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Hydrocarbons Test - 43

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Hydrocarbons Test - 43
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which one will form thiophene when heated with sulphur or $$H_{2}S$$?
    Solution
    ethene  C2H2 is product
  • Question 2
    1 / -0
    Which of the following alkenes will give an optically active alcohol when treated with $$H_{2}/H_{2}SO_{4}$$?
    Solution
    only 1 butene is akenes will give an optically active alcohol when treated with H2/H2SO4?
  • Question 3
    1 / -0
    The reactivity of hydrogen atoms attached to the carbon atom in an alkane has the order: 
    Solution
    Order of reactivity of hydrogen atoms is tertiary > secondary > primary.
    Hence, Option "C" is the correct answer.
  • Question 4
    1 / -0
    Reaction of alkanes with halogen is explosive in case of:
    Solution
    Reaction of alkanes with halogen is explosive in case of $$F_{2}$$.
    Hence, Option "B" is the correct answer.
  • Question 5
    1 / -0
    The most important method to prepare lower hydrocarbon is 
    Solution
    The most important method to prepare lower hydrocarbon is cracking.

    For eg. : $$\mathrm{C_6H_{14} \xrightarrow{\Delta} \underset{Ethene}{C_2H_4} + \underset{Butane}{C_4H_{10}}}$$

    Hence, Option "A" is the correct answer.
  • Question 6
    1 / -0
    Ethane can be prepared by
    Solution
    Reactions:
    A) $$\mathrm{CH_3-COONa \xrightarrow[Sodalime]{\Delta} \underset{Methane}{CH_4} + CO_2}$$

    B) Sodium succinate on electrolysis produce ethyne.

    C) Sodium acetate on electrolysis produce ethane.

    Hence, Option "C" is the correct answer.
  • Question 7
    1 / -0
    Action of heat on a mixture of sodium propanoate and sodalime produces
    Solution
    Action of heat on a mixture of sodium propanoate and sodalime:
    $$\mathrm{CH_3CH_2COONa \xrightarrow[Sodalime]{\Delta} CH_3-CH_3 +CO_2}$$

    So, the product obtained is ethane.
    Hence, Option "B" is the correct answer.
  • Question 8
    1 / -0
    The IUPAC name of neo-pentane is:
    Solution
    Neo-pentane is $$\mathrm{CH_3-C(CH_3)(CH_3)-CH_3}$$.
    So, IUPAC Nme of Neo-pentane is 2,2-dimethylpropane.

    Hence, Option "D" is the correct answer.
  • Question 9
    1 / -0
    Finely divided platinum and palladium commonly known as platinum and palladium black, may be prepared by reducing their,soluble salts with:
    Solution

  • Question 10
    1 / -0
    Butane can be converted into 2-methylpropane, if heated with:
    Solution
    Isomerisation of an alkane takes place when reacted with $$\mathrm{AlCl_3}$$.

    So, for converting butane into 2-methylpropane, butane may be reacted with $$\mathrm{AlCl_3}$$.

    Hence, Option "A" is the correct answer.
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