Some Basic Concepts of Chemistry Test

Directions For Questions

The strength of

H_{2}O_{2}

is expressed in several ways like molarity, normality, % (w/v), volume strength etc. The strength of

10\:V

means

1

volume of

H_{2}O_{2}

on decomposition gives

10

volumes of oxygen at

STP

1

litre of

H_{2}O_{2}

gives

10

litre of

O_{2}

STP

. The decomposition of

H_{2}O_{2}

is shown as under:

H_{2}O_{2} (aq) \rightarrow H_{2}O(l)+\displaystyle \frac {1}{2} O_{2} (g)

H_{2}O_{2}

can acts as oxidising as well as reducing agent. As oxidizing agent,

H_{2}O_{2}

converted into

H_{2}O

and as reducing agent,

H_{2}O_{2}

converted into

O_{2}

. In both the cases, its

n

-factor is

2

\therefore

Normality of

H_{2}O_{2}

solution

= 2 \times

Molarity of

H_{2}O_{2}

solution.

...view full instructions

$40\: g\: Ba(MnO_{4} )_{2}$ (mol. wt. $= 375$ g/mol) sample containing some inert impurities in acidic medium is completely reacted with $125$ mL of $33.6\: V$ of $H_{2}O_{2}$ . What is the percentage purity of the sample?

Some Basic Conc...

Question 1

10 ml10\ ml10 ml

20 ml20\ ml20 ml

30 ml30\ ml30 ml

25 ml25\ ml25 ml

Question 2

45.45%45.45\%45.45%

43.34%43.34\%43.34%

34.23%34.23\%34.23%

35.67%35.67\%35.67%

Question 3

30

35

40

46

Question 4

30 ml

40 ml

43 ml

49 ml

Question 5

28.12%28.12 \%28.12%

70.31%70.31 \%70.31%

85%85 \%85%

None of the above

Question 6

707070 ml

757575 ml

808080 ml

828282 ml

Question 7

CH4=4.5ml,CO2=1.5mlCH_{4}= 4.5 ml, CO_{2}= 1.5 mlCH4​=4.5ml,CO2​=1.5ml

CH4=3.6ml,CO2=2.5mlCH_{4}= 3.6 ml, CO_{2}= 2.5 mlCH4​=3.6ml,CO2​=2.5ml

CH4=4.8ml,CO2=1.8mlCH_{4}= 4.8 ml, CO_{2}= 1.8 mlCH4​=4.8ml,CO2​=1.8ml

CH4=5.1ml,CO2=2.8mlCH_{4}= 5.1 ml, CO_{2}= 2.8 mlCH4​=5.1ml,CO2​=2.8ml

Question 8

2:12:12:1

1:21:21:2

3:43:43:4

4:14:14:1

Question 9

C2H2=16ml,CO=24ml\displaystyle\:C_{2}H_{2}= 16 ml, CO= 24 mlC2​H2​=16ml,CO=24ml

C2H2=23ml,CO=14ml\displaystyle\:C_{2}H_{2}= 23 ml, CO= 14 mlC2​H2​=23ml,CO=14ml

C2H2=30ml,CO=26ml\displaystyle\:C_{2}H_{2}= 30 ml, CO= 26 mlC2​H2​=30ml,CO=26ml

C2H2=33ml,CO=28ml\displaystyle\:C_{2}H_{2}= 33 ml, CO= 28 mlC2​H2​=33ml,CO=28ml

Question 10

46.67%46.67\%46.67%

23.34%23.34\%23.34%

60.00%60.00\%60.00%

20.00%20.00\%20.00%

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$10\ ml$

$20\ ml$

$30\ ml$

$25\ ml$

$45.45\%$

$43.34\%$

$34.23\%$

$35.67\%$

$28.12 \%$

$70.31 \%$

$85 \%$

$70$ ml

$75$ ml

$80$ ml

$82$ ml

$CH_{4}= 4.5 ml, CO_{2}= 1.5 ml$

$CH_{4}= 3.6 ml, CO_{2}= 2.5 ml$

$CH_{4}= 4.8 ml, CO_{2}= 1.8 ml$

$CH_{4}= 5.1 ml, CO_{2}= 2.8 ml$

$2:1$

$1:2$

$3:4$

$4:1$

$\displaystyle\:C_{2}H_{2}= 16 ml, CO= 24 ml$

$\displaystyle\:C_{2}H_{2}= 23 ml, CO= 14 ml$

$\displaystyle\:C_{2}H_{2}= 30 ml, CO= 26 ml$

$\displaystyle\:C_{2}H_{2}= 33 ml, CO= 28 ml$

$46.67\%$

$23.34\%$

$60.00\%$

$20.00\%$