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Hydrocarbons Test - 50

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Hydrocarbons Test - 50
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Weekly Quiz Competition
  • Question 1
    1 / -0
    In the reaction C2H5CH=CH2+HXProductC_{2}H_{5}CH=CH_{2}+H-X\rightarrow Product What is the product
    Solution
    C2H5CH=CH2+HXC_{2}H_{5}CH=CH_{2}+H-X\rightarrowC2H5CHXCH3C_{2}H_{5}-CHX-CH_{3}
    When halide react with 1 butene then tere will be a two product is possible. 
    1.C2H5CHXCH3C_{2}H_{5}-CHX-CH_{3}
    2.C2H5CH2CHX3C_{2}H_{5}-CH_2-CHX3
    But 90%of the product is C2H5CHXCH3C_{2}H_{5}-CHX-CH_{3}
    And 10% is C2H5CH2CHX3C_{2}H_{5}-CH_2-CHX3.
    Therefore our answer is Option C. 
  • Question 2
    1 / -0
    Oils are converted into fats by
    Solution
    Oil are unsaturated esters which are converted into fats by saturating it by catalytic hydrogenation.\text{Oil are unsaturated esters which are converted into fats by saturating it by catalytic hydrogenation.}
  • Question 3
    1 / -0
    Which of the following occurs easily in ethylene?
    Solution
    In case of ethene double bond is present. Hence, addition reactions occur easily.

    Example: CH2=CH2+HClCH3CH2ClCH_2=CH_2+HCl\to CH_3-CH_2Cl
  • Question 4
    1 / -0
    The order of increasing reactivity towards HClHCl of the following compounds will be
    (1) CH2=CH2CH_{2}=CH_{2}
    (2) (CH3)2C=CH2(CH_{3})_{2}C=CH_{2}
    (3)CH3CH=CHCH3CH_{3}CH=CHCH_{3}
    Solution
    The correct order of increasing reactivity towards HCl is
    CH3CH=CHCH3 CH_3CH = CHCH_3 <(CH3)2C=CH2 <(CH_3) _2C = CH_2 <CH2=CH2 <CH_2 = CH_2 .
     As the number of alkyl groups attached to the carbon atoms increases, the + I effect of the alkyl groups increases and the alkene becomes electron rich. Hence, the reactivity towards HCl increases as pi electrons of the double bond are donated to proton.
    Also as the stability of alkene decreases (cis isomer is less stable than trans isomer), the reactivity towards acid catalyzed hydration increases.
    Therefore, Option C is correct answer for this.
  • Question 5
    1 / -0
    Which of the following are formed on addition reaction of DCIDCI with 3-methyl-1-butene
    Solution
    Option  A is a correct answer  for this question. 

  • Question 6
    1 / -0
    Which one of the following organic compounds decolourises an alkaline KMnO4KMnO_{4} solution?
    Solution
    C3H6C_{3}H_{6} is an alkene therefore decolourises alkaline KMnO4KMnO_{4} solution.
  • Question 7
    1 / -0
    Protein can be most easily removed from
    Solution
    because of insolubility of protein in benzene, protein can be easily removed from benzene.
  • Question 8
    1 / -0
    Which kind of isomerism will butene2-2 show?
    Solution
    2-Butene\text{2-Butene} shows geometrical isomerism.

  • Question 9
    1 / -0
    Elimination reaction of 2-bromo-pentane to form pent-2-ene is:
    a) β\beta- Elimination reaction
    b) Follows Zaitsev rule
    c) Dehydrohalogenation reaction
    d) Dehydration reaction
    Solution
    Refer above image,
    This reaction is an example of β\beta- elimination.
    Hydrogen is removed from β\beta- carbon and halogen from α\alpha- carbon, dehydrohalogenation reaction
    Generally in E2 reaction Zaitsev alkene is formed as major product (more stable alkene)

  • Question 10
    1 / -0
    The correct IUPAC name of the following alkane is 

    Solution
    The given alkane has the longest chain of 88 carbon atoms hence , it is Octane . 
    Side chain on carbon 2,32,3and 66 follow lowest sum rule.
    On carbon 22-methyl , on carbon 33-and carbon-66-ethyl groups are present. Ethyl comes before methyl (alphabetically) and two ethyl groups are there.
    Hence the correct IUPAC name is 3,63,6-Diethyl-22-methyloctane.

    Hence, Option "A" is the correct answer. 
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