Organic Chemistry Some Basic Principles and Techniques Test

Result

Organic Chemistry Some Basic Principles and Techniques Test - 51

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following is an example of nucleophilic addition reaction?

A
$${\text{CH}} \equiv {\text{CH}} + {\text{C}}{{\text{l}}_{\text{2}}}\xrightarrow{{}}{\text{CHCl = CHCl}}$$

B
$${\text{HC}} \equiv {\text{CH}}\xrightarrow[{{\text{C}}{{\text{H}}_3}{\text{COOH}}}]{{{\text{HCl}}}}{\text{C}}{{\text{H}}_2}{\text{ = CHCl}}$$

C
$${\text{HC}} \equiv {\text{CH}} + {{\text{H}}_{\text{2}}}{\text{O}}\xrightarrow[{{\text{H}}{{\text{g}}^{2 \oplus }},\Delta }]{{{{\text{H}}^ \oplus }}}{\text{C}}{{\text{H}}_3} - {\text{CO}} - {\text{H}}$$

D
$${\text{H}} - {\text{C}} \equiv {\text{C}} - {\text{H}}\xrightarrow{{{\text{NaN}}{{\text{H}}_2}}}{\text{HC}} \equiv {{\text{C}}^{( - )}}{\text{N}}{{\text{a}}^ \oplus }$$

Solution
Question 2
1 / -0

The most reactive of C-X bond towards nucleophile in the following compound is

A

B

C
$$(CH_3)_3C-X$$

D
$$(CH_3)_2CH-X$$

Solution
Question 3
1 / -0

Which of the following reactions give same product

A

B

C

D
Question 4
1 / -0

In the given compound which functional group is absent ?

A
Ketone

B
Ether

C
Amide

D
Ester

Solution
Question 5
1 / -0

Which of the following is correct for hydbridization of C-atom?

A
$$CH_{4}-SP^{3}$$

B
$$C_{2}H_{4}-sp^{2}$$

C
$$C_{2}H_{2}-sp$$

D
All of these

Solution

CH4− Alkane SP3

C2H4- Alkene SP2
C2H2- Alkyne SP

Hence all hybridization of carbon are correct
Question 6
1 / -0

Which of the following has highest bond strength?

A
$$
2 p \pi-2 p \pi
$$

B
$$
2 p \pi-3 p \pi
$$

C
$$
3 d \pi-3 d \pi
$$

D
$$
1 s-2 p
$$
Question 7
1 / -0

$$H - \underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}} - \underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}} - \underset{\!\!OH}{\underset{|}{\overset{H}{\overset{|}{C}}} - }H$$ $$H - \underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}} - \underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}} - OH$$ $$H - \underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}} - \underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}} - H$$ $$\underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}} = \underset{H}{\underset{|}{\overset{H}{\overset{|}{C}}}}$$

$$(1)$$ $$(2)$$ $$(3)$$ $$(4)$$

The structures of four molecules are shown.

Which molecules belong to the same homologous series?

A
$$1$$ and $$2$$

B
$$1$$ and $$3$$

C
$$2$$ and $$4$$

D
$$3$$ and $$4$$

Solution

Molecules $$1$$ and $$2$$ contain the same functional group, i.e., alcohol, and their formula differs by $$CH_2$$ group. Thus belongs to the same homologous series while compound $$3$$ and $$4$$ belongs to alkane and alkene respectively.
A homologous series is a group or class of compounds having the same general formula and similar chemical properties in which successive members differ by $$-CH_2$$ group.
Hence, option A is correct.
Question 8
1 / -0

Ammonia and chlorine react together in the gas phase.
$$8NH_3+3Cl_2\rightarrow N_2+6NH_4Cl$$
Which statements are correct?
$$1$$. Ammonia behaves as a reducing agent.
$$2$$. Ammonia behaves as a base.
$$3$$. The oxidation number of hydrogen changes.

A
$$1, 2$$ and $$3$$ are correct

B
$$1$$ and $$2$$ only are correct

C
$$2$$ and $$3$$ only are correct

D
$$1$$ only is correct

Solution

$$\text{Ammonia behaves as a reducing agent as it donates its lone pair electron.}$$
$$\text{Ammonia reacting as Brownsted acid.}$$
$$\text{Oxitation number of hydrogen is not changes.}$$
Question 9
1 / -0

Product

A

B

C

D

Solution
Question 10
1 / -0

In which of the following func-tional group isomerism is not possible?

1) Alcohols
2) Aldehydes
3) Alkyl halides
4) Cyanides

A
$$1, 2, 3$$ and $$4$$ are correct

B
$$1$$ and $$2$$ only are correct

C
$$2$$ and $$3$$ only are correct

D
$$3$$ only is correct

Solution

$$\text{Alkyl halides does not have any functional group.}$$