Hydrocarbons Test

Result

Hydrocarbons Test - 33

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Weekly Quiz Competition

Question 1
1 / -0

The correct order of relative rates of catalytic hydrogenation is:

A
$$CH_2 = CH_2 > RCH = CH_2 > RCH = CHR > R_2C = CHR $$

B
$$R_2C = CHR > RCH = CHR > RCH = CH_2 > CH_2 = CH_2 $$

C
$$RCH = CHR > R_2C = CHR > RCH = CH_2 > CH_2 = CH_2 $$

D
$$R_2C = CHR > CH_2 = CH_2 > RCH = CHR > RCH = CH_2 $$

Solution

Hydrogenation of less unsubstituted alkenes is very easy when compared to substituted alkenes.
So, the correct order of relative rates of catalytic hydrogen is
$$CH_2=CH_2 > RCH=CH_2 >RCH=CHR >R_2C=CHR$$
Question 2
1 / -0

Reaction involving $$'syn'$$ addition is:

A
$$CH_2=CH_2\xrightarrow{H^+/H_2O}$$

B
$$CH_3CH = CH_2 \xrightarrow{HX}$$

C
$$CH_3CH = CH_2 \xrightarrow[NaBH_4]{Hg(OAc)_2/H_2O}$$

D
$$CH_2=CH_2\xrightarrow[H_2O_2/OH]{B_2H_3/THF}$$

Solution
Question 3
1 / -0

A

B

C

D

Solution
Question 4
1 / -0

In the following reaction, the organic product X has the structure?

A

B

C

D

Solution
Question 5
1 / -0

Product in the reaction is

A

B
$$2CH_{ 3 }{ CH }{ O }$$

C
$$2{ CH }_{ 3 }{ COOH }$$

D
$${ CH }_{ 3 }{ CHO }$$ + $${ CH }_{ 3 }{ COO }H$$

Solution

In the given question, acidified Potassium permanganate is been added to But-2-ene.

As we know that,acidified Potassium permanganate is a strong oxidizing agent. Hence, it will oxidize the But-2-ene into $$2C{H_3} - CHO$$.
Hence,(b) is the correct answer.
Question 6
1 / -0

In the reaction shown, product $$A$$ is:

A

B

C

D

Solution
Question 7
1 / -0

What would be the final product of the given sequence of reactions?

A

B

C

D

Solution

So, the correct option is $$A$$
Question 8
1 / -0

Identify product.

A
$$C_2H_2+2CO_2$$

B
$$2KOH+H_2$$

C
$$2KOH+2CO_2$$

D
$$C_2H_2+H_2$$
Question 9
1 / -0

The treatment of $${ { (CH }_{ 3 }) }_{ 2 } C={ CHCH }_{ 3 }$$ with boiling $${ KMnO }_{ 4 }$$ produces :

A
$${ CH }_{ 3 }{ COCH }_{ 3 }+{ CH }_{ 3 }{ COCH }_{ 3 }$$

B
$${ CH }_{ 3 }{ COCH }_{ 3 }+{ CH }_{ 3 }CHO$$

C
$${ CH }_{ 3 }CHO+{ CO }_{ 2 }$$

D
$${ CH }_{ 3 }{ COCH }_{ 3 }\quad$$ only

Solution

$$KMnO_4$$ act a strong oxidising agent oxidises the double bond to give acetone and acetaldehyde as a product.
Question 10
1 / -0

$$H_3C-C\equiv C-CH_3$$ maximum number of linear atoms in given compound is:

A
4

B
6

C
10

D
8

Solution

Since one carbon$$.$$ Carbon triple bond is present
The No$$.$$ of linear atom$$=6$$
Hence$$,$$ option $$(B)$$ is correct$$.$$