Hydrocarbons Test

Result

Hydrocarbons Test - 26

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Weekly Quiz Competition

Question 1
1 / -0

$$CH_3 - \underset{CH_3}{\underset{|}{C}H} MgCl + CH_3 - \!\!\!\!\overset{CH_3}{\overset{|}{\underset{\,\,\,\,CH_3}{\underset{|}{C} }}\!\!\!-} \,OH \rightarrow$$ '$$Q$$'
What is 'Q'?

A
Isobutane

B
Isopropane

C
Tert. butyl chloride

D
Propane

Solution

In the given reaction, the reaction between Grignard's reagent and tert-butyl alcohol takes place.
Here, breaking of $$R$$ and $$MgX$$ bond takes place to give caranion ion. This ion has a high affinity of a proton. The $$MgX$$ part substitues $$H$$ from $$-OH$$ to remove $$H^+$$ ion.
This $$H^+$$ ions gets attached to the carbanion ion to form Isopropane as a product.
Question 2
1 / -0

The major product of the reaction of 2-butene with alkaline $$KMnO_4$$ solution is

A

B

C

D

Solution

Alkenes give diol with alkaline $$KMnO_4$$.
Option D is correct.
Question 3
1 / -0

The major product of acid-catalysed dehydration of Pentan $$-3-ol$$ is:

A
$$Pent-1-ene$$

B
$$2-Methyl-1-butene$$

C
$$Pent-2-ene$$

D
$$3-Methyl-1-butene$$

Solution
Question 4
1 / -0

Arrange the given alkenes in decreasing order of their reactivity towards bromination:

A
i> ii> iii> iv

B
iv> iii> ii> i

C
i> ii> iv> iii

D
iii> iv> ii> i

Solution

reactivity towards Bromination depends on e$$^-$$ rich alkene since Br$$^+$$ is electrophile.
The alkene which have more methyl group attached to the doubly bonded carbon atom will be more electron rich.
Thus the order of the reactivity towards bromination reaction can be given as follow:

$$ i> ii> iii> iv$$

Option A is correct.
Question 5
1 / -0

Which of the following is true about the given reaction?

A
The above reaction is of iodination

B
$$HNO_{3}$$ acts as reducing agent in the reaction

C
Iodine cation is electrophile of the reaction

D
The reaction involves electrophilic aromatic substitution

Solution

In the fiven reaction, addition of the iodine takes place on benzene ring. Thus the given reaction is a iodination reaction.
Question 6
1 / -0

s-Butyl bromide is allowed to react with sodium in dry ether, The major product formed is :

A

B

C

D

Solution
Question 7
1 / -0

Ethyl benzene react with $$BH_{2}/ FeBr_{3}$$ to give:

A

B

C

D

Solution
Question 8
1 / -0

s-Butyl bromide is allowed to react with sodium in dry ether.The major product formed is :

A

B

C

D

Solution
Question 9
1 / -0

$$2, 3-Dibromobutane$$ can be converted to $$2-butyne$$ in a two-step reaction using:

A
(i) $$HCl$$ and (ii) $$NaH$$

B
(i) alcoholic $$KOH$$ and (ii) $$NaNH_{2}$$

C
(i) $$Na$$ and (ii) $$NaOH$$

D
(i) $$Br_{2}$$ and (ii) $$NaH$$

Solution
Question 10
1 / -0

$$CH\ \equiv \ CH\ \xrightarrow [ Ni{ \left( CN \right) }_{ 2 } ]{ Pressure } X$$. Here $$X$$ in the reaction.

A
Benzene

B
Ethane

C
Cycloctatetraene

D
Cyclohexane

Solution

3 moles of acetylene when catalysed with $$Ni(CN)_2$$ gives benzene.