Hydrocarbons Test

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Hydrocarbons Test - 3

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Weekly Quiz Competition

Question 1
1 / -0

Carbon-carbon double bond in alkenes consists of

A
one weak sigma (σ) bond due to head-on overlapping of sp³ hybridised orbitals one weak pi (π)bond

B
one strong sigma (σ)bond due to head-on overlapping of sp³ hybridised orbitals one weak pi (π)bond

C
one weak sigma (σ) bond due to head-on overlapping of sp² hybridised orbitals one weak pi (π) bond

D
one strong sigma (σ) bond due to head-on overlapping of sp² hybridised orbitals one weak pi (π) bond

Solution

sigma bond is formed by head-on overlap of sp2 hybridised orbitals while the pi bond is formed by lateral or sideways overlapping of the two 2p-orbitals of the two carbon atoms. Alkenes contain 1 weak pi bond and 1 strong sigma bond.
Question 2
1 / -0

In the alkene having IUPAC name 3-Methyl-1-butene the double bond lies on carbon atom numbered

A
1

B
2

C
3

D
4

Solution

‘1’ is written before butene which indicates that the position of the double bond is on carbon 1.The structure of the compound is: CH₂=CHCH(CH₃)CH₃
Question 3
1 / -0

Stereoisomeric alkenes due to different arrangement of atoms or groups in space are referred to as

A
position isomers

B
geometric isomers

C
constitutional isomers

D
chain isomers

Solution

Isomers which have the same structural formulae but difffer in the relative spatial arrangements of atoms or groups around the double bond are called geometric isomers.athus geometrical isomers are atype of stereoisomers.
Question 4
1 / -0

The boiling point of isomeric branched chain alkene is

A
same boiling point as straight chain alkenes

B
lower than the boiling point of straight chain alkene

C
same boiling point as straight chain alkenes except optical isomers

D
higher boiling point than straight chain alkenes

Solution

As surface area decreases with branching,the boiling point also decreases.
Question 5
1 / -0

The number of position isomers of C₅H₈ is

A
2

B
3

C
4

D
5

Solution

n-pentyne , 3-methyl butyne, pent-2-yne
Question 6
1 / -0

Thus ethyne molecule consists of

A
one C−−C σ bond, two C−−H σ bonds and three C−−C π bonds

B
three C−−C σ bond, two C−−H σ bonds and three C−−C π bonds

C
one C−−C σ bond, two C−−H σ bonds and two C−−C π bonds

D
one C−−C σ bond, three C−−H σ bonds and two C−−C π bonds

Solution

Ethyne is an unsaturated compound which belongs to the alkyne family and has the formula C₂H₂.Thus it consists of one C–C σ bond, two C–H σ bonds and two C–C π bonds.
Question 7
1 / -0

Majority of the reactions of alkynes are the examples of

A
nucleophilic substitution

B
electrophilic substitution

C
electrophilic addition

D
nucleophilic addition

Solution

Alkynes have two pi bonds,hence they are electron rich species.They attract electrophiles thereby undergoing electrophilic addition reactions.

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Hydrocarbons Test - 3

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Hydrocarbons Test - 3

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Question 1

one weak sigma (σ) bond due to head-on overlapping of sp3 hybridised orbitals one weak pi (π)bond

one strong sigma (σ)bond due to head-on overlapping of sp3 hybridised orbitals one weak pi (π)bond

one weak sigma (σ) bond due to head-on overlapping of sp2 hybridised orbitals one weak pi (π) bond

one strong sigma (σ) bond due to head-on overlapping of sp2 hybridised orbitals one weak pi (π) bond

Solution

Question 2

1

2

3

4

Solution

Question 3

position isomers

geometric isomers

constitutional isomers

chain isomers

Solution

Question 4

same boiling point as straight chain alkenes

lower than the boiling point of straight chain alkene

same boiling point as straight chain alkenes except optical isomers

higher boiling point than straight chain alkenes

Solution

Question 5

2

3

4

5

Solution

Question 6

one C−−C σ bond, two C−−H σ bonds and three C−−C π bonds

three C−−C σ bond, two C−−H σ bonds and three C−−C π bonds

one C−−C σ bond, two C−−H σ bonds and two C−−C π bonds

one C−−C σ bond, three C−−H σ bonds and two C−−C π bonds

Solution

Question 7

nucleophilic substitution

electrophilic substitution

electrophilic addition

nucleophilic addition

Solution

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one weak sigma (σ) bond due to head-on overlapping of sp³ hybridised orbitals one weak pi (π)bond

one strong sigma (σ)bond due to head-on overlapping of sp³ hybridised orbitals one weak pi (π)bond

one weak sigma (σ) bond due to head-on overlapping of sp² hybridised orbitals one weak pi (π) bond

one strong sigma (σ) bond due to head-on overlapping of sp² hybridised orbitals one weak pi (π) bond