Organic Chemistry Some Basic Principles and Techniques Test

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Organic Chemistry Some Basic Principles and Techniques Test - 32

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Weekly Quiz Competition

Question 1
1 / -0

The IUPAC name for the hydrocarbon represented by:

A
3, 3-diethylpentane

B
2-ethylpentane

C
tetraethyl carbon

D
neo-nonane

Solution

3, 3-diethylpentane
Question 2
1 / -0

Passing $${H}_{2}S$$ gas into a mixture of $${ Mn }^{ 2+ },{ Ni }^{ 2+ },{ Cu }^{ 2+ },{ Hg }^{ 2+ }$$ ions in acidified aqueous solution precipitates:

A
$$CuS$$ and $$HgS$$

B
$$MnS$$ and $$CuS$$

C
$$MnS$$ and $$NiS$$

D
$$NiS$$ and $$HgS$$

Solution

$${Cu}^{2+}$$ and $${Hg}^{2+}$$ lie in IInd group of qualitative analysis $${H}_{2}S$$ in acid medium is reagent for it.
$$HCl\rightarrow {H}^{+}+{Cl}^{-}$$
$${H}_{2}S\leftrightharpoons 2{H}^{+}+{S}^{2-}$$
Question 3
1 / -0

Identify the compound 'D' in above mentioned series of reactions.

A

B

C

D

Solution

As $$-COOH$$ group is not electron donating,so maximum positive change will be on ortho position.
Question 4
1 / -0

Pi bond is formed between the two atoms when their is a:

A
donation of electron pair from one atom to another.

B
axial overlapping of atomic orbitals

C
transfer of one or more than one electron from one atom to another

D
lateral overlapping of atomic orbitals

Solution

Pi bond is a type of covalent bond formed when their is a lateral overlapping between the atomic orbitals of the two given atoms.
The one formed due to axial overlapping is called sigma bond, and due to lone pair donation is called coordinate bond.
Question 5
1 / -0

Among the given compounds 2, 3-dimethylhexane is:

A
i

B
ii

C
iii

D
iv

Solution

$$\displaystyle 2, 3-dimethylhexane $$ is compound $$\displaystyle ii$$. The parent chain contains 6 C atoms. Hence it is derivative of hexane. The numbering is started from the end which gives lowest locants to the substituents.
Question 6
1 / -0

How do we differentiate between $${ Fe }^{ 3+ }$$ and $${ Cr }^{ 3+ }$$ in group III?

A
By taking excess of $${ NH }_{ 4 }OH$$

B
By increasing $${ NH }_{ 4 }^{ + }$$ ion cocentration

C
By decreasing $${ OH }^{ - }$$ ion concentration

D
Both (b) and (c)

Solution

NH4+ ions are increased to suppress release of OH– ions, hence solubility product of Fe(OH)3 is attained. Colour of precipitate is different.
Question 7
1 / -0

What is the IUPAC name of the following compound ?

A
1, 2 - dimethyl cyclopropyl cyclohexane

B
1, 2 - dimethyl spiro [2, 5] octane

C
7, 8 - dimethyl spiro [5, 2] octane

D
1, 2 - dimethyl bicyclo [5, 2] octane

Solution

Two rings with one common atom produce a spiro ring system. Numbering follows the smaller path first, passing through the spiro carbon and around the second ring.
Question 8
1 / -0

In presence of $$HCl(aq.);{H}_{2}S$$ gas results the precipitation of group-2 cations but not of group-4 cations during qualitative analysis. It is due to:

A
Lower concentration of $${ S }^{ 2- }$$

B
Higher concentration of $${ S }^{ 2- }$$

C
Lower concentration of $${ H }^{ + } $$

D
Higher concentration of $${ H }^{ + }$$

Solution

Due to common ion effect, the ionisation of $${H}_{2}S$$ is suppressed and at low concentration of $${S}^{2-}$$ ions, the second group sulphides are precipitated.
Question 9
1 / -0

$$HCHO$$ and $$HCOOH$$ are detected by

A
$$NaH{ CO }_{ 3 }$$

B
$$Cu{ SO }_{ 4 }/NaOH$$

C
$$Ag{ NO }_{ 3 }/{ NH }_{ 4 }OH$$

D
All of these

Solution

Both $$HCHO$$ and $$HCOOH$$ react with $$Ag{ NO }_{ 3 }/{ NH }_{ 4 }OH\quad $$
$$Cu{ SO }_{ 4 }/NaOH\quad $$ solution. But $$HCOOH$$ gives effervescences of $${CO}_{2}$$ when reacts with $$NaH{ CO }_{ 3 }$$, whereas $$HCHO$$ does not give any effervescence of $${CO}_{2}$$ when reacts with $$NaH{ CO }_{ 3 }$$.
$$HCOOH+NaH{ CO }_{ 3 }\longrightarrow HCOONa+{ H }_{ 2 }O+{ CO }_{ 2 }\uparrow \quad $$
Question 10
1 / -0

Which of the following is among the major products of the reaction of (E)-3-methy1,2-pentene with $$BH_3$$ in THF followed by the addition of $$H_2O_2/HO^-$$?

A

B

C

D

Solution

So, the structure of $$3-$$ methyl $$2-$$ pentene .
The reagents $$BH_3$$ in Tetrahydrofuran followed by addition of $$H_2O_2/OH^-$$ is the reaction of oxidation called as Hydroboration oxidation. When an alkene undergoes hydroboration oxidation, we get alcohol as a result.