The p-Block Elements Test

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The p-Block Elements Test - 17

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Weekly Quiz Competition

Question 1
1 / -0

The structure of silica is :

A
Layer lattice

B
Tetrahedral

C
Trigonal

D
Linear

Solution

Silica exists as a polymeric solid, in which each Silicon atom is bonded to 4 oxygen atoms and each oxygen atom is bonded to 2 silicon atoms. Thus, in this structure, each silica molecule has a tetrahedral structure, with silicon atom having $$sp^3$$ hybridisation.
Question 2
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Which one of the following is true with respect to $$SiO_{2}$$?

A
Linear, acidic

B
Linear, basic

C
Tetrahedral, acidic

D
Angular, basic

Solution

$$SiO_2$$ is acidic in nature and is used as an acidic flux in metallurgy. Silicon in $$SiO_2$$ is $$sp^3$$ hybridised which gives it a tetrahedral structure.
Hence, option C is the correct answer.
Question 3
1 / -0

Silicones are:

A
conductors

B
insulators

C
semiconductors

D
used to prepare graphite

Solution

Hint: Silicon belongs to the p-block. It is in the carbon group.

Explanation:

Silicones are a variety of synthetic polymers which have a repeating chemical unit in a long chain.

A silicon-oxygen backbone with hydrogen and/or hydrocarbon groups linked to the silicon atoms makes up silicone. Organic silicon polymers with $$Si-O-Si$$ links belong to this category.

Silicones are chemically inert and repel water. They can be utilized as semiconductors since they are consist of $$Si$$ units.

Hence, the correct answer is $$C$$.
Question 4
1 / -0

Which oxides has three dimensional structure ?

A
CO

B
$$CO_{2}$$

C
$$SiO_{2}$$

D
$$SO_{2}$$

Solution

$$CO$$, $$CO_2$$ are linear molecules whereas $$SO_2$$ is a bent shaped molecule. However, $$SiO_2$$ is 3-d shaped due to $$sp_3$$ hybridisation of silicon.
Question 5
1 / -0

Organosilicon polymers containing which type of linkages:

A
Si-S-Si

B
Si-O-Si

C
Si-N-Si

D
Si-C-Si

Solution

Organosilicon compounds have general formula $$[R_{2} SiO]_{n}$$.
Question 6
1 / -0

Hybridisation of silicon atom in silica is :

A
sp

B
$$sp^{2}$$

C
$$sp^{3}$$

D
$$sp^{3}d$$

Solution

Silicon in silica forms 4 sigma bonds thus its hybridisation is $$sp_3$$.
Question 7
1 / -0

Which is not a true dioxide?

A
$$CO_{2}$$

B
$$SO_{2}$$

C
$$MnO_{2}$$

D
$$SiO_{2}$$

Solution

Silicon dioxide is a three dimensional network solid in which each Si-atom is covalently bonded in tetrahedral manner with four oxygen atom while in $$CO_2$$, $$SO_2$$ and $$MnO_2$$. C, S and Mn atoms are bonded to oxygen atom by either $$\pi$$-bond or coordinate covalent bonds.
$$SiO_2 + 4HF \rightarrow SiF_4 + 2H_2O$$
Question 8
1 / -0

The structure of crystalline silica is similar to that
of:

A
Diamond

B
Graphite

C
Silicates

D
Silicic acid

Solution

The structure of silica is very similar to that of diamond, with each silicon atom having tetrahedral bond and bonded to 4 oxygen atoms, which in turn are connected to another silicon atom, thus effectively, each C-C bond of diamond has been replaced by a Si-O-Si link to give the silica lattice.
Question 9
1 / -0

The major product formed when alkyl chloride when passed over silicon at 300$$^{\circ}$$C in the presence of Cu catalyst?

A
$$R-S-Cl_{2}$$

B
$$R_{2}-SiCl_{2}$$

C
$$R_{2}-SiCl$$

D
$$R_{4}-Si$$

Solution

$$R_{2} - SiCl_{2}$$ (Major product)
$$R_{3} - SiCl, R - SiCl_{3} $$ (Minor products)
Question 10
1 / -0

Which of the following is/are not correct?

A
$$SiO_{2}$$is used as acid flux.

B
The distance between the layers in graphite is $$3.35\times10^{-8}$$cm.

C
$$SiO_{2}$$reacts with $$Na_{2}CO_{3}$$ and liberates CO.

D
The hybridization of C in graphite is $$Sp^{2}$$.

Solution

$$CO_2$$ is released when $$SiO_2$$ reacts with $$Na_2CO_3$$.
$$SiO_2 + Na_2CO_3 \rightarrow Na_2SiO_3 + CO_2$$

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 17

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The p-Block Elements Test - 17

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SHARING IS CARING

Question 1

Layer lattice

Tetrahedral

Trigonal

Linear

Solution

Question 2

Linear, acidic

Linear, basic

Tetrahedral, acidic

Angular, basic

Solution

Question 3

conductors

insulators

semiconductors

used to prepare graphite

Solution

Question 4

CO

$$CO_{2}$$

$$SiO_{2}$$

$$SO_{2}$$

Solution

Question 5

Si-S-Si

Si-O-Si

Si-N-Si

Si-C-Si

Solution

Question 6

sp

$$sp^{2}$$

$$sp^{3}$$

$$sp^{3}d$$

Solution

Question 7

$$CO_{2}$$

$$SO_{2}$$

$$MnO_{2}$$

$$SiO_{2}$$

Solution

Question 8

Diamond

Graphite

Silicates

Silicic acid

Solution

Question 9

$$R-S-Cl_{2}$$

$$R_{2}-SiCl_{2}$$

$$R_{2}-SiCl$$

$$R_{4}-Si$$

Solution

Question 10

$$SiO_{2}$$is used as acid flux.

The distance between the layers in graphite is $$3.35\times10^{-8}$$cm.

$$SiO_{2}$$reacts with $$Na_{2}CO_{3}$$ and liberates CO.

The hybridization of C in graphite is $$Sp^{2}$$.

Solution

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