The p-Block Elements Test

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The p-Block Elements Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

Diamond is covalent, yet it has high melting point. because of

A
planar structure with strong C-C bonds difficult to break

B
sp² hybridisation with strong C-C bonds difficult to break

C
the presence of rigid three dimensional extended network thought the lattice.

D
2-dimensional network with strong C-C bonds difficult to break

Solution

carbon atom undergoes Sp³hybridization and linked to four other carbon atoms by using hybridized orbitals in tetrahedral fashion led a rigid three dimensional extended network thought the lattice.
Question 2
1 / -0

The valence shell electronic configuration of p-block elements is ns²np^{1 - 6} But this is not true in the case of

A
Helium

B
nitrogen

C
carbon

D
Boron

Solution

As only one I^st period element of p-block, it has unique 1s² configuration besides other element of that block (ns²np^{1 - 6}) . It is a noble gas.
Question 3
1 / -0

Cohen Orthoboric acid (H₃BO₃) is strongly heated, the residue is

A
Boron

B
Al₂O₃, 2H₂O

C
Meta boric acid

D
None of these

Solution

Meta boric acid
Question 4
1 / -0

Me₃SiCl is used during polymerisation of organo silicones because

A
Me₃ SiCl improves the quality and yield of the polymer

B
Me₃ SiCl acts as a catalyst during polymerisation

C
to control the chain length of the polymer

D
Me3 SiCl does not block the end terminal of silicone polymer

Solution

the chain length of the polymers can be controlled by adding Me₃SiCl which blocks the ends of the chain to produce silicone
Question 5
1 / -0

Which of the following statements are correct?

A
Fullerenes have dangling bonds

B
Graphite is slippery and hard and therefore used as a dry lubricant in Machines

C
Fullerenes are cage-like molecules

D
Graphite is thermodynamically not stable allotrope of carbon

Solution

Fullerence have cage like spheroidal molecular ( C₆₀₎ structure and have no dangling bonds.
Question 6
1 / -0

Which one of the following orders correctly represents the increasing acid strengths of the given acids?

A
HOClO₂< HOClO₃< HOClO < HOCl

B
HOCl < HOClO < HOClO₂< HOClO₃

C
HOClO < HOCl < HOClO₃< HOClO₂

D
HOClO₃< HOClO₂< HOClO < HOCl

Solution

Acidity increases as the number of terminal oxygen atom attached to the halogen (cl) atom because of inductive-effect
Question 7
1 / -0

Regular use of which of the following fertilizers increases the acidity of the soil?

A
Urea

B
Potassium nitrate

C
Superphosphate of lime

D
Ammonium sulphate

Solution

Ammonium sulphate addition increases acidity in the soil.

In the presence of water and oxygen in the soil, ammonium and sulfate are decomposed by naturally occurring microbes. During this process, acids are released into the soil, along with nitrogen and sulfur compounds.
Question 8
1 / -0

The percentage of p-character in the orbitals forming P - P bonds in P₄ is

A
33

B
25

C
50

D
75

Solution

The species P₄has a tetrahedron structure. Each P involves SP³ hybrid orbital. Hence p-character will be 75
Question 9
1 / -0

When Cl₂ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

A
Zero to + 1 and zero to –5

B
Zero to – 1 and zero to +5

C
Zero to + 1 and zero to –3

D
Zero to – 1 and zero to +3

Solution

reaction of Cl₂ and hot and concentrated sodium hydroxide solution is as below:

6 NaOH + 3Cl₂ → 5NaCl + NaClO₃ + 3H₂O

Here Cl₂ disproportionate to -1 and +5
Question 10
1 / -0

In which of the following compounds, nitrogen exhibits highest oxidation state?

A
NH₃

B
NH₂OH

C
N₂H₄

D
N₃H

Solution

N₃H is Hydrazoic acid and can be seen as N₃^- H+.

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The p-Block Elements Test - 6

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The p-Block Elements Test - 6

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Question 1

planar structure with strong C-C bonds difficult to break

sp2 hybridisation with strong C-C bonds difficult to break

the presence of rigid three dimensional extended network thought the lattice.

2-dimensional network with strong C-C bonds difficult to break

Solution

Question 2

Helium

nitrogen

carbon

Boron

Solution

Question 3

Boron

Al2O3, 2H2O

Meta boric acid

None of these

Solution

Question 4

Me3 SiCl improves the quality and yield of the polymer

Me3 SiCl acts as a catalyst during polymerisation

to control the chain length of the polymer

Me3 SiCl does not block the end terminal of silicone polymer

Solution

Question 5

Fullerenes have dangling bonds

Graphite is slippery and hard and therefore used as a dry lubricant in Machines

Fullerenes are cage-like molecules

Graphite is thermodynamically not stable allotrope of carbon

Solution

Question 6

HOClO2< HOClO3< HOClO < HOCl

HOCl < HOClO < HOClO2< HOClO3

HOClO < HOCl < HOClO3< HOClO2

HOClO3< HOClO2< HOClO < HOCl

Solution

Question 7

Urea

Potassium nitrate

Superphosphate of lime

Ammonium sulphate

Solution

Question 8

33

25

50

75

Solution

Question 9

Zero to + 1 and zero to –5

Zero to – 1 and zero to +5

Zero to + 1 and zero to –3

Zero to – 1 and zero to +3

Solution

Question 10

NH3

NH2OH

N2H4

N3H

Solution

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sp² hybridisation with strong C-C bonds difficult to break

Al₂O₃, 2H₂O

Me₃ SiCl improves the quality and yield of the polymer

Me₃ SiCl acts as a catalyst during polymerisation

HOClO₂< HOClO₃< HOClO < HOCl

HOCl < HOClO < HOClO₂< HOClO₃

HOClO < HOCl < HOClO₃< HOClO₂

HOClO₃< HOClO₂< HOClO < HOCl

NH₃

NH₂OH

N₂H₄

N₃H