Some Basic Concepts of Chemistry Test

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Some Basic Concepts of Chemistry Test - 9

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Weekly Quiz Competition

Question 1
1 / -0

Given that Avagadro’s Number

= 6.02 x 10²³ atoms/mol ,

the number of hydrogen atoms in 18g of water is.

A
1.204 x 10²³

B
3. 204 x 10²⁴

C
1. 204 x 10²⁴

D
2. 204 x 10²⁴

Solution

Since,18g H₂O

= 1mol water containing 6.02 x 10²³ molecules of water (H₂O )

& the number of H atoms in 1 molecule of hydrogen (H₂) = 2

∴∴ the number of H atoms in 6.02 x 10²³ molecules

= (6.02 x 10²³ x 2)

=1.204 x 10²⁴.
Question 2
1 / -0

There are ___m in 2000 mm?

A
0.02 m

B
20 m

C
0.002 m

D
2 m

Solution

Since , 1 m

=1000 mm.

or, 1 mm

= 1/1000m

∴ 2000 mm

=[ 1/1000 X 2000 ] m

= 2 m
Question 3
1 / -0

There are ____ L in 0.05 ml?

A
5.0 liters

B
0.50 L

C
0.0005 liters

D
0.00005 L

Solution

Since , 1L

= 1000mL

or , 1mL

=1/1000 L .

∴ 0.05mL

= 1/1000 X 0.05L

= 0.00005 L .
Question 4
1 / -0

Choose the most appropriate option to complete the statement -

" Whenever there is a rearrangement of atoms which makes or breaks chemical bonds ------------------------ "

A
a chemical reaction takes place

B
catalysts are produced.

C
reactants disappear

D
products appear,

Solution

The occurance of a chemical reaction is always associated with breaking & formation of bonds of the reactant and products along with rearrangement of their atoms , hence the statement at option 1 is most appropriate. ie. " Whenever there is a rearrangement of atoms which makes or breaks chemical bonds a chemical reaction takes place."
Question 5
1 / -0

We have to prepare a Litre solution of 0.2 M NaOH from the available 1 M solution.

What volume of 1M NaOH is required to be taken ?

A
0.2 mL

B
20 mL

C
2 mL

D
200 mL

Solution

Since ,

total strength of given  solution

= total strength of prepared solution

∴ Apply the relation -

M1 x V1 = M2 x V2

where , M1= molarity of solution given= 1.0  M ,

V1 = volume of solution given= ?

& M2= molarity of solution to be prepared = 0.20 M (given )

V2 = volume of solution to be prepared = 1000 mL ( given )

Substiuting the given values we get ,

1.00M x V1 = 0.20 ×1000

V1= ( 0.20 × 1000) / 1.00

V1 =   200 mL
Question 6
1 / -0

20 m/s is the same as:

A
200 cm/s

B
0.002 mm/s

C
2000 mm/s

D
0.02 km/s

Solution

Since , 1000 m

= 1 km

∴ 20 m

= 20/1000 km

= 0.02 km

Hence , 20 m / s = 0.02 km / s
Question 7
1 / -0

30 microliters is the same as:

A
0.03 mL

B
0.003 mL

C
0.0003 liters

D
3000000 liters

Solution

Since , 1 microliter

= 1 x10^-6liters ,

& 1ml

= 1 x 10^-3

∴ 1 microliter

= 0.001 mL

∴∴ 30 microliters

= ( 0.001 x 30 ) mL

= 0.03 mL
Question 8
1 / -0

20 grams is the same as:

A
1500 mg

B
2000 mg

C
200 mg

D
20000 mg

Solution

Since ,

1 g

= 1000 mg

∴ 20 g

= (20 x 1000 ) mg

= 20,000 mg

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Some Basic Concepts of Chemistry Test - 9

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Some Basic Concepts of Chemistry Test - 9

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Question 1

1.204 x 1023

3. 204 x 1024

1. 204 x 1024

2. 204 x 1024

Solution

Question 2

0.02 m

20 m

0.002 m

2 m

Solution

Question 3

5.0 liters

0.50 L

0.0005 liters

0.00005 L

Solution

Question 4

a chemical reaction takes place

catalysts are produced.

reactants disappear

products appear,

Solution

Question 5

0.2 mL

20 mL

2 mL

200 mL

Solution

Question 6

200 cm/s

0.002 mm/s

2000 mm/s

0.02 km/s

Solution

Question 7

0.03 mL

0.003 mL

0.0003 liters

3000000 liters

Solution

Question 8

1500 mg

2000 mg

200 mg

20000 mg

Solution

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1.204 x 10²³

3. 204 x 10²⁴

1. 204 x 10²⁴

2. 204 x 10²⁴