Hydrocarbons Test

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Hydrocarbons Test - 1

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Weekly Quiz Competition

Question 1
1 / -0

The boiling point of isomeric branched chain alkene is

A
lower than the boiling point of straight chain alkene

B
same boiling point as straight chain alkenes except optical isomers

C
higher boiling point than straight chain alkenes

D
same boiling point as straight chain alkenes

Solution

Explanation:

As surface area decreases with branching,the boiling point also decreases.
Question 2
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Stereoisomeric alkenes due to different arrangement of atoms or groups in space are referred to as

A
geometric isomers

B
position isomers

C
chain isomers

D
constitutional isomers

Solution

Explanation:

Isomers which have the same structural formulae but difffer in the relative spatial arrangements of atoms or groups around the double bond are called geometric isomers.athus geometrical isomers are atype of stereoisomers.
Question 3
1 / -0

In the alkene having IUPAC name 3-Methyl-1-butene the double bond lies on carbon atom numbered

A
3

B
1

C
2

D
4

Solution

Explanation:

1 is written before butene which indicates that the position of the double bond is on carbon 1.The structure of the compound is: CH₂=CHCH(CH₃)CH₃
Question 4
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Carbon-carbon double bond in alkenes consists of

A
one weak sigma (σ) bond due to head-on overlapping of sp_² hybridised orbitals one weak pi (π) bond

B
one weak sigma (σ) bond due to head-on overlapping of sp³ hybridised orbitals one weak pi (π)bond

C
one strong sigma (σ) bond due to head-on overlapping of sp2 hybridised orbitals one weak pi (π) bond

D
one strong sigma (σ)bond due to head-on overlapping of sp3 hybridised orbitals one weak pi (π)bond

Solution

Explanation:

sigma bond is formed by head-on overlap of sp2 hybridised orbitals while the pi bond is formed by lateral or sideways overlapping of the two 2p-orbitals of the two carbon atoms. Alkenes contain 1 weak pi bond and 1 strong sigma bond.
Question 5
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Halogenation of alkanes is a

A
Rearrangement reaction

B
Substitution reaction

C
Elimination reaction

D
Addition reaction

Solution

Explanation:

Halogenation of alkanes is a substitution reaction because the hydrogen atoms are replaced by halogens in the presence of sunlight to give the corresponding alkyl halides.The reaction follows free radical mechanism.
Question 6
1 / -0

boiling point of alkanes

A
decreases with increase in molecular mass

B
is independent of branching

C
increases with increase in molecular mass

D
is independent of molecular mass

Solution

Explanation:

As molecular mass increases,the magnitude of van der Waals forces of attraction increases and hence boiling point increases accordingly.
Question 7
1 / -0

The number of possible conformational isomers of ethane is

A
two

B
infinite

C
zero

D
one

Solution

Explanation:

conformational isomers are obtained by rotation about a carbon-carbon single bond.This results in infinite number of momentary arrangements of atoms in space.Hence for ethane infinite number of conformations are possible.
Question 8
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Which of these is not a characteristic of aromatic Hydrocarbons?

A
they may contain double bonds

B
they are special type of cyclic compounds

C
carbon atoms form a an open chain

D
carbon atoms form a closed chain or ring

Solution

Explanation:

aromatic hydrocarbon are not open chained. They are ring structures.they contain one or more benzene rings either fused or isolated in their molecules.
Question 9
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Which of these fuels given below is not a hydrocarbon?

A
Hydrogen

B
CNG

C
LPG

D
LNG

Solution

Explanation:

Because hydrocarbons contain both C and H and hence Hydrogen is not a hydrocarbon.

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Re-Attempt Weekly Quiz Competition

Hydrocarbons Test - 1

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Hydrocarbons Test - 1

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Question 1

lower than the boiling point of straight chain alkene

same boiling point as straight chain alkenes except optical isomers

higher boiling point than straight chain alkenes

same boiling point as straight chain alkenes

Solution

Question 2

geometric isomers

position isomers

chain isomers

constitutional isomers

Solution

Question 3

3

1

2

4

Solution

Question 4

one weak sigma (σ) bond due to head-on overlapping of sp2 hybridised orbitals one weak pi (π) bond

one weak sigma (σ) bond due to head-on overlapping of sp3 hybridised orbitals one weak pi (π)bond

one strong sigma (σ) bond due to head-on overlapping of sp2 hybridised orbitals one weak pi (π) bond

one strong sigma (σ)bond due to head-on overlapping of sp3 hybridised orbitals one weak pi (π)bond

Solution

Question 5

Rearrangement reaction

Substitution reaction

Elimination reaction

Addition reaction

Solution

Question 6

decreases with increase in molecular mass

is independent of branching

increases with increase in molecular mass

is independent of molecular mass

Solution

Question 7

two

infinite

zero

one

Solution

Question 8

they may contain double bonds

they are special type of cyclic compounds

carbon atoms form a an open chain

carbon atoms form a closed chain or ring

Solution

Question 9

Hydrogen

CNG

LPG

LNG

Solution

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one weak sigma (σ) bond due to head-on overlapping of sp_² hybridised orbitals one weak pi (π) bond

one weak sigma (σ) bond due to head-on overlapping of sp³ hybridised orbitals one weak pi (π)bond