Hydrocarbons Test

Result

Hydrocarbons Test - 37

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Weekly Quiz Competition

Question 1
1 / -0

$${ CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 3 }\xrightarrow [ ]{ 400-{ 600 }^{ o }C } X+Y$$ $$X$$ and $$Y$$ are

A
ethylene, ethane

B
Hydrogen, ethylene

C
methane, ethylene

D
Hydrogen, methane

Solution
Question 2
1 / -0

Which of the following does not give alkane with $$R-Mg-X.$$

A
$$Ph-OH$$

B
$$C_6H_6$$

C
$$CH_3COOH$$

D
$$HCl$$

Solution
Question 3
1 / -0

$$CH_3CH=CH-CH_2-CO_2H\xrightarrow[\Delta]{}(X) $$ (major); Product (X) is :

A
$$CH_3CH=CH-CH_3$$

B
$$CH_3-\underset{\,\,\,\,CH_3}{\underset{|}{C}}=CH_2$$

C
$$CH_3-CH_2-CH=CH_2$$

D
$$CH_3-CH=CH_2$$

Solution
Question 4
1 / -0

$$CH_{3}-CH=CH_{2}+HOBr\longrightarrow P$$; The major product $$'P'$$ is

A

B

C

D

Solution
Question 5
1 / -0

An alkyl halide produces a single alkene when it reacts with sodium ethoxide and ethanol. This alkene undergoes hydrogenation and produces $$2-$$methyl butane. What is the identity of the alkyl bromide?

A
$$1-$$bromo$$-2, 2-$$dimethyl propane

B
$$1-$$bromo butane

C
$$1-$$bromo$$-2-$$methyl butane

D
$$2-$$bromo$$-2-$$methyl butane

Solution

$$Cl-CH_2-CH-CH_2CH_3 \xrightarrow [EtOH]{NaOEt} CH_2=C-CH_2CH_3\xrightarrow [H_2]{catalyst}CH_3=C-CH_2-CH_3$$
| | |
$$CH_3$$ $$CH_3$$. $$CH_3$$

Hence C is correct answer
Question 6
1 / -0

$$n$$ propyl alcohol on reacting with anhydrous alumina at $$623\,K$$ forms

A
Ethane

B
Propene

C
propyne

D
Propane

Solution
Question 7
1 / -0

When acetylene is possed through dil, $$H_2SO_4$$ in the presence of $$HgSO_4$$, the compound formed is

A
ether

B
ketone

C
acetic acid

D
acetaldehyde

Solution
Question 8
1 / -0

Which of the following is correct?

A
Cyclohexane < n- hexane: melting point

B
Cyclohexane < n-hexane: boiling point

C
Cyclohexane < n-hexane: density

D
None pof these

Solution
Question 9
1 / -0

Product $$A$$ is:

A
$$Ph-CH={CH}_{2}$$

B
$$Ph-C\equiv CH$$

C
$$Ph-{CH}_{2}-{CH}_{3}$$

D
$$Ph-C\equiv C\circleddash Na\oplus $$

Solution
Question 10
1 / -0

Addition of bromine to $$1, 3-butadiene$$ gives:

A
$$1, 2$$ addition product

B
$$1, 4$$ addition product

C
Both $$1, 2$$ and $$1, 4$$ addition products

D
No reaction

Solution

1,3-butadiene accompanies the bromine molecule to form two products.

They are 1,2-add products and 1,4-surplus products.

At low temperatures, the 1,2-pair is predominant but at higher temperatures, the 1,4-pair is predominant.Products A and B will be on this basis.