Chemical Bonding and Molecular Structure Test 23

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Chemical Bonding and Molecular Structure Test 23

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Weekly Quiz Competition

Question 1
1 / -0

The Hybridisation and magnetic behavior of complex $$[Ni(CO)_{4}]$$ is

A
$$dsp^{2}$$, paramagnetic

B
$$dsp^{2}$$, diamagnetic

C
$$sp^{3}$$, paramagnetic

D
$$sp^{3}$$, diamagnetic
Question 2
1 / -0

The major binding force in graphite is

A
ionic bond

B
covalent bond

C
hydrogen bond

D
London force

Solution

Graphite is an allotrope of carbon in which ll the carbon atoms are sp2 hybridize in nature.
Thus the main binding force in graphite is covalent bonding as hybridization takes place when there is covalent bonding.
Question 3
1 / -0

Which of the following is the correct order of radius?

A
$$H^{-} > H > H^{+}$$

B
$$Na^{+} > F^{-} > O^{2-}$$

C
$$F^{-} > O^{2-} > Na^{+}$$

D
$$Al^{3+} > Mg^{2+} > N^{3-}$$

Solution

H has one electron and one proton. If one more electron is added to the shell, the effective nuclear charge per electron decreases and hence electron cloud tends to move away from the attractive positive charge and hence, the radius increases as compared to the parent atomic radius.

On the other side, when the only electron of H is removed, a single proton is left in the atom solely having a positive charge. There is no electron cloud as in to move away. So it tends to contract and therefore it's radius decreases as compared to the parent atomic radius.

Hence, the correct order is $$H^- > H > H^+$$.

Therefore, option A is correct.
Question 4
1 / -0

Solid $$CO_{2}$$ form:

A
Ionic bond

B
Van der Waal's bond

C
Chemical bond

D
Covalent bond

Solution

The correct option is D.

A covalent bond is a chemical bond, involving the exchange of pairs of electrons between atoms. In case of $$CO_2$$, two oxygen and one carbon atoms share their outermost electrons between them which forms a strong covalent bond. Therefore, solid $$CO_2$$ form covalent bond by sharing of electrons among them.
Option A is incorrect because ionic requires transfer of electrons.
Options B is incorrect because the van der Waals force is caused by temporary attractions between electron rich region of one molecules and electron poor regions of another.
Option C is incorrect because chemical bonding may form between two oppositely charge atom.
Question 5
1 / -0

Consider the following species:
(i) $$[O_2]^{2-}$$
(ii) $$[CO]^+$$
(iii) $$[O_2]^+$$
Among these sigma bond alone is present in?

A
(i) alone

B
(ii) alone

C
(iii) alone

D
(i) and (ii)

E
(i), (ii) and (iii)

Solution

Only $$[O_2]^{2−}$$ contains one σ bond between two bonded atoms.

$$O_2^{2-} =\ \ ^-O-O^-$$

∴ (i) alone is the correct option.
Question 6
1 / -0

In the hydrocarbon, $$H_3\underset{6}{C}-\underset{5}{C}H=\underset{4}{C}H-\underset{3}{C}H_2-\underset{2}{C}\equiv \underset{1}{C}H$$

The state of hybridization of carbons $$1, 3, 5$$ are in the following sequence is:

A
$$sp, sp^2, sp^3$$

B
$$sp^3, sp^2, sp$$

C
$$sp^2, sp, sp^3$$

D
$$sp, sp^3, sp^2$$

Solution

$$H_3\underset{6}{\overset{sp^3}C}-\underset{5}{\overset{sp^2}C}H=\underset{4}{\overset{sp^2}C}H-\underset{3}{\overset{sp^3}C}H_2-\underset{2}{\overset{sp}C}\equiv \underset{1}{\overset{sp}C}H$$
The state of hybridisation of carbon in $$1, 3$$ and $$5$$ position are $$sp, sp^3, sp^2$$
Question 7
1 / -0

Which of the following hydrocarbons ahs lowest dipole moment?

A

B
$$CH_3 - C\equiv C - CH_3$$

C
$$CH_3 - CH_2 - C \equiv C - H$$

D
$$CH_2 = CH - C \equiv CH$$

Solution

$$CH_3−C≡C−CH_3$$ will have zero dipole moment because being $$\text{symmetrical with a linear structure.}$$ resultant dipole moment will be zero.
Question 8
1 / -0

_______ bond is the most polar.

A
$$C-O$$

B
$$C-Br$$

C
$$C-S$$

D
$$C-F$$

Solution

$$C-F$$ bond is more polar since fluorine $$(F)$$ is more electronegative than other elements given.

The order of electronegativity is $$F>O>Br>S$$.

Hence the correct answer is option D.
Question 9
1 / -0

The enolic form of butanone contains?

A
$$12\sigma$$ bonds, $$1\pi$$ bond and $$2$$ lone pairs of electrons

B
$$11\sigma$$ bonds, $$1\pi$$ bond and $$2$$ lone pairs of electrons

C
$$12\sigma$$ bonds, $$1\pi$$ bond and $$1$$ lone pair of electrons

D
$$10\sigma$$ bonds, $$2\pi$$ bonds and $$2$$ lone pairs of electrons

E
$$13\sigma$$ bonds, $$1\pi$$ bonds and $$2$$ lone pairs of electrons

Solution
Question 10
1 / -0

Allyl cyanide contains _____ $$\sigma$$ and ____ $$\pi$$-bonds.

A
$$5\sigma, 7\pi$$

B
$$9\sigma, 3\pi$$

C
$$3\sigma, 4\pi$$

D
$$9\sigma, 9\pi$$

Solution

There are 9 $$\sigma$$ and 3 $$\pi$$ bonds.

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Chemical Bonding and Molecular Structure Test 23

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Question 1

$$dsp^{2}$$, paramagnetic

$$dsp^{2}$$, diamagnetic

$$sp^{3}$$, paramagnetic

$$sp^{3}$$, diamagnetic

Question 2

ionic bond

covalent bond

hydrogen bond

London force

Solution

Question 3

$$H^{-} > H > H^{+}$$

$$Na^{+} > F^{-} > O^{2-}$$

$$F^{-} > O^{2-} > Na^{+}$$

$$Al^{3+} > Mg^{2+} > N^{3-}$$

Solution

Question 4

Ionic bond

Van der Waal's bond

Chemical bond

Covalent bond

Solution

Question 5

(i) alone

(ii) alone

(iii) alone

(i) and (ii)

(i), (ii) and (iii)

Solution

Question 6

$$sp, sp^2, sp^3$$

$$sp^3, sp^2, sp$$

$$sp^2, sp, sp^3$$

$$sp, sp^3, sp^2$$

Solution

Question 7

$$CH_3 - C\equiv C - CH_3$$

$$CH_3 - CH_2 - C \equiv C - H$$

$$CH_2 = CH - C \equiv CH$$

Solution

Question 8

$$C-O$$

$$C-Br$$

$$C-S$$

$$C-F$$

Solution

Question 9

$$12\sigma$$ bonds, $$1\pi$$ bond and $$2$$ lone pairs of electrons

$$11\sigma$$ bonds, $$1\pi$$ bond and $$2$$ lone pairs of electrons

$$12\sigma$$ bonds, $$1\pi$$ bond and $$1$$ lone pair of electrons

$$10\sigma$$ bonds, $$2\pi$$ bonds and $$2$$ lone pairs of electrons

$$13\sigma$$ bonds, $$1\pi$$ bonds and $$2$$ lone pairs of electrons

Solution

Question 10

$$5\sigma, 7\pi$$

$$9\sigma, 3\pi$$

$$3\sigma, 4\pi$$

$$9\sigma, 9\pi$$

Solution

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