Hydrocarbons Test

Result

Hydrocarbons Test - 42

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Weekly Quiz Competition

Question 1
1 / -0

The IUPAC name of the given compound will be:

A
5-ethyl-1-methyl-2-propylcyclohexane

B
1-ethyl-3-methyl-4-propylcyclohexane

C
4-Ethyl-2-methyl-1-propylcyclohexane

D
1-propyl-3-ethyl-2-methylcyclohexane

Solution
Question 2
1 / -0

Which name is correct?

A

B

C

D

Solution

The IUPAC name of the shown is bicyclo (2.2.2) hexane.

Hence, option D is correct.
Question 3
1 / -0

Select the correct IUPAC name of the given compound:

A
1,1-cyclobutyl heptane

B
Bicyclo [6.3.0] nonane

C
Spiro [3.6] decane

D
Spiro [6.3] decane

Solution
Question 4
1 / -0

Which of the following is the correct IUPAC name of the given compound?

A
3-cyclobutyl-1-methylcyclohexane

B
1-methyl-3-cyclobutylcyclohexane

C
1-cyclobutyl-5-methylcyclohexane

D
1-cyclobutyl-3-methylcyclohexane

Solution
Question 5
1 / -0

When a mixture of acetylene and nitrogen is subjected to electric discharge, the product obtained is

A
Ether

B
Ethyl amine

C
$$HCN$$

D
Ammonia

Solution

Unsaturated hydrocarbons can participate in a number of different addition reactions across their double or triple bonds.
$$2CH_4 + 2 NH_3 + 3 O_2 $$ $$\rightarrow$$ $$2 HCN + 6 H_2O$$
Question 6
1 / -0

Ethylene reacts with sulphur monochloride to form:

A
Ethyl chloride

B
Ethylene chloride

C
Mustard gas

D
Ethylidene chloride

Solution

Mustard gas is synthesized by treating sulfur monochloride with ethylene:
In the Levinstein process, disulfur dichloride is used:

$$8S_2Cl_2$$ + $$16C_2H_4$$ $$\rightarrow$$ $$8(ClCH_2CH_2)_2S$$ + S.
Question 7
1 / -0

Aqueous solution of an organic compound $$'A'$$ on electrolysis liberates acetylene and $$CO_{2}$$ at anode. $$'A'$$ is

A
Potassium citrate

B
Potassium acetate

C
Potassium succinate

D
Potassium maleate

Solution
Question 8
1 / -0

To prepare $$2-butyne$$ from $$2, 2, 3, 3-tetrachlorobutane$$, use is made of:

A
Zinc

B
Sodamide

C
$$Alc. KOH$$

D
$$aq. KOH$$

Solution
Question 9
1 / -0

Acetylene is prepared industrially by passing electric discharge through graphite electrodes in the atmosphere of

A
Air

B
$$H_{2}$$

C
$$N_{2}$$

D
$$CO_{2}$$
Solution
Acetylene is prepared industrially by passing electric discharge through graphite electrodes in the atmosphere of $$H_2$$.
$$2C{{H}_{2}}\xrightarrow{Electric\,arc}CH\equiv CH$$
Question 10
1 / -0

$$H_{2}C = CH_{2} + HOCl \rightarrow$$ ____ $$+$$ ____ $$\rightarrow$$ ethylene chlorohydrin. Fill in the blanks in the above reaction with

A
$$CH_{2}OH - \overset {-}{C}H_{2} + \overset {+}{C}l$$

B
$$CH_{2}Cl - \overset {-}{C}H_{2} + \overset {+}{O}H$$

C
$$CH_{2}OH - \overset {+}{C}H_{2} + \overset {-}{C}l$$

D
$$CH_{2}Cl - \overset {+}{C}H_{2} + \overset {-}{O}H$$

Solution

$$H_2C=CH_2+HOCl \rightarrow CH_2Cl- CH_2^- + OH^-$$
hence D is correct