,mo{l^{ - 1}}$$).

A
$$9.6$$ g

B
$$96.0$$ g

C
$$4.8$$ g

D
$$48.0$$ g

Solution

Using the ideal gas equation,
$$PV=nRT$$
$$16atm\times 9L=n\times 0.082\times 300K$$ .....(given)
Therefore, n=6
$$n=\dfrac{Weight}{atomic mass}$$
weight of $$CH_4=16g{mol}^{-1}\times 6mol=96g$$
Question 7
1 / -0

Which of the following represents the Avogadro number?

A
Number of molecule present in 1 L of gas at N.T.P

B
Number of molecule present in 22.4 L of gas at N.T.P

C
Number of molecule present in 22.4 of gas at 298K and 1 atm pressure

D
Number of molecule present in one mole of gas at any temp and pressure

Solution

Avogadro number is defined as the number of gas molecules present in one mole of gas at any pressure and temperature. It's value is $$6.023 \times 10^{23}$$. So the correct option is D
Question 8
1 / -0

What is the value of $$n$$ in the following equation?

$$Cr\left( OH \right) _{ 4 }^{ - }+OH^{ - }\longrightarrow Cr{ O }_{ 4 }^{ 2- }+H_{ 2 }O\ +\ ne^-$$

A
$$3$$

B
$$6$$

C
$$5$$

D
$$2$$

Solution

The given reaction is
$$[Cr(OH)_{4}]^{-}+ OH^{-} \rightarrow [CrO_{4}]^{-2} +H_{2}O+ne^{-}$$
Now balancing the equation, $$2[Cr(OH)_{4}]^{-}+ 8OH^{-} \rightarrow 2[CrO_{4}]^{-2} +8H_{2}O+6e^{-}$$. So the value of n is 6. Correct option is B
Question 9
1 / -0

Mass of the one atom of the element X is $$1.66 \times 10^{-26}$$ g. Number of atoms in 1 g of the element is:

A
$$1.66 \times 10^{-26}$$

B
$$1.66 \times 10^{25}$$

C
$$1.66 \times 10^{-24} x No$$

D
$$6.024 \times 10^{25}$$

Solution

Mass of one atom = $$1.66 \times 10^{-26} g$$
$$1.66 \times 10^{-26} gm \rightarrow 1 \, atom$$
$$1 \, gm \rightarrow \dfrac{1}{1.66 \times 10^{-26}} $$ atom
$$= 6.024 \times 10^{25} atom$$
Question 10
1 / -0

A sample of potato starch was ground in ball mill to give a starch lime molecule of lower molecular weight. The product analysed $$0.86\%$$ phosphorus. If each molecule is assumed to contain one atom of phosphorus.The molecular weight of the material is:-

A
$$3.6\times 10^{6}$$

B
$$4.9\times 10^{4}$$

C
$$7.2\times 10^{6}$$

D
$$3.6\times 10^{4}$$

Solution

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Some Basic Concepts of Chemistry Test - 57

Result

Some Basic Concepts of Chemistry Test - 57

Score

-

Rank

-

SHARING IS CARING

Question 1

Dalton's therory

Avogadro's hypothesis

Berzelius hypothesis

Law of gaseous volume

Solution

Question 2

$$0.12g$$

$$0.21g$$

$$0.252g$$

$$0.3g$$

Solution

Question 3

18000

16000

10000

14000

Solution

Question 4

90.6 g

9.06 g

0.906 g

906 g

Solution

Question 5

24.4 %

78 %

48.8 %

19.68 %

Solution

Question 6

$$9.6$$ g

$$96.0$$ g

$$4.8$$ g

$$48.0$$ g

Solution

Question 7

Number of molecule present in 1 L of gas at N.T.P

Number of molecule present in 22.4 L of gas at N.T.P

Number of molecule present in 22.4 of gas at 298K and 1 atm pressure

Number of molecule present in one mole of gas at any temp and pressure

Solution

Question 8

$$3$$

$$6$$

$$5$$

$$2$$

Solution

Question 9

$$1.66 \times 10^{-26}$$

$$1.66 \times 10^{25}$$

$$1.66 \times 10^{-24} x No$$

$$6.024 \times 10^{25}$$

Solution

Question 10

$$3.6\times 10^{6}$$

$$4.9\times 10^{4}$$

$$7.2\times 10^{6}$$

$$3.6\times 10^{4}$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.